uz
Feedback
INFOSYS EXAM SOLUTIONS

INFOSYS EXAM SOLUTIONS

Kanalga Telegram’da o‘tish

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

Ko'proq ko'rsatish

📈 Telegram kanali INFOSYS EXAM SOLUTIONS analitikasi

INFOSYS EXAM SOLUTIONS (@coding_are) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 14 323 obunachidan iborat bo'lib, Taʼlim toifasida 14 155-o'rinni va Hindiston mintaqasida 29 163-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 14 323 obunachiga ega bo‘ldi.

01 Avgust, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 987 ga, so‘nggi 24 soatda esa 552 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 7.48% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 2.55% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 1 061 marta ko‘riladi; birinchi sutkada odatda 362 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 3 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent placement, gaurntee, suree, capgemini, infosy kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

Yuqori yangilanish chastotasi (oxirgi ma’lumot 02 Avgust, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

14 323
Obunachilar
+55224 soatlar
+8087 kunlar
+98730 kunlar
Postlar arxiv
else t = (p.y - A.y) / dy; } withT.push_back({t, p}); } sort(withT.begin(), withT.end(), [](const pair&a, const pair&b){ return a.first < b.first; }); for (size_t k=1;k visited(V,0); vector path; set cyclesSeen; bool anyCycle = false; const double EPS_COMPARE = 1e-7; auto cycleKeyCanon = [&](const vector &c)->string{ int n = c.size(); int minpos = 0; for (int i=1;i r1; for (int i=0;i r2; for (int i=0;i> foundCycles; function dfs = [&](int start, int u){ for (int v : adj[u]){ if (v == start && path.size() >= 3){ vector cycle = path; string key = cycleKeyCanon(cycle); if (!cyclesSeen.count(key)){ cyclesSeen.insert(key); foundCycles.push_back(cycle); } anyCycle = true; continue; } if (!visited[v] && v > start){ visited[v] = 1; path.push_back(v); dfs(start, v); path.pop_back(); visited[v] = 0; } } }; for (int s=0;s poly; for (int id : cycle) poly.push_back(nodes[id]); double areaK = polygonArea(poly); if (areaK <= EPS) continue; double usedPerim = 0.0; for (int i=0;i areaC + EPS_COMPARE){ cout<<"Kalyan"; return 0; } } cout<<"Computer"; return 0; }

