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INFOSYS EXAM SOLUTIONS

INFOSYS EXAM SOLUTIONS

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πŸ”₯Guys plz Stop fearing for daily exams πŸ“ πŸ‘¨β€πŸ’» @srksvk is here to help you all at lowest cost possible.πŸ’ͺ πŸŒ€ ” Our Only Aim Is To Let Get Placed To You In A Reputed Company πŸ”₯Effort from our side = πŸ’― πŸ“±Main Channel: @coding_are πŸ“±Tel I'd : @srksvk

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πŸ“ˆ Analytical overview of Telegram channel INFOSYS EXAM SOLUTIONS

Channel INFOSYS EXAM SOLUTIONS (@coding_are) in the English language segment is an active participant. Currently, the community unites 14 323 subscribers, ranking 14 155 in the Education category and 29 163 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 14 323 subscribers.

According to the latest data from 01 August, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 987 over the last 30 days and by 552 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 7.48%. Within the first 24 hours after publication, content typically collects 2.55% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 1 061 views. Within the first day, a publication typically gains 362 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 3.
  • Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œπŸ”₯Guys plz Stop fearing for daily exams πŸ“ πŸ‘¨β€πŸ’» @srksvk is here to help you all at lowest cost possible.πŸ’ͺ πŸŒ€ ” Our Only Aim Is To Let Get Placed To You In A Reputed Company πŸ”₯Effort from our side = πŸ’― πŸ“±Main Channel: @coding_are πŸ“±Tel I'd : @srks...”

Thanks to the high frequency of updates (latest data received on 02 August, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

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else t = (p.y - A.y) / dy; } withT.push_back({t, p}); } sort(withT.begin(), withT.end(), [](const pair&a, const pair&b){ return a.first < b.first; }); for (size_t k=1;k visited(V,0); vector path; set cyclesSeen; bool anyCycle = false; const double EPS_COMPARE = 1e-7; auto cycleKeyCanon = [&](const vector &c)->string{ int n = c.size(); int minpos = 0; for (int i=1;i r1; for (int i=0;i r2; for (int i=0;i> foundCycles; function dfs = [&](int start, int u){ for (int v : adj[u]){ if (v == start && path.size() >= 3){ vector cycle = path; string key = cycleKeyCanon(cycle); if (!cyclesSeen.count(key)){ cyclesSeen.insert(key); foundCycles.push_back(cycle); } anyCycle = true; continue; } if (!visited[v] && v > start){ visited[v] = 1; path.push_back(v); dfs(start, v); path.pop_back(); visited[v] = 0; } } }; for (int s=0;s poly; for (int id : cycle) poly.push_back(nodes[id]); double areaK = polygonArea(poly); if (areaK <= EPS) continue; double usedPerim = 0.0; for (int i=0;i areaC + EPS_COMPARE){ cout<<"Kalyan"; return 0; } } cout<<"Computer"; return 0; }

