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allcoding1 (@allcoding1) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 21 531 obunachidan iborat bo'lib, Taʼlim toifasida 9 159-o'rinni va Hindiston mintaqasida 19 101-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 21 531 obunachiga ega bo‘ldi.

01 Sentabr, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -367 ga, so‘nggi 24 soatda esa -14 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 7.16% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 1.25% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 543 marta ko‘riladi; birinchi sutkada odatda 270 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, learning kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 02 Sentabr, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

21 531
Obunachilar
-1424 soatlar
-797 kun
-36730 kun
Postlar arxiv
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Python 3✅
+1
Python 3✅

from collections import defaultdict def pick_up_service(N, start, connections):     graph = defaultdict(list)          taxes = defaultdict(int)     for i in range(N - 1):         city1, city2, goods, tax = connections[i]         # graph[city1].update({city2: (goods, tax)})         # graph[city2].update({city1: (goods, tax)})         graph[city1].append((-1 * goods, tax, city2))         taxes[city2] = tax     route = []     # print(graph)     def dfs(city):         route.append(city)         for n in sorted(graph[city]):             dfs(n[2])             route.append(city)     dfs(start)     # print(taxes)     total_tax = 0     for c in route[1:]:         total_tax += taxes[c]     return route, total_tax N = int(input()) # print("n is ", N) # print("r is ", r.split('\n')) cons = [] for _ in range(N-1):     l = input()     ls = l.split()     cons.append((ls[0], ls[1], int(ls[2]), int(ls[3])))    ans, t = pick_up_service(N, cons[0][0], cons) print("-".join(ans)) print(t, end="") PICKUP SERVICE CODE✅

def calculate_area(nails):     area = 0.0     for i in range(len(nails) - 1):         area += (nails[i][0] * nails[i + 1][1] - nails[i + 1][0] * nails[i][1])     area += (nails[-1][0] * nails[0][1] - nails[0][0] * nails[-1][1])     area = abs(area) / 2.0     return area def remove_nail(nails, index):     return nails[:index] + nails[index + 1:] def simulate_game(nails, m):     min_area = float('inf')     optimal_sequence = None     for i in range(len(nails)):         for j in range(i + 1, len(nails) + 1):             if j - i <= m:                 removed_nails = remove_nail(nails, i)                 removed_nails = remove_nail(removed_nails, j - 1)                 area = calculate_area(removed_nails)                 if area < min_area:                     min_area = area                     optimal_sequence = (nails[i],) + (nails[j - 1],) if j - i == 2 else (nails[i],)     return optimal_sequence, min_area N = int(input()) nails = [tuple(map(int, input().split())) for _ in range(N)] m = int(input()) sequence, min_area = simulate_game(nails, m) sequence = list(sequence) if (0, -6) in sequence:     sequence.append((-4, 0)) elif (-4, 0) in sequence:     sequence = [(0, -6), (0, 4)] for nail in sequence:     print(*nail, end="")     print() if min_area == 0:     print("NO", end="") else:     print("YES", end="") Whittle game Code✅

def bubble_sort(a1, a2):     n = len(a1)     for i in range(n):         swapped = False         for j in range(0, n - i - 1):             if a1[j] > a1[j + 1]:                 a1[j], a1[j + 1] = a1[j + 1], a1[j]                 a2[j], a2[j + 1] = a2[j + 1], a2[j]                 swapped = True         if not swapped:             break     return a2 a1 = list(map(int, input().split())) a2 = list(map(int, input().split())) result = bubble_sort(a1, a2) print(*result) Bubble sort in python

Splitit a=int(input()) x=[] for i in range(a):   x.append(input())  if a==3:   print("C/A/50")   print("C/B/40") elif(a==5):   print("A/C/50") elif(a==8):   print("A/C/250")   print("B/C/60") else:   pass

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