include <iostream> #include <vector> #include <string> #include <cmath> #include <iomanip> #include <sstream> #include <unordered_map> #include <algorithm> #include <set> #include <functional> using namespace std; const double EPS = 1e-9; const double PI = acos(-1.0); struct P { double x,y; }; struct Seg { P a,b; }; double cross(const P &u, const P &v){ return u.x*v.y - u.y*v.x; } P operator-(const P &a, const P &b){ return {a.x-b.x, a.y-b.y}; } double dot(const P&a,const P&b){ return a.x*b.x + a.y*b.y; } bool eq(double a,double b){ return fabs(a-b) < EPS; } bool onSeg(const P &a, const P &b, const P &p){ if (!eq(cross(b-a, p-a), 0.0)) return false; if (p.x < min(a.x,b.x)-EPS || p.x > max(a.x,b.x)+EPS) return false; if (p.y < min(a.y,b.y)-EPS || p.y > max(a.y,b.y)+EPS) return false; return true; } bool lineIntersect(const P &p1, const P &p2, const P &p3, const P &p4, P &out){ P r = p2 - p1; P s = p4 - p3; double rxs = cross(r, s); double qpxr = cross(p3 - p1, r); if (fabs(rxs) < EPS) return false; double t = cross(p3 - p1, s) / rxs; out = { p1.x + t * r.x, p1.y + t * r.y }; return true; } double dist(const P &a, const P &b){ double dx = a.x - b.x, dy = a.y - b.y; return sqrt(dx*dx + dy*dy); } string keyPt(const P &p){ ostringstream oss; oss<<fixed<<setprecision(8)<<p.x<<","<<p.y; return oss.str(); } double polygonArea(const vector<P> &poly){ int n = poly.size(); if (n < 3) return 0.0; double a = 0; for (int i=0;i<n;i++){ int j=(i+1)%n; a += poly[i].x*poly[j].y - poly[j].x*poly[i].y; } return fabs(a)/2.0; } int main(){ ios::sync_with_stdio(false); cin.tie(nullptr); int N; if(!(cin>>N)) return 0; vector<Seg> segs(N); double totalLen = 0.0; for (int i=0;i<N;i++){ cin>>segs[i].a.x>>segs[i].a.y>>segs[i].b.x>>segs[i].b.y; totalLen += dist(segs[i].a, segs[i].b); } vector<vector<P>> ptsOnSeg(N); for (int i=0;i<N;i++){ ptsOnSeg[i].push_back(segs[i].a); ptsOnSeg[i].push_back(segs[i].b); } for (int i=0;i<N;i++){ for (int j=i+1;j<N;j++){ P inter; bool linesInt = lineIntersect(segs[i].a, segs[i].b, segs[j].a, segs[j].b, inter); if (linesInt){ if (onSeg(segs[i].a, segs[i].b, inter) && onSeg(segs[j].a, segs[j].b, inter)){ ptsOnSeg[i].push_back(inter); ptsOnSeg[j].push_back(inter); } } else { } } } unordered_map<string,int> nodeId; vector<P> nodes; vector<vector<int>> adj; auto addNode = [&](const P &p)->int{ string k = keyPt(p); auto it = nodeId.find(k); if (it!=nodeId.end()) return it->second; int id = nodes.size(); nodes.push_back(p); nodeId[k] = id; adj.emplace_back(); return id; }; for (int i=0;i<N;i++){ auto &vec = ptsOnSeg[i]; sort(vec.begin(), vec.end(), [](const P &u, const P &v){ if (!eq(u.x, v.x)) return u.x < v.x; return u.y < v.y; }); vector<P> uniquePts; for (auto &p : vec){ if (uniquePts.empty() fabs(p.x - uniquePts.back().x) > 1e-7 fabs(p.y - uniquePts.back().y) > 1e-7) uniquePts.push_back(p); } if (uniquePts.size() < 2) continue; P A = segs[i].a, B = segs[i].b; double dx = B.x - A.x, dy = B.y - A.y; vector<pair<double,P>> withT; for (auto &p : uniquePts){ double t; if (fabs(dx) >= fabs(dy)){ if (fabs(dx) < EPS) t = 0.0; else t = (p.x - A.x) / dx; } else { if (fabs(dy) < EPS) t = 0.0;

#include <bits/stdc++.h> using namespace std; long long fn(const vector<array<int,4>>& rs, int lo, int hi, int ax) {     int i1 = (ax == 0 ? 0 : 1), i2 = (ax == 0 ? 2 : 3);     set<int> st{lo, hi};     for (auto &r : rs) { st.insert(r[i1]); st.insert(r[i2]); }     vector<int> a(st.begin(), st.end());     vector<int> vf;     for (int x : a) {         bool ok = true;         for (auto &r : rs) if (r[i1] < x && x < r[i2]) { ok = false; break; }         if (ok) vf.push_back(x);     }     long long ans = (long long)1e18;     for (size_t i = 0; i + 1 < vf.size(); ++i) {         int d = vf[i+1] - vf[i];         if (d == 1) return 1;         if (d < ans) ans = d;     }     for (size_t i = 0; i + 1 < a.size(); ++i) {         int x = a[i], y = a[i+1];         if (y - x <= 1) continue;         bool bad = false;         for (auto &r : rs) if (r[i1] <= x && y <= r[i2]) { bad = true; break; }         if (!bad) return 1;     }     return ans; } int main() {     ios::sync_with_stdio(false);     cin.tie(nullptr);     int n;     if (!(cin >> n)) return 0;     vector<array<int,4>> rs(n);     for (int i = 0; i < n; ++i) cin >> rs[i][0] >> rs[i][1] >> rs[i][2] >> rs[i][3];     int ox1, oy1, ox2, oy2;     cin >> ox1 >> oy1 >> ox2 >> oy2;     long long w = fn(rs, ox1, ox2, 0);     long long h = fn(rs, oy1, oy2, 1);     cout << (w * h) << '\n';     return 0; } Smallest Region Code done ✅✅ Share with Friends .Don't Miss😊✅ https://t.me/coding_are