include <iostream> #include <vector> #include <string> #include <cmath> #include <iomanip> #include <sstream> #include <unordered_map> #include <algorithm> #include <set> #include <functional> using namespace std; const double EPS = 1e-9; const double PI = acos(-1.0); struct P { double x,y; }; struct Seg { P a,b; }; double cross(const P &u, const P &v){ return u.x*v.y - u.y*v.x; } P operator-(const P &a, const P &b){ return {a.x-b.x, a.y-b.y}; } double dot(const P&a,const P&b){ return a.x*b.x + a.y*b.y; } bool eq(double a,double b){ return fabs(a-b) < EPS; } bool onSeg(const P &a, const P &b, const P &p){ if (!eq(cross(b-a, p-a), 0.0)) return false; if (p.x < min(a.x,b.x)-EPS || p.x > max(a.x,b.x)+EPS) return false; if (p.y < min(a.y,b.y)-EPS || p.y > max(a.y,b.y)+EPS) return false; return true; } bool lineIntersect(const P &p1, const P &p2, const P &p3, const P &p4, P &out){ P r = p2 - p1; P s = p4 - p3; double rxs = cross(r, s); double qpxr = cross(p3 - p1, r); if (fabs(rxs) < EPS) return false; double t = cross(p3 - p1, s) / rxs; out = { p1.x + t * r.x, p1.y + t * r.y }; return true; } double dist(const P &a, const P &b){ double dx = a.x - b.x, dy = a.y - b.y; return sqrt(dx*dx + dy*dy); } string keyPt(const P &p){ ostringstream oss; oss<<fixed<<setprecision(8)<<p.x<<","<<p.y; return oss.str(); } double polygonArea(const vector<P> &poly){ int n = poly.size(); if (n < 3) return 0.0; double a = 0; for (int i=0;i<n;i++){ int j=(i+1)%n; a += poly[i].x*poly[j].y - poly[j].x*poly[i].y; } return fabs(a)/2.0; } int main(){ ios::sync_with_stdio(false); cin.tie(nullptr); int N; if(!(cin>>N)) return 0; vector<Seg> segs(N); double totalLen = 0.0; for (int i=0;i<N;i++){ cin>>segs[i].a.x>>segs[i].a.y>>segs[i].b.x>>segs[i].b.y; totalLen += dist(segs[i].a, segs[i].b); } vector<vector<P>> ptsOnSeg(N); for (int i=0;i<N;i++){ ptsOnSeg[i].push_back(segs[i].a); ptsOnSeg[i].push_back(segs[i].b); } for (int i=0;i<N;i++){ for (int j=i+1;j<N;j++){ P inter; bool linesInt = lineIntersect(segs[i].a, segs[i].b, segs[j].a, segs[j].b, inter); if (linesInt){ if (onSeg(segs[i].a, segs[i].b, inter) && onSeg(segs[j].a, segs[j].b, inter)){ ptsOnSeg[i].push_back(inter); ptsOnSeg[j].push_back(inter); } } else { } } } unordered_map<string,int> nodeId; vector<P> nodes; vector<vector<int>> adj; auto addNode = [&](const P &p)->int{ string k = keyPt(p); auto it = nodeId.find(k); if (it!=nodeId.end()) return it->second; int id = nodes.size(); nodes.push_back(p); nodeId[k] = id; adj.emplace_back(); return id; }; for (int i=0;i<N;i++){ auto &vec = ptsOnSeg[i]; sort(vec.begin(), vec.end(), [](const P &u, const P &v){ if (!eq(u.x, v.x)) return u.x < v.x; return u.y < v.y; }); vector<P> uniquePts; for (auto &p : vec){ if (uniquePts.empty() fabs(p.x - uniquePts.back().x) > 1e-7 fabs(p.y - uniquePts.back().y) > 1e-7) uniquePts.push_back(p); } if (uniquePts.size() < 2) continue; P A = segs[i].a, B = segs[i].b; double dx = B.x - A.x, dy = B.y - A.y; vector<pair<double,P>> withT; for (auto &p : uniquePts){ double t; if (fabs(dx) >= fabs(dy)){ if (fabs(dx) < EPS) t = 0.0; else t = (p.x - A.x) / dx; } else { if (fabs(dy) < EPS) t = 0.0;

#include <bits/stdc++.h> using namespace std; long long fn(const vector<array<int,4>>& rs, int lo, int hi, int ax) {     int i1 = (ax == 0 ? 0 : 1), i2 = (ax == 0 ? 2 : 3);     set<int> st{lo, hi};     for (auto &r : rs) { st.insert(r[i1]); st.insert(r[i2]); }     vector<int> a(st.begin(), st.end());     vector<int> vf;     for (int x : a) {         bool ok = true;         for (auto &r : rs) if (r[i1] < x && x < r[i2]) { ok = false; break; }         if (ok) vf.push_back(x);     }     long long ans = (long long)1e18;     for (size_t i = 0; i + 1 < vf.size(); ++i) {         int d = vf[i+1] - vf[i];         if (d == 1) return 1;         if (d < ans) ans = d;     }     for (size_t i = 0; i + 1 < a.size(); ++i) {         int x = a[i], y = a[i+1];         if (y - x <= 1) continue;         bool bad = false;         for (auto &r : rs) if (r[i1] <= x && y <= r[i2]) { bad = true; break; }         if (!bad) return 1;     }     return ans; } int main() {     ios::sync_with_stdio(false);     cin.tie(nullptr);     int n;     if (!(cin >> n)) return 0;     vector<array<int,4>> rs(n);     for (int i = 0; i < n; ++i) cin >> rs[i][0] >> rs[i][1] >> rs[i][2] >> rs[i][3];     int ox1, oy1, ox2, oy2;     cin >> ox1 >> oy1 >> ox2 >> oy2;     long long w = fn(rs, ox1, ox2, 0);     long long h = fn(rs, oy1, oy2, 1);     cout << (w * h) << '\n';     return 0; } Smallest Region Code done βœ…βœ… Share with Friends .Don't MissπŸ˜Šβœ… https://t.me/coding_are

