en
Feedback

Don't get caught by a cheater! Telemetrio finds and tags such channels 👉 If you want to see the tag, subscribe

allcoding1

allcoding1

Open in Telegram

📈 Analytical overview of Telegram channel allcoding1

Channel allcoding1 (@allcoding1) in the English language segment is an active participant. Currently, the community unites 20 819 subscribers, ranking 9 647 in the Education category and 19 582 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 20 819 subscribers.

According to the latest data from 23 October, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -422 over the last 30 days and by -15 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 1.26%. Within the first 24 hours after publication, content typically collects 1.18% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 263 views. Within the first day, a publication typically gains 246 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 1.
  • Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, learning.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 24 October, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

20 819
Subscribers
-1524 hours
-987 days
-42230 days
Posts Archive
Send Questions Astrome & IBM.....

Goat Grazing Astrome Java Telegram:- @allcoding1
Goat Grazing Astrome Java Telegram:-  @allcoding1

from itertools import permutations def unique_permutations(nums): unique_perms = set(permutations(nums)) return [list(perm) for perm in unique_perms] # Take input for nums nums_input = input("Enter a list of numbers separated by spaces: ") nums = [int(num) for num in nums_input.split()] # Get and print unique permutations output = unique_permutations(nums) print(output)

Saks subarray product✅ long long solve(vector& nums, int k) {     if (k <= 1) return 0;     int n = nums.size();     long long p = 1;     int i = 0, j = 0;     long long ans = 0;     while (j < n) {         p *= nums[j];         while (i <= j && p > k) {             p /= nums[i];             i++;         }         ans += j - i + 1;         j++;     }     return ans; }

#include <iostream> #include <vector> #include <unordered_map> class Main { public:     static long getZeroBitSubarrays(const std::vector<int>& arr) {         int n = arr.size();         long totalSubarrayCount = static_cast<long>(n) * (n + 1) / 2;         long nonzeroSubarrayCount = 0;         std::unordered_map<int, int> windowBitCounts;         int leftIdx = 0;         for (int rightIdx = 0; rightIdx < n; rightIdx++) {             int rightElement = arr[rightIdx];             if (rightElement == 0) {                 windowBitCounts.clear();                 leftIdx = rightIdx + 1;                 continue;             }             std::vector<int> setBitIndices = getSetBitIndices(rightElement);             for (int index : setBitIndices) {                 windowBitCounts[index]++;             }             while (leftIdx < rightIdx && isBitwiseAndZero(rightIdx - leftIdx + 1, windowBitCounts)) {                 for (int index : getSetBitIndices(arr[leftIdx])) {                     windowBitCounts[index]--;                     if (windowBitCounts[index] == 0) {                         windowBitCounts.erase(index);                     }                 }                 leftIdx++;             }             nonzeroSubarrayCount += (rightIdx - leftIdx + 1);         }         return totalSubarrayCount - nonzeroSubarrayCount;     } private:     static std::vector<int> getSetBitIndices(int x) {         std::vector<int> setBits;         int pow2 = 1;         int exponent = 0;         while (pow2 <= x) {             if ((pow2 & x) != 0) {                 setBits.push_back(exponent);             }             exponent++;             pow2 *= 2;         }         return setBits;     }     static bool isBitwiseAndZero(int windowLength, const std::unordered_map<int, int>& bitCounts) {         for (const auto& entry : bitCounts) {             if (entry.second >= windowLength) {                 return false;             }         }         return true;     } }; DE Shaw ✅ C++ Telegram:- @allcoding1

🎯TCS National Qualifier Test (TCS NQT) 2024 Location: Across India Qualification: B.E / B.Tech / M.E / M.Tech / M.Sc / MCA / Any Graduate / Under Graduate / Diploma Batch: 2018/2019/2020/2021/2022/2023/2024 Apply Now:- www.allcoding1.com Telegram:- @allcoding1

