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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

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📈 Analytical overview of Telegram channel MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

Channel MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) in the English language segment is an active participant. Currently, the community unites 13 242 subscribers, ranking 15 362 in the Education category and 32 092 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 13 242 subscribers.

According to the latest data from 18 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -138 over the last 30 days and by -2 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 2.93%. Within the first 24 hours after publication, content typically collects 1.11% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 388 views. Within the first day, a publication typically gains 147 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
  • Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

Thanks to the high frequency of updates (latest data received on 19 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

13 242
Subscribers
-224 hours
-457 days
-13830 days
Posts Archive
#include <bits/stdc++.h> bool isInside(int x, int y, const vector<pair<int, int>>& verts) { int cross = 0, N = verts.size(); for(int i = 0; i < N; ++i){ int x1 = verts[i].first, y1 = verts[i].second; int x2 = verts[(i+1)%N].first, y2 = verts[(i+1)%N].second; if(((y1 <= y) && (y2 > y)) || ((y2 <= y) && (y1 > y))){ double ix = x1 + (double)(y - y1) * (x2 - x1) / (y2 - y1); if(ix > x) cross++; } } return (cross % 2) != 0; } int main(){ ios::sync_with_stdio(false); cin.tie(0); int N; cin >> N; vector<pair<int, int>> verts(N); int minX = INT32_MAX, maxX = INT32_MIN, minY = INT32_MAX, maxY = INT32_MIN; for(auto &p : verts){ cin >> p.first >> p.second; minX = min(minX, p.first); maxX = max(maxX, p.first); minY = min(minY, p.second); maxY = max(maxY, p.second); } int M; cin >> M; int w = maxX - minX + 1, h = maxY - minY + 1; vector<vector<int>> grid(h, vector<int>(w, 0)); for(int y = minY; y < maxY; ++y){ for(int x = minX; x < maxX; ++x){ if(isInside(x + 0.5, y + 0.5, verts)){ grid[y - minY][x - minX] = 1; } } } vector<pair<int, int>> cells; for(int i=0;i<h;i++) { for(int j=0;j<w;j++) { if(grid[i][j]==1){ cells.emplace_back(i,j); } } } sort(cells.begin(), cells.end()); int minPresses = INT32_MAX; function<void(int, vector<vector<int>>&, int)> backtrack = & { if(presses >= minPresses) return; while(idx < cells.size() && curGrid[cells[idx].first][cells[idx].second]==0){ idx++; } if(idx == cells.size()){ minPresses = min(minPresses, presses); return; } int y = cells[idx].first, x = cells[idx].second; bool canPlace = true; for(int dy=0; dy<M && canPlace; dy++){ for(int dx=0; dx<M && canPlace; dx++){ int ny = y + dy, nx = x + dx; if(ny >= h nx >= w curGrid[ny][nx]==0) canPlace = false; } } if(canPlace){ vector<vector<int>> newGrid = curGrid; for(int dy=0; dy<M; dy++){ for(int dx=0; dx<M; dx++){ int ny = y + dy, nx = x + dx; if(ny < h && nx < w) newGrid[ny][nx] = 0; } } backtrack(idx +1, newGrid, presses +1); } }; backtrack(0, grid, 0); cout << minPresses; } COUNT PRESS

Plague #include <iostream> #include <vector> #include <queue> #include <set> #include <tuple> using namespace std; int countInfectedNeighbors(const vector<vector<int>>& grid, int x, int y) {     int n = grid.size();     int infected = 0;     for (int dx = -1; dx <= 1; dx++) {         for (int dy = -1; dy <= 1; dy++) {             if (dx == 0 && dy == 0) continue;             int nx = x + dx, ny = y + dy;             if (nx >= 0 && nx < n && ny >= 0 && ny < n && grid[nx][ny] == 1) {                 infected++;             }         }     }     return infected; } vector<vector<int>> simulatePlague(const vector<vector<int>>& grid) {     int n = grid.size();     vector<vector<int>> nextGrid = grid;         for (int x = 0; x < n; x++) {         for (int y = 0; y < n; y++) {             int infected = countInfectedNeighbors(grid, x, y);                         if (grid[x][y] == 0 && infected == 3) {                 nextGrid[x][y] = 1;             } else if (grid[x][y] == 1) {                 if (infected < 2 || infected > 3) {                     nextGrid[x][y] = 0;                 }             }         }     }         return nextGrid; } int solve(int n, vector<vector<char>>& initialGrid) {     vector<vector<int>> grid(n, vector<int>(n));     int startx = -1, starty = -1, destx = -1, desty = -1;         for (int x = 0; x < n; x++) {         for (int y = 0; y < n; y++) {             grid[x][y] = (initialGrid[x][y] == '1') ? 1 : 0;                         if (initialGrid[x][y] == 's') {                 startx = x;                 starty = y;                 grid[x][y] = 0;             }             if (initialGrid[x][y] == 'd') {                 destx = x;                 desty = y;                 grid[x][y] = 0;             }         }     }         queue<tuple<int, int, vector<vector<int>>, int>> q;     set<tuple<int, int, vector<vector<int>>>> visited;         q.push({startx, starty, grid, 0});         while (!q.empty()) {         auto [x, y, current_grid, days] = q.front();         q.pop();                 if (x == destx && y == desty) {             return days;         }                 auto state_key = make_tuple(x, y, current_grid);         if (visited.count(state_key)) continue;         visited.insert(state_key);                 vector<vector<int>> next_grid = simulatePlague(current_grid);                 vector<pair<int, int>> moves = {{0,0}, {-1,0}, {1,0}, {0,-1}, {0,1}};         for (auto [dx, dy] : moves) {             int nx = x + dx, ny = y + dy;                         if (nx >= 0 && nx < n && ny >= 0 && ny < n && next_grid[nx][ny] == 0) {                 q.push({nx, ny, next_grid, days + 1});             }         }     }         return -1; } int main() {     int n;     cin >> n;         vector<vector<char>> grid(n, vector<char>(n));     for (int i = 0; i < n; i++) {         for (int j = 0; j < n; j++) {             cin >> grid[i][j];         }     }         cout << solve(n, grid)+1;     return 0; } Plague 2050

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