import sys from collections import defaultdict def main(): a = list(map(int, sys.stdin.read().strip().split())) i = 0 n = a[i]; i += 1 sl = [] for _ in range(n): x1, y1, x2, y2 = a[i:i+4]; i += 4 sl.append((x1, y1, x2, y2)) sx, sy, e = a[i], a[i+1], a[i+2] g = defaultdict(list) nx = {} for s, (x1, y1, x2, y2) in enumerate(sl): dx = 1 if x2 > x1 else -1 dy = 1 if y2 > y1 else -1 L = abs(x2 - x1) if dy == -1: for k in range(L): x = x1 + dx * k y = y1 - k g[(x, y)].append(s) nx[(x, y, s)] = (x + dx, y - 1) g[(x2, y2)].append(s) else: for k in range(L): x = x2 - dx * k y = y2 - k g[(x, y)].append(s) nx[(x, y, s)] = (x - dx, y - 1) g[(x1, y1)].append(s) def fall(x, y): for yy in range(y - 1, -1, -1): if (x, yy) in g: return x, yy return x, 0 x, y = sx, sy if (x, y) not in g: x, y = fall(x, y) while True: if y == 0: break if (x, y) not in g: x, y = fall(x, y) continue ids = g[(x, y)] if len(ids) == 1: s = ids[0] if (x, y, s) not in nx: x, y = fall(x, y) continue if e == 0: break e -= 1 x, y = nx[(x, y, s)] else: c = x * y dn = [(s, nx[(x, y, s)]) for s in ids if (x, y, s) in nx] if e <= c: if not dn: x, y = fall(x, y) continue break e -= c if not dn: x, y = fall(x, y) continue bx, by = None, -1 for s, (xx, yy) in dn: if yy > by: bx, by = xx, yy if e == 0: break e -= 1 x, y = bx, by print(x, y) if name == "main": main() GRAVITY GLIDE βœ… SHARE CHANNEL TO UR FRIENDS https://t.me/coding_are

#include <bits/stdc++.h> using namespace std; using ll = long long; using P = pair<ll,ll>; static vector<P> merge_itv(vector<P> v){ sort(v.begin(), v.end()); vector<P> r; for(auto &p: v){ if(r.empty() || p.first > r.back().second){ r.push_back(p); }else{ if(p.second > r.back().second) r.back().second = p.second; } } return r; } int main(){ ios::sync_with_stdio(false); cin.tie(nullptr); int n; if(!(cin >> n)) return 0; map<ll, vector<P>> hv; map<ll, vector<P>> vv; for(int i=0;i<n;i++){ ll x1,y1,x2,y2; cin >> x1 >> y1 >> x2 >> y2; if(y1 == y2){ if(x1 > x2) swap(x1,x2); hv[y1].push_back({x1,x2}); }else{ if(y1 > y2) swap(y1,y2); vv[x1].push_back({y1,y2}); } } struct H { ll y,l,r; }; vector<H> hs; for(auto &e: hv){ ll y = e.first; auto m = merge_itv(e.second); for(auto &q: m) hs.push_back({y, q.first, q.second}); } struct V { ll x,yb,yt; }; vector<V> vs; for(auto &e: vv){ ll x = e.first; auto m = merge_itv(e.second); for(auto &q: m) vs.push_back({x, q.first, q.second}); } int h = (int)hs.size(); int v = (int)vs.size(); int w = (h + 63) >> 6; vector<vector<unsigned long long>> msk(v, vector<unsigned long long>(w, 0ULL)); for(int i=0;i<v;i++){ ll x = vs[i].x, yb = vs[i].yb, yt = vs[i].yt; for(int j=0;j<h;j++){ const auto &hh = hs[j]; if(yb <= hh.y && hh.y <= yt && hh.l <= x && x <= hh.r){ int b = j >> 6, o = j & 63; msk[i][b] |= (1ULL << o); } } } long long ans = 0; for(int i=0;i<v;i++){ for(int j=i+1;j<v;j++){ long long k = 0; for(int b=0;b<w;b++){ unsigned long long x = msk[i][b] & msk[j][b]; k += __builtin_popcountll(x); } if(k >= 2) ans += k*(k-1)/2; } } cout << ans << "\n"; return 0; } *Shape Counts* 😍😍 *Join & Share this channel in your College groups For Placement Help* https://t.me/coding_are