package Graph; import java.util.*; public class Largest_Sum_Cycle { public static int solution(int arr[]) { &nbsp; ArrayLists
package Graph; import java.util.*; public class Largest_Sum_Cycle { public static int solution(int arr[]) {   ArrayList<Integer>sum=new ArrayList<>();     for(int i=0;i<arr.length;i++)   {       ArrayList<Integer>path=new ArrayList<>();       int j=i;       int t=0;      while(arr[j]<arr.length&&arr[j]!=i&&arr[j]!=-1&&!path.contains(j))   {    path.add(j);    t+=j;    j=arr[j];    if(arr[j]==i)    {     t+=j;     break;    }   }   if(j<arr.length&&i==arr[j])    sum.add(t);   }   if(sum.isEmpty())    return -1;     return Collections.max(sum);   } public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc=new Scanner(System.in); int testcases=sc.nextInt(); for(int loop=0;loop<testcases;loop++) { int numofBlocks=sc.nextInt(); int arr[]=new int[numofBlocks]; int src,dest; for(int i=0;i<numofBlocks;i++) { arr[i]=sc.nextInt(); } System.out.println(solution(arr)); } } } Juspay ✅ Telegram:- @allcoding1

import java.util.Scanner; import java.util.*; public class metting {     public static void helperFunction()     {         Scanner sc = new Scanner(System.in);         int n = sc.nextInt();         int[] edges = new int[n];                 for (int i = 0; i < n; i++)         {             edges[i] = sc.nextInt();         }                 int C1 = sc.nextInt();         int C2 = sc.nextInt();         // int ans=minimumWeight(n,edges,C1,C2);         // System.out.println(ans);   //  public static int minimumWeight(int n, int[] edges, int C1, int C2) {         List<List<Integer>> list = new ArrayList<>();         for (int i = 0; i < n; i++) {             list.add(new ArrayList<Integer>());         }         for (int i = 0; i < n; i++) {             if (edges[i] != -1) {                 list.get(i).add(edges[i]);             }         }         long[] array1 = new long[n];         long[] array2 = new long[n];         Arrays.fill(array1, Long.MAX_VALUE);         Arrays.fill(array2, Long.MAX_VALUE);         juspay(C1, list, array1);         juspay(C2, list, array2);         int node = 0;         long dist = Long.MAX_VALUE;         for (int i = 0; i < n; i++) {             if (array1[i] == Long.MAX_VALUE || array2[i] == Long.MAX_VALUE)                 continue;             if (dist > array1[i] + array2[i]) {                 dist = array1[i] + array2[i];                 node = i;             }         }         if (dist == Long.MAX_VALUE)         System.out.print(-1);             //return -1;        // return node;          System.out.print(node);     }     private static void juspay(int start, List<List<Integer>> graph, long[] distances)     {         PriorityQueue<Integer> pq = new PriorityQueue<>();         pq.offer(start);         distances[start] = 0;         while (!pq.isEmpty())         {             int curr = pq.poll();             for (int neighbor : graph.get(curr))             {                 long distance = distances[curr] + 1;                 if (distance < distances[neighbor])                 {                     distances[neighbor] = distance;                     pq.offer(neighbor);                 }             }         }     }     public static void main(String[] args) {      metting m = new metting();         metting.helperFunction();     } } Nearest meeting Cell Juspay ✅ Telegram:- @allcoding1

🎯TCS National Qualifier Test (TCS NQT) 2024 Location: Across India Qualification: B.E / B.Tech / M.E / M.Tech / M.Sc / MCA / Any Graduate / Under Graduate / Diploma Batch: 2018/2019/2020/2021/2022/2023/2024 Apply Now:- www.allcoding1.com Telegram:- @allcoding1

string make_string_S_to_T(string S) {     string T=“programming”;     bool possible = false;     int M = T.length();     int N = S.length();     for (int i = 0; i <= M; i++) {         int prefix_length = i;         int suffix_length = M - i;         string prefix = S.substr(0, prefix_length);         string suffix = S.substr(N - suffix_length, suffix_length);         if (prefix + suffix == T) {             possible = true;             break;         }     }     if (possible)         return "YES";     else         return "NO"; } Deleting substring ✅ Zeta Telegram:- @allcoding1

