en
Feedback
ACCENTURE EXAM HELP ! CISCO EXAM !

ACCENTURE EXAM HELP ! CISCO EXAM !

Open in Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

Show more

📈 Analytical overview of Telegram channel ACCENTURE EXAM HELP ! CISCO EXAM !

Channel ACCENTURE EXAM HELP ! CISCO EXAM ! (@coding_are) in the English language segment is an active participant. Currently, the community unites 13 207 subscribers, ranking 15 294 in the Education category and 31 490 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 13 207 subscribers.

According to the latest data from 30 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -144 over the last 30 days and by 6 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 3.08%. Within the first 24 hours after publication, content typically collects 1.29% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 407 views. Within the first day, a publication typically gains 170 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
  • Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

Thanks to the high frequency of updates (latest data received on 01 July, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

13 207
Subscribers
+624 hours
-127 days
-14430 days
Posts Archive
For BNY mellon answers join the group Join ..👇👇👇👇 https://t.me/ibmsolution

IBM exam successfully done by laptop access ✅✅✅✅ Both code fully passed with all test case passed ✅✅ Contact for placement ex
+1
IBM exam successfully done by laptop access ✅✅✅✅ Both code fully passed with all test case passed ✅✅ Contact for placement exams @srksvk

IBM Hiring Role :- Application Developer Location - Banglore Full time You will get the Exam link in 1-2 Hours. Apply Link https://careers.ibm.com/job/19372309/application-developer-content-courseware-design-bangalore-in/ Apply soon link may be expire anytime. U got Exam mail also Immediately Those who want clear IBM exam so contact fast and book your slotts Contact @srksvk

Lumens exam successfully done by laptop access bro ✅✅✅✅✅✅✅ All critical mcq are done with 100% correct answer ✅✅ Contact for
+2
Lumens exam successfully done by laptop access bro ✅✅✅✅✅✅✅ All critical mcq are done with 100% correct answer ✅✅ Contact for placement exams @srksvk

Virtusa and ibm for answer solution. Join .. https://t.me/ibmsolution

Virtusa Exam All Codes available Help available Contact @VickySir12

IBM exam successfully done by remote access ✅✅✅ Both code fully paased with all tets case passed ✅✅ Contact for exams @srksvk
+1
IBM exam successfully done by remote access ✅✅✅ Both code fully paased with all tets case passed ✅✅ Contact for exams @srksvk

E Litmus. , Virtusa Exam , ibm exam Help available Book your slot Limited Slots Available. Contact @srksvk 100% Clearance guarantee.and genuine help Remote access available ✅

IBM exam successfully done by remote access ✅✅✅ Both code fully paased with all tets case passed ✅✅ Contact for exams @srksvk
+1
IBM exam successfully done by remote access ✅✅✅ Both code fully paased with all tets case passed ✅✅ Contact for exams @srksvk

Amazon sde exam successfully done by remote access ✅✅✅ Bith code fully passed with all tets case passed ✅✅ All MCQ 💯% correc
+5
Amazon sde exam successfully done by remote access ✅✅✅ Bith code fully passed with all tets case passed ✅✅ All MCQ 💯% correct ✅✅✅ Contact for placement exam @srksvk

E Litmus. , Virtusa Exam , ibm exam Help available Book your slot Limited Slots Available. Contact @srksvk 100% Clearance guarantee.and genuine help Remote access available ✅

Hello Everyone Welcome Guys We tried our best to help you in free in TCS CODEVITAA 💯 Mostly code successfully ✅✅💯💯 Due to lot of rush we are unable to provide personal support to each candidate But we posted codes here to help you. So support Us And we will help u in any placement drive Thank You.

Guys Submit your exam Only 9 mins left Otherwise at end moment server issue you will face

Share ✅✅✅✅✅✅ Share ✅✅✅✅ @codeing_area

Shared everyonee fasttt I will uploded all code ...full working Shared ✅✅✅✅

----- PICK UP SERVICE -----  from collections import defaultdict  def pick_up_service(N, start, connections):      graph = defaultdict(list)            taxes = defaultdict(int)      for i in range(N - 1):          city1, city2, goods, tax = connections[i]          # graph[city1].update({city2: (goods, tax)})          # graph[city2].update({city1: (goods, tax)})          graph[city1].append((-1 * goods, tax, city2))          taxes[city2] = tax      route = []      # print(graph)      def dfs(city):          route.append(city)          for n in sorted(graph[city]):              dfs(n[2])              route.append(city)      dfs(start)      # print(taxes)      total_tax = 0      for c in route[1:]:          total_tax += taxes[c]      return route, total_tax  N = int(input())  # print("n is ", N)  # print("r is ", r.split('\n'))  cons = []  for _ in range(N-1):      l = input()      ls = l.split()      cons.append((ls[0], ls[1], int(ls[2]), int(ls[3])))      ans, t = pick_up_service(N, cons[0][0], cons)  print("-".join(ans))  print(t, end="") Fully working ✅😁😁😁😁 Passes ✅✅✅✅ Share @codeing_area

✅✅✅

Share shared