#include <bits/stdc++.h> using namespace std; struct P { int x, y; bool operator==(const P &o) const { return x == o.x && y == o.y; } }; struct PH { size_t operator()(P const &p) const { return (uint64_t(uint32_t(p.x)) << 32) ^ uint32_t(p.y); } }; struct K { int x, y, s; bool operator==(const K &o) const { return x == o.x && y == o.y && s == o.s; } }; struct KH { size_t operator()(K const &k) const { uint64_t h = k.x; h = (h << 21) ^ k.y; h = (h << 21) ^ k.s; return size_t(h); } }; int main() { ios::sync_with_stdio(false); cin.tie(nullptr); vector<long long> a; long long v; while (cin >> v) a.push_back(v); int i = 0; int n = (int)a[i++]; vector<array<int,4>> sl(n); for (int j = 0; j < n; j++) { sl[j][0] = (int)a[i++]; sl[j][1] = (int)a[i++]; sl[j][2] = (int)a[i++]; sl[j][3] = (int)a[i++]; } int sx = (int)a[i++], sy = (int)a[i++], e = (int)a[i++]; unordered_map<P, vector<int>, PH> g; unordered_map<K, pair<int,int>, KH> nx; for (int s = 0; s < n; s++) { int x1 = sl[s][0], y1 = sl[s][1], x2 = sl[s][2], y2 = sl[s][3]; int dx = (x2 > x1) ? 1 : -1; int dy = (y2 > y1) ? 1 : -1; int L = abs(x2 - x1); if (dy == -1) { for (int k = 0; k < L; k++) { int x = x1 + dx * k; int y = y1 - k; g[{x,y}].push_back(s); nx[{x,y,s}] = {x + dx, y - 1}; } g[{x2,y2}].push_back(s); } else { for (int k = 0; k < L; k++) { int x = x2 - dx * k; int y = y2 - k; g[{x,y}].push_back(s); nx[{x,y,s}] = {x - dx, y - 1}; } g[{x1,y1}].push_back(s); } } auto fall = [&](int x, int y) -> pair<int,int> { for (int yy = y - 1; yy >= 0; yy--) { auto it = g.find({x, yy}); if (it != g.end()) return {x, yy}; } return {x, 0}; }; int x = sx, y = sy; if (g.find({x,y}) == g.end()) { auto p = fall(x, y); x = p.first; y = p.second; } while (true) { if (y == 0) break; auto it = g.find({x,y}); if (it == g.end()) { auto p = fall(x, y); x = p.first; y = p.second; continue; } auto &ids = it->second; if (ids.size() == 1) { int s = ids[0]; auto it2 = nx.find({x,y,s}); if (it2 == nx.end()) { auto p = fall(x, y); x = p.first; y = p.second; continue; } if (e == 0) break; e--; x = it2->second.first; y = it2->second.second; } else { long long c = 1LL * x * y; vector<pair<int,pair<int,int>>> dn; dn.reserve(ids.size()); for (int s : ids) { auto it3 = nx.find({x,y,s}); if (it3 != nx.end()) dn.push_back({s, it3->second}); } if ((long long)e <= c) { if (dn.empty()) { auto p = fall(x, y); x = p.first; y = p.second; continue; } break; } e -= (int)c; if (dn.empty()) { auto p = fall(x, y); x = p.first; y = p.second; continue; } int bx = 0, by = -1; for (auto &qq : dn) { int xx = qq.second.first; int yy = qq.second.second; if (yy > by) { by = yy; bx = xx; } } if (e == 0) break; e--; x = bx; y = by; } } cout << x << " " << y; return 0; } Gravity Code βœ…βœ… Share our channel Fast https://t.me/coding_are