#include using namespace std; vector solution(vector a, int n, int k) { &nbsp;&nbsp;&nbsp; vector v; &nbsp;&nbsp;&nbsp; deque
#include <bits/stdc++.h> using namespace std; vector<int> solution(vector<int> a, int n, int k) {     vector<int> v;     deque<int> dq;     for (int i = 0; i < n; i++) {         while (!dq.empty() && dq.front() <= i - k)             dq.pop_front();         while (!dq.empty() && a[dq.back()] <= a[i])             dq.pop_back();         dq.push_back(i);         if (i >= k - 1)             v.push_back(a[dq.front()]);     }     return v; } int main() {     int n, k;     cin >> n >> k;     vector<int> a(n);     for (int i = 0; i < n; i++)         cin >> a[i];     vector<int> result = solution(a, n, k);     for (int i = 0; i < result.size(); i++)         cout << result[i] << " ";     return 0; }.  //cricket match ✅ Zeta Telegram:- @allcoding1

class Solution { public:      void bfs(vector<vector<int>>&vis,vector<vector<char>>&grid,int i,int j,int n,int m)     {         vis[i][j]=1;         queue<pair<int,int>>q;         q.push({i,j});         while(!q.empty())         {             int row=q.front().first;             int col=q.front().second;             q.pop();             int delrow[4]={1,0,-1,0};             int delcol[4]={0,1,0,-1};                    for(int k=0;k<=3;k++){                     int nrow=row+delrow[k];                     int ncol=col+delcol[k];                     if(nrow>=0 and nrow<n and ncol>=0 and ncol<m and grid[nrow][ncol]=='1' and !vis[nrow][ncol])                     {                         vis[nrow][ncol]=1;                         q.push({nrow,ncol});                     }                 }             }         }     int numIslands(vector<vector<char>>& grid) {     int n=grid.size();         int m=grid[0].size();         vector<vector<int>>vis(n,vector<int>(m,0));         int cnt=0;         for(int i=0;i<n;i++)         {             for(int j=0;j<m;j++)             {                 if(!vis[i][j] and grid[i][j]=='1')                 {                     cnt++;                     bfs(vis,grid,i,j,n,m);                 }             }         }         return cnt;     } }; Zeta ✅ Telegram:- @allcoding1

class Solution { public:      void bfs(vector<vector<int>>&vis,vector<vector<char>>&grid,int i,int j,int n,int m)     {         vis[i][j]=1;         queue<pair<int,int>>q;         q.push({i,j});         while(!q.empty())         {             int row=q.front().first;             int col=q.front().second;             q.pop();             int delrow[4]={1,0,-1,0};             int delcol[4]={0,1,0,-1};                    for(int k=0;k<=3;k++){                     int nrow=row+delrow[k];                     int ncol=col+delcol[k];                     if(nrow>=0 and nrow<n and ncol>=0 and ncol<m and grid[nrow][ncol]=='1' and !vis[nrow][ncol])                     {                         vis[nrow][ncol]=1;                         q.push({nrow,ncol});                     }                 }             }         }     int numIslands(vector<vector<char>>& grid) {     int n=grid.size();         int m=grid[0].size();         vector<vector<int>>vis(n,vector<int>(m,0));         int cnt=0;         for(int i=0;i<n;i++)         {             for(int j=0;j<m;j++)             {                 if(!vis[i][j] and grid[i][j]=='1')                 {                     cnt++;                     bfs(vis,grid,i,j,n,m);                 }             }         }         return cnt;     } }; Zeta ✅ Telegram:- @allcoding1

any paid promotion DM :- @Priya_i

Fake #scammer This not my ID @allcoding1_officiaI

KPMG Off Campus Drive Hiring 2024 | Front End Developer | 4 LPA+ Job Title : Front End Developer Qualification : B.E / B.Tech Batch : Any Batch Package : 4 LPA+ Apply Now:- www.allcoding1.com Telegram:- @allcoding1

SELECT category, title, total_stock FROM ( SELECT p.category, p.title, SUM(w.quantity) AS total_stock FROM products p JOIN wa
SELECT   category,   title,   total_stock FROM (   SELECT     p.category,     p.title,     SUM(w.quantity) AS total_stock   FROM     products p   JOIN     warehouse w ON p.product_id = w.product_id   GROUP BY     p.category, p.title   HAVING     total_stock > 10 ) AS filtered_data ORDER BY   category ASC, title ASC, total_stock DESC; IBM✅ Telegram:- @allcoding1

IBM✅ SQL Telegram:- @allcoding1
+1
IBM✅ SQL Telegram:- @allcoding1