import sys from collections import defaultdict def main(): a = list(map(int, sys.stdin.read().strip().split())) i = 0 n = a[i]; i += 1 sl = [] for _ in range(n): x1, y1, x2, y2 = a[i:i+4]; i += 4 sl.append((x1, y1, x2, y2)) sx, sy, e = a[i], a[i+1], a[i+2] g = defaultdict(list) nx = {} for s, (x1, y1, x2, y2) in enumerate(sl): dx = 1 if x2 > x1 else -1 dy = 1 if y2 > y1 else -1 L = abs(x2 - x1) if dy == -1: for k in range(L): x = x1 + dx * k y = y1 - k g[(x, y)].append(s) nx[(x, y, s)] = (x + dx, y - 1) g[(x2, y2)].append(s) else: for k in range(L): x = x2 - dx * k y = y2 - k g[(x, y)].append(s) nx[(x, y, s)] = (x - dx, y - 1) g[(x1, y1)].append(s) def fall(x, y): for yy in range(y - 1, -1, -1): if (x, yy) in g: return x, yy return x, 0 x, y = sx, sy if (x, y) not in g: x, y = fall(x, y) while True: if y == 0: break if (x, y) not in g: x, y = fall(x, y) continue ids = g[(x, y)] if len(ids) == 1: s = ids[0] if (x, y, s) not in nx: x, y = fall(x, y) continue if e == 0: break e -= 1 x, y = nx[(x, y, s)] else: c = x * y dn = [(s, nx[(x, y, s)]) for s in ids if (x, y, s) in nx] if e <= c: if not dn: x, y = fall(x, y) continue break e -= c if not dn: x, y = fall(x, y) continue bx, by = None, -1 for s, (xx, yy) in dn: if yy > by: bx, by = xx, yy if e == 0: break e -= 1 x, y = bx, by print(x, y) if name == "main": main() GRAVITY GLIDE ✅ SHARE CHANNEL TO UR FRIENDS https://t.me/coding_are

#include <bits/stdc++.h> using namespace std; using ll = long long; using P = pair<ll,ll>; static vector<P> merge_itv(vector<P> v){ sort(v.begin(), v.end()); vector<P> r; for(auto &p: v){ if(r.empty() || p.first > r.back().second){ r.push_back(p); }else{ if(p.second > r.back().second) r.back().second = p.second; } } return r; } int main(){ ios::sync_with_stdio(false); cin.tie(nullptr); int n; if(!(cin >> n)) return 0; map<ll, vector<P>> hv; map<ll, vector<P>> vv; for(int i=0;i<n;i++){ ll x1,y1,x2,y2; cin >> x1 >> y1 >> x2 >> y2; if(y1 == y2){ if(x1 > x2) swap(x1,x2); hv[y1].push_back({x1,x2}); }else{ if(y1 > y2) swap(y1,y2); vv[x1].push_back({y1,y2}); } } struct H { ll y,l,r; }; vector<H> hs; for(auto &e: hv){ ll y = e.first; auto m = merge_itv(e.second); for(auto &q: m) hs.push_back({y, q.first, q.second}); } struct V { ll x,yb,yt; }; vector<V> vs; for(auto &e: vv){ ll x = e.first; auto m = merge_itv(e.second); for(auto &q: m) vs.push_back({x, q.first, q.second}); } int h = (int)hs.size(); int v = (int)vs.size(); int w = (h + 63) >> 6; vector<vector<unsigned long long>> msk(v, vector<unsigned long long>(w, 0ULL)); for(int i=0;i<v;i++){ ll x = vs[i].x, yb = vs[i].yb, yt = vs[i].yt; for(int j=0;j<h;j++){ const auto &hh = hs[j]; if(yb <= hh.y && hh.y <= yt && hh.l <= x && x <= hh.r){ int b = j >> 6, o = j & 63; msk[i][b] |= (1ULL << o); } } } long long ans = 0; for(int i=0;i<v;i++){ for(int j=i+1;j<v;j++){ long long k = 0; for(int b=0;b<w;b++){ unsigned long long x = msk[i][b] & msk[j][b]; k += __builtin_popcountll(x); } if(k >= 2) ans += k*(k-1)/2; } } cout << ans << "\n"; return 0; } *Shape Counts* 😍😍 *Join & Share this channel in your College groups For Placement Help* https://t.me/coding_are