Uno Code #include <bits/stdc++.h> using namespace std; int findp(int x, vector<int>& p) { return p[x] == x ? x : p[x] = findp(p[x], p); } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int n; cin >> n; vector<string> names(n); for (int i = 0; i < n; i++) cin >> names[i]; vector<int> skill(n); for (int i = 0; i < n; i++) cin >> skill[i]; unordered_map<string, int> id; for (int i = 0; i < n; i++) id[names[i]] = i; int f; cin >> f; vector<int> p(n); iota(p.begin(), p.end(), 0); for (int i = 0; i < f; i++) { string a, b; cin >> a >> b; int x = findp(id[a], p), y = findp(id[b], p); if (x != y) p[y] = x; } unordered_map<int, vector<int>> clusters; for (int i = 0; i < n; i++) clusters[findp(i, p)].push_back(i); vector<vector<int>> group; vector<int> groupSkill, groupSize; for (auto& [r, v] : clusters) { group.push_back(v); int s = 0; for (int x : v) s += skill[x]; groupSkill.push_back(s); groupSize.push_back(v.size()); } int r; cin >> r; int m = group.size(); vector<vector<int>> rival(m); unordered_map<int, int> idx; { int i = 0; for (auto& [root, _] : clusters) idx[root] = i++; } for (int i = 0; i < r; i++) { string a, b; cin >> a >> b; int ga = idx[findp(id[a], p)]; int gb = idx[findp(id[b], p)]; if (ga != gb) { rival[ga].push_back(gb); rival[gb].push_back(ga); } } int limit; cin >> limit; int best = 0; int total = 1 << m; for (int mask = 0; mask < total; mask++) { int sumSkill = 0, count = 0; bool valid = true; for (int i = 0; i < m && valid; i++) { if (mask & (1 << i)) { for (int x : rival[i]) { if (mask & (1 << x)) { valid = false; break; } } sumSkill += groupSkill[i]; if (sumSkill > limit) { valid = false; break; } count += groupSize[i]; } } if (valid) best = max(best, count); } cout << best; return 0; } Uno Code βœ… βœ… All Passed πŸ’―πŸ’―βœ…βœ… Share our channel Fast https://t.me/coding_are

