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MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 Telegram 频道 MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer 的分析概览

频道 MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 13 242 名订阅者,在 教育 类别中位列第 15 362,并在 印度 地区排名第 32 092

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 13 242 名订阅者。

根据 18 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -138,过去 24 小时变化为 -2,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 2.93%。内容发布后 24 小时内通常能获得 1.11% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 388 次浏览,首日通常累积 147 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 2
  • 主题关注点: 内容集中在 placement, gaurntee, suree, capgemini, infosy 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

凭借高频更新(最新数据采集于 19 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

13 242
订阅者
-224 小时
-457
-13830
帖子存档
#include <bits/stdc++.h> bool isInside(int x, int y, const vector<pair<int, int>>& verts) { int cross = 0, N = verts.size(); for(int i = 0; i < N; ++i){ int x1 = verts[i].first, y1 = verts[i].second; int x2 = verts[(i+1)%N].first, y2 = verts[(i+1)%N].second; if(((y1 <= y) && (y2 > y)) || ((y2 <= y) && (y1 > y))){ double ix = x1 + (double)(y - y1) * (x2 - x1) / (y2 - y1); if(ix > x) cross++; } } return (cross % 2) != 0; } int main(){ ios::sync_with_stdio(false); cin.tie(0); int N; cin >> N; vector<pair<int, int>> verts(N); int minX = INT32_MAX, maxX = INT32_MIN, minY = INT32_MAX, maxY = INT32_MIN; for(auto &p : verts){ cin >> p.first >> p.second; minX = min(minX, p.first); maxX = max(maxX, p.first); minY = min(minY, p.second); maxY = max(maxY, p.second); } int M; cin >> M; int w = maxX - minX + 1, h = maxY - minY + 1; vector<vector<int>> grid(h, vector<int>(w, 0)); for(int y = minY; y < maxY; ++y){ for(int x = minX; x < maxX; ++x){ if(isInside(x + 0.5, y + 0.5, verts)){ grid[y - minY][x - minX] = 1; } } } vector<pair<int, int>> cells; for(int i=0;i<h;i++) { for(int j=0;j<w;j++) { if(grid[i][j]==1){ cells.emplace_back(i,j); } } } sort(cells.begin(), cells.end()); int minPresses = INT32_MAX; function<void(int, vector<vector<int>>&, int)> backtrack = & { if(presses >= minPresses) return; while(idx < cells.size() && curGrid[cells[idx].first][cells[idx].second]==0){ idx++; } if(idx == cells.size()){ minPresses = min(minPresses, presses); return; } int y = cells[idx].first, x = cells[idx].second; bool canPlace = true; for(int dy=0; dy<M && canPlace; dy++){ for(int dx=0; dx<M && canPlace; dx++){ int ny = y + dy, nx = x + dx; if(ny >= h nx >= w curGrid[ny][nx]==0) canPlace = false; } } if(canPlace){ vector<vector<int>> newGrid = curGrid; for(int dy=0; dy<M; dy++){ for(int dx=0; dx<M; dx++){ int ny = y + dy, nx = x + dx; if(ny < h && nx < w) newGrid[ny][nx] = 0; } } backtrack(idx +1, newGrid, presses +1); } }; backtrack(0, grid, 0); cout << minPresses; } COUNT PRESS

Plague #include <iostream> #include <vector> #include <queue> #include <set> #include <tuple> using namespace std; int countInfectedNeighbors(const vector<vector<int>>& grid, int x, int y) {     int n = grid.size();     int infected = 0;     for (int dx = -1; dx <= 1; dx++) {         for (int dy = -1; dy <= 1; dy++) {             if (dx == 0 && dy == 0) continue;             int nx = x + dx, ny = y + dy;             if (nx >= 0 && nx < n && ny >= 0 && ny < n && grid[nx][ny] == 1) {                 infected++;             }         }     }     return infected; } vector<vector<int>> simulatePlague(const vector<vector<int>>& grid) {     int n = grid.size();     vector<vector<int>> nextGrid = grid;         for (int x = 0; x < n; x++) {         for (int y = 0; y < n; y++) {             int infected = countInfectedNeighbors(grid, x, y);                         if (grid[x][y] == 0 && infected == 3) {                 nextGrid[x][y] = 1;             } else if (grid[x][y] == 1) {                 if (infected < 2 || infected > 3) {                     nextGrid[x][y] = 0;                 }             }         }     }         return nextGrid; } int solve(int n, vector<vector<char>>& initialGrid) {     vector<vector<int>> grid(n, vector<int>(n));     int startx = -1, starty = -1, destx = -1, desty = -1;         for (int x = 0; x < n; x++) {         for (int y = 0; y < n; y++) {             grid[x][y] = (initialGrid[x][y] == '1') ? 1 : 0;                         if (initialGrid[x][y] == 's') {                 startx = x;                 starty = y;                 grid[x][y] = 0;             }             if (initialGrid[x][y] == 'd') {                 destx = x;                 desty = y;                 grid[x][y] = 0;             }         }     }         queue<tuple<int, int, vector<vector<int>>, int>> q;     set<tuple<int, int, vector<vector<int>>>> visited;         q.push({startx, starty, grid, 0});         while (!q.empty()) {         auto [x, y, current_grid, days] = q.front();         q.pop();                 if (x == destx && y == desty) {             return days;         }                 auto state_key = make_tuple(x, y, current_grid);         if (visited.count(state_key)) continue;         visited.insert(state_key);                 vector<vector<int>> next_grid = simulatePlague(current_grid);                 vector<pair<int, int>> moves = {{0,0}, {-1,0}, {1,0}, {0,-1}, {0,1}};         for (auto [dx, dy] : moves) {             int nx = x + dx, ny = y + dy;                         if (nx >= 0 && nx < n && ny >= 0 && ny < n && next_grid[nx][ny] == 0) {                 q.push({nx, ny, next_grid, days + 1});             }         }     }         return -1; } int main() {     int n;     cin >> n;         vector<vector<char>> grid(n, vector<char>(n));     for (int i = 0; i < n; i++) {         for (int j = 0; j < n; j++) {             cin >> grid[i][j];         }     }         cout << solve(n, grid)+1;     return 0; } Plague 2050

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