#include <bits/stdc++.h> using namespace std; struct P { int x, y; bool operator==(const P &o) const { return x == o.x && y == o.y; } }; struct PH { size_t operator()(P const &p) const { return (uint64_t(uint32_t(p.x)) << 32) ^ uint32_t(p.y); } }; struct K { int x, y, s; bool operator==(const K &o) const { return x == o.x && y == o.y && s == o.s; } }; struct KH { size_t operator()(K const &k) const { uint64_t h = k.x; h = (h << 21) ^ k.y; h = (h << 21) ^ k.s; return size_t(h); } }; int main() { ios::sync_with_stdio(false); cin.tie(nullptr); vector<long long> a; long long v; while (cin >> v) a.push_back(v); int i = 0; int n = (int)a[i++]; vector<array<int,4>> sl(n); for (int j = 0; j < n; j++) { sl[j][0] = (int)a[i++]; sl[j][1] = (int)a[i++]; sl[j][2] = (int)a[i++]; sl[j][3] = (int)a[i++]; } int sx = (int)a[i++], sy = (int)a[i++], e = (int)a[i++]; unordered_map<P, vector<int>, PH> g; unordered_map<K, pair<int,int>, KH> nx; for (int s = 0; s < n; s++) { int x1 = sl[s][0], y1 = sl[s][1], x2 = sl[s][2], y2 = sl[s][3]; int dx = (x2 > x1) ? 1 : -1; int dy = (y2 > y1) ? 1 : -1; int L = abs(x2 - x1); if (dy == -1) { for (int k = 0; k < L; k++) { int x = x1 + dx * k; int y = y1 - k; g[{x,y}].push_back(s); nx[{x,y,s}] = {x + dx, y - 1}; } g[{x2,y2}].push_back(s); } else { for (int k = 0; k < L; k++) { int x = x2 - dx * k; int y = y2 - k; g[{x,y}].push_back(s); nx[{x,y,s}] = {x - dx, y - 1}; } g[{x1,y1}].push_back(s); } } auto fall = [&](int x, int y) -> pair<int,int> { for (int yy = y - 1; yy >= 0; yy--) { auto it = g.find({x, yy}); if (it != g.end()) return {x, yy}; } return {x, 0}; }; int x = sx, y = sy; if (g.find({x,y}) == g.end()) { auto p = fall(x, y); x = p.first; y = p.second; } while (true) { if (y == 0) break; auto it = g.find({x,y}); if (it == g.end()) { auto p = fall(x, y); x = p.first; y = p.second; continue; } auto &ids = it->second; if (ids.size() == 1) { int s = ids[0]; auto it2 = nx.find({x,y,s}); if (it2 == nx.end()) { auto p = fall(x, y); x = p.first; y = p.second; continue; } if (e == 0) break; e--; x = it2->second.first; y = it2->second.second; } else { long long c = 1LL * x * y; vector<pair<int,pair<int,int>>> dn; dn.reserve(ids.size()); for (int s : ids) { auto it3 = nx.find({x,y,s}); if (it3 != nx.end()) dn.push_back({s, it3->second}); } if ((long long)e <= c) { if (dn.empty()) { auto p = fall(x, y); x = p.first; y = p.second; continue; } break; } e -= (int)c; if (dn.empty()) { auto p = fall(x, y); x = p.first; y = p.second; continue; } int bx = 0, by = -1; for (auto &qq : dn) { int xx = qq.second.first; int yy = qq.second.second; if (yy > by) { by = yy; bx = xx; } } if (e == 0) break; e--; x = bx; y = by; } } cout << x << " " << y; return 0; } Gravity Code ✅✅ Share our channel Fast https://t.me/coding_are