C++ Cable Wrap TCS CodeVita Zone 2 #include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int N, M; cin >> N >> M; vector<string> grid(N); for (int i = 0; i < N; i++) { grid[i].resize(M); for (int j = 0; j < M; j++) { cin >> grid[i][j]; } } vector<int> horizontal_rods, vertical_rods; for (int i = 0; i < N; i++) { if (all_of(grid[i].begin(), grid[i].end(), [](char c){ return c != '.'; })) horizontal_rods.push_back(i); } for (int j = 0; j < M; j++) { bool full = true; for (int i = 0; i < N; i++) if (grid[i][j] == '.') full = false; if (full) vertical_rods.push_back(j); } vector<vector<bool>> is_cross(N, vector<bool>(M, false)); for (int c : vertical_rods) { for (int i = 0; i < N; i++) { int left = c - 1, right = c + 1; if (left >= 0 && right < M && grid[i][left] == 'C' && grid[i][right] == 'C') is_cross[i][c] = true; } } for (int r : horizontal_rods) { for (int j = 0; j < M; j++) { int up = r - 1, down = r + 1; if (up >= 0 && down < N && grid[up][j] == 'C' && grid[down][j] == 'C') is_cross[r][j] = true; } } vector<vector<bool>> cable(N, vector<bool>(M, false)); for (int i = 0; i < N; i++) for (int j = 0; j < M; j++) if (grid[i][j] == 'C' || is_cross[i][j]) cable[i][j] = true; vector<vector<int>> adj(N * M); int di[4] = {-1, 0, 1, 0}; int dj[4] = {0, 1, 0, -1}; for (int i = 0; i < N; i++) { for (int j = 0; j < M; j++) { if (!cable[i][j]) continue; int id = i * M + j; for (int d = 0; d < 4; d++) { int ni = i + di[d], nj = j + dj[d]; if (ni >= 0 && ni < N && nj >= 0 && nj < M && cable[ni][nj]) adj[id].push_back(ni * M + nj); } } } int start = -1; for (int i = 0; i < N && start == -1; i++) for (int j = 0; j < M; j++) if (cable[i][j] && adj[i * M + j].size() == 1) { start = i * M + j; break; } vector<bool> visited(N * M, false); vector<int> sum_h(N, 0), sum_v(M, 0); int curr = start, prevv = -1; visited[curr] = true; while (true) { int cr = curr / M, cc = curr % M; int nextt = -1; for (int nb : adj[curr]) if (nb != prevv && !visited[nb]) { nextt = nb; break; } if (is_cross[cr][cc] && prevv != -1) { int pr = prevv / M, pc = prevv % M; int sign = (grid[cr][cc] == 'C') ? 1 : -1; if (pr == cr) sum_v[cc] += ((pc < cc) ? 1 : -1) * sign; else sum_h[cr] += ((pr < cr) ? 1 : -1) * sign; } if (nextt == -1) break; prevv = curr; curr = nextt; visited[curr] = true; } long long answer = 0; for (int r : horizontal_rods) answer += abs(sum_h[r]) / 2; for (int c : vertical_rods) answer += abs(sum_v[c]) / 2; cout << answer; return 0; } C++ Cable Wrap TCS CodeVita Zone 2 https://t.me/coding_are

Ubs exam successfully completed by remote access πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘ 1/1 code done with all tests cases passed βœ…βœ…βœ…βœ… 27/27 mce do
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Ubs exam successfully completed by remote access πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘ 1/1 code done with all tests cases passed βœ…βœ…βœ…βœ… 27/27 mce done with πŸ’― correct answer βœ… Contact for placement exam @srksvk

Accenture on campus exam successfully completed by remote access πŸ‘πŸ‘πŸ‘πŸ‘ 90/90 MCQ done βœ… and first round CLEARED πŸŽ‰ πŸ₯³ πŸ₯³ οΏ½
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Accenture on campus exam successfully completed by remote access πŸ‘πŸ‘πŸ‘πŸ‘ 90/90 MCQ done βœ… and first round CLEARED πŸŽ‰ πŸ₯³ πŸ₯³ πŸ₯³ πŸ₯³ πŸ₯³ πŸ₯³ πŸ₯³ πŸ₯³ 2/2 code done with all tests case's passed πŸ”₯ πŸ₯³ Contact for placement exam @srksvk

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Capgemini exam CLEARED πŸŽ‰πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³ Congratulations bro πŸŽ‰πŸŽ‰πŸŽ‰πŸŽ‰πŸŽ‰πŸŽ‰πŸŽ‰ Helped proof πŸ‘‡πŸ‘‡πŸ‘‡ Co
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Capgemini exam CLEARED πŸŽ‰πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³πŸ₯³ Congratulations bro πŸŽ‰πŸŽ‰πŸŽ‰πŸŽ‰πŸŽ‰πŸŽ‰πŸŽ‰ Helped proof πŸ‘‡πŸ‘‡πŸ‘‡ Contact for placement exam @srksvk

Eurofin exam successfully completed by remote access πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘ 2/2 code done with all tests cases passedβœ… 42/42 MCQ done
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Eurofin exam successfully completed by remote access πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘ 2/2 code done with all tests cases passedβœ… 42/42 MCQ done with πŸ’― correct answer βœ…βœ… Contact for placement exam @srksvk

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Black and green exam successfully completed by remote access πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘ 196/196 question done with πŸ’― correct answer πŸ”₯ Contact for placement exam @srksvk

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Visa exam successfully completed by remote access πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘ 4/4 code done with all tests cases passed βœ…βœ… Contact for p
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Ibm exam successfully completed by remote access πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘ 2/2 code done with all tests case's passed πŸ”₯πŸ”₯ Contact for placement exam @srksvk

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