Uno Code #include <bits/stdc++.h> using namespace std; int findp(int x, vector<int>& p) { return p[x] == x ? x : p[x] = findp(p[x], p); } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int n; cin >> n; vector<string> names(n); for (int i = 0; i < n; i++) cin >> names[i]; vector<int> skill(n); for (int i = 0; i < n; i++) cin >> skill[i]; unordered_map<string, int> id; for (int i = 0; i < n; i++) id[names[i]] = i; int f; cin >> f; vector<int> p(n); iota(p.begin(), p.end(), 0); for (int i = 0; i < f; i++) { string a, b; cin >> a >> b; int x = findp(id[a], p), y = findp(id[b], p); if (x != y) p[y] = x; } unordered_map<int, vector<int>> clusters; for (int i = 0; i < n; i++) clusters[findp(i, p)].push_back(i); vector<vector<int>> group; vector<int> groupSkill, groupSize; for (auto& [r, v] : clusters) { group.push_back(v); int s = 0; for (int x : v) s += skill[x]; groupSkill.push_back(s); groupSize.push_back(v.size()); } int r; cin >> r; int m = group.size(); vector<vector<int>> rival(m); unordered_map<int, int> idx; { int i = 0; for (auto& [root, _] : clusters) idx[root] = i++; } for (int i = 0; i < r; i++) { string a, b; cin >> a >> b; int ga = idx[findp(id[a], p)]; int gb = idx[findp(id[b], p)]; if (ga != gb) { rival[ga].push_back(gb); rival[gb].push_back(ga); } } int limit; cin >> limit; int best = 0; int total = 1 << m; for (int mask = 0; mask < total; mask++) { int sumSkill = 0, count = 0; bool valid = true; for (int i = 0; i < m && valid; i++) { if (mask & (1 << i)) { for (int x : rival[i]) { if (mask & (1 << x)) { valid = false; break; } } sumSkill += groupSkill[i]; if (sumSkill > limit) { valid = false; break; } count += groupSize[i]; } } if (valid) best = max(best, count); } cout << best; return 0; } Uno Code ✅ ✅ All Passed 💯💯✅✅ Share our channel Fast https://t.me/coding_are

C++ Cable Wrap TCS CodeVita Zone 2 #include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int N, M; cin >> N >> M; vector<string> grid(N); for (int i = 0; i < N; i++) { grid[i].resize(M); for (int j = 0; j < M; j++) { cin >> grid[i][j]; } } vector<int> horizontal_rods, vertical_rods; for (int i = 0; i < N; i++) { if (all_of(grid[i].begin(), grid[i].end(), [](char c){ return c != '.'; })) horizontal_rods.push_back(i); } for (int j = 0; j < M; j++) { bool full = true; for (int i = 0; i < N; i++) if (grid[i][j] == '.') full = false; if (full) vertical_rods.push_back(j); } vector<vector<bool>> is_cross(N, vector<bool>(M, false)); for (int c : vertical_rods) { for (int i = 0; i < N; i++) { int left = c - 1, right = c + 1; if (left >= 0 && right < M && grid[i][left] == 'C' && grid[i][right] == 'C') is_cross[i][c] = true; } } for (int r : horizontal_rods) { for (int j = 0; j < M; j++) { int up = r - 1, down = r + 1; if (up >= 0 && down < N && grid[up][j] == 'C' && grid[down][j] == 'C') is_cross[r][j] = true; } } vector<vector<bool>> cable(N, vector<bool>(M, false)); for (int i = 0; i < N; i++) for (int j = 0; j < M; j++) if (grid[i][j] == 'C' || is_cross[i][j]) cable[i][j] = true; vector<vector<int>> adj(N * M); int di[4] = {-1, 0, 1, 0}; int dj[4] = {0, 1, 0, -1}; for (int i = 0; i < N; i++) { for (int j = 0; j < M; j++) { if (!cable[i][j]) continue; int id = i * M + j; for (int d = 0; d < 4; d++) { int ni = i + di[d], nj = j + dj[d]; if (ni >= 0 && ni < N && nj >= 0 && nj < M && cable[ni][nj]) adj[id].push_back(ni * M + nj); } } } int start = -1; for (int i = 0; i < N && start == -1; i++) for (int j = 0; j < M; j++) if (cable[i][j] && adj[i * M + j].size() == 1) { start = i * M + j; break; } vector<bool> visited(N * M, false); vector<int> sum_h(N, 0), sum_v(M, 0); int curr = start, prevv = -1; visited[curr] = true; while (true) { int cr = curr / M, cc = curr % M; int nextt = -1; for (int nb : adj[curr]) if (nb != prevv && !visited[nb]) { nextt = nb; break; } if (is_cross[cr][cc] && prevv != -1) { int pr = prevv / M, pc = prevv % M; int sign = (grid[cr][cc] == 'C') ? 1 : -1; if (pr == cr) sum_v[cc] += ((pc < cc) ? 1 : -1) * sign; else sum_h[cr] += ((pr < cr) ? 1 : -1) * sign; } if (nextt == -1) break; prevv = curr; curr = nextt; visited[curr] = true; } long long answer = 0; for (int r : horizontal_rods) answer += abs(sum_h[r]) / 2; for (int c : vertical_rods) answer += abs(sum_v[c]) / 2; cout << answer; return 0; } C++ Cable Wrap TCS CodeVita Zone 2 https://t.me/coding_are

Ubs exam successfully completed by remote access 👍👍👍👍👍👍👍👍 1/1 code done with all tests cases passed ✅✅✅✅ 27/27 mce do
+2
Ubs exam successfully completed by remote access 👍👍👍👍👍👍👍👍 1/1 code done with all tests cases passed ✅✅✅✅ 27/27 mce done with 💯 correct answer ✅ Contact for placement exam @srksvk

Accenture on campus exam successfully completed by remote access 👍👍👍👍 90/90 MCQ done ✅ and first round CLEARED 🎉 🥳 🥳 �
+2
Accenture on campus exam successfully completed by remote access 👍👍👍👍 90/90 MCQ done ✅ and first round CLEARED 🎉 🥳 🥳 🥳 🥳 🥳 🥳 🥳 🥳 2/2 code done with all tests case's passed 🔥 🥳 Contact for placement exam @srksvk

Accenture on campus Accolite IBM Amazon Capgemini Any off campus or on campus exam  help available Contact fast and book your slots Contact @srksvk 200% suree clearance grauntee 🔥   Remote access available All company interview help available with sure clearance gaurntee

Capgemini exam CLEARED 🎉🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳 Congratulations bro 🎉🎉🎉🎉🎉🎉🎉 Helped proof 👇👇👇 Co
+1
Capgemini exam CLEARED 🎉🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳 Congratulations bro 🎉🎉🎉🎉🎉🎉🎉 Helped proof 👇👇👇 Contact for placement exam @srksvk

Eurofin exam successfully completed by remote access 👍👍👍👍👍👍👍 2/2 code done with all tests cases passed✅ 42/42 MCQ done
+5
Eurofin exam successfully completed by remote access 👍👍👍👍👍👍👍 2/2 code done with all tests cases passed✅ 42/42 MCQ done with 💯 correct answer ✅✅ Contact for placement exam @srksvk

Black and green exam successfully completed by remote access 👍👍👍👍👍 196/196 question done with 💯 correct answer 🔥 Conta
+1
Black and green exam successfully completed by remote access 👍👍👍👍👍 196/196 question done with 💯 correct answer 🔥 Contact for placement exam @srksvk

Visa exam successfully completed by remote access 👍👍👍👍👍👍👍👍 4/4 code done with all tests cases passed ✅✅ Contact for p
+4
Visa exam successfully completed by remote access 👍👍👍👍👍👍👍👍 4/4 code done with all tests cases passed ✅✅ Contact for placement exam @srksvk 200% suree clearance gaurntee

Visa exam successfully completed by remote access 👍👍👍👍👍👍👍👍 4/4 code done with all tests cases passed ✅✅ Contact for p
+5
Visa exam successfully completed by remote access 👍👍👍👍👍👍👍👍 4/4 code done with all tests cases passed ✅✅ Contact for placement exam @srksvk 200% suree clearance gaurntee ✅

Ibm exam successfully completed by remote access 👍👍👍👍👍👍👍👍 2/2 code done with all tests case's passed 🔥🔥 Contact for
+1
Ibm exam successfully completed by remote access 👍👍👍👍👍👍👍👍 2/2 code done with all tests case's passed 🔥🔥 Contact for placement exam @srksvk

Icici bank exam cleared 🔥🥳🎉🎉🎉🎉🎉 After one year got result 🔥🔥🔥🔥🔥🔥 Contact for placement exam @srksvk
+1
Icici bank exam cleared 🔥🥳🎉🎉🎉🎉🎉 After one year got result 🔥🔥🔥🔥🔥🔥 Contact for placement exam @srksvk

Infosys interview help successfully completed by remote access 👍👍👍👍👍👍👍👍👍👍👍 All answers provided on time with 💯 co
+2
Infosys interview help successfully completed by remote access 👍👍👍👍👍👍👍👍👍👍👍 All answers provided on time with 💯 correct answer 🔥🥳🥳🥳🥳 Contact for placement exam @srksvk

Hiii guy's now I am available So contact me for exam help and interview help Contact @srksvk 200% suree clearance gaurntee ✅