Available now! Telegram Research 2025 β the year's key insights 
ACCENTURE EXAM HELP ! CISCO EXAM !
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π₯Guys plz Stop fearing for daily exams π π¨βπ» @srksvk is here to help you all at lowest cost possible.πͺ π β Our Only Aim Is To Let Get Placed To You In A Reputed Company π₯Effort from our side = π― π±Main Channel: @coding_are π±Tel I'd : @srksvk
Show moreπ Analytical overview of Telegram channel ACCENTURE EXAM HELP ! CISCO EXAM !
Channel ACCENTURE EXAM HELP ! CISCO EXAM ! (@coding_are) in the English language segment is an active participant. Currently, the community unites 13 208 subscribers, ranking 15 294 in the Education category and 31 490 in the India region.
π Audience metrics and dynamics
Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 13 208 subscribers.
According to the latest data from 30 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -144 over the last 30 days and by 6 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 3.08%. Within the first 24 hours after publication, content typically collects 1.29% reactions from the total number of subscribers.
- Post reach: On average, each post receives 407 views. Within the first day, a publication typically gains 170 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
- Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.
π Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
βπ₯Guys plz Stop fearing for daily exams π
π¨βπ» @srksvk is here to help you all at lowest cost possible.πͺ
π β Our Only Aim Is To Let Get Placed To You In A Reputed Company
π₯Effort from our side = π―
π±Main Channel: @coding_are
π±Tel I'd : @srks...β
Thanks to the high frequency of updates (latest data received on 01 July, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
13 208
Subscribers
+624 hours
-127 days
-14430 days
Posts Archive
def mirror_reflection(digits, side):
images = {
'0': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image1.png',
'1': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image2.png',
'2': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image3.png',
'3': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image4.png',
'4': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image5.png',
'5': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image6.png',
'6': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image7.png',
'7': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image8.png',
'8': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image9.png',
'9': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image0.png',
}
result = []
for d, s in zip(digits, side):
if s == 'L':
result.append(images[d])
else:
# For U, D, R, and S, print the seven segment display
result.append(d)
return ''.join(result)
# Input parsing
digits = input().strip()
side = input().strip()
# Output
print(mirror_reflection(digits, side))
Mirror reflection code .... pythonβ
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No one sharing group everyone
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import numpy as np
def find_widest_valley(n, A, B):
def surface_equation(x):
return sum(np.sin(a*x + b) for a, b in zip(A, B))
def find_local_maxima():
maxima = []
for i in range(1, n-1):
if surface_equation(i-1) < surface_equation(i) > surface_equation(i+1):
maxima.append(i)
return maxima
def find_valley_width(left, right):
return right - left
maxima = find_local_maxima()
widest_valley_width = 0
widest_valley_index = 0
for i in range(len(maxima)-1):
left_maxima = maxima[i]
right_maxima = maxima[i+1]
current_valley_width = find_valley_width(left_maxima, right_maxima)
if current_valley_width > widest_valley_width:
widest_valley_width = current_valley_width
widest_valley_index = left_maxima + 1
return widest_valley_index
# Input parsing
n = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
# Output
print(find_widest_valley(n, A, B))
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@codeing_area
def convert(expression):
stack = []
tokens = expression.split()
for token in reversed(tokens):
if is_operand(token):
stack.append(int(token))
elif is_operator(token):
if len(stack) < 2:
return float('-inf')
operand2 = stack.pop()
operand1 = stack.pop()
if token == "+":
stack.append(operand1 + operand2)
elif token == "-":
stack.append(operand1 - operand2)
elif token == "*":
stack.append(operand1 * operand2)
elif token == "/":
stack.append(operand1 / operand2)
elif token == "^":
stack.append(operand1 ** operand2)
elif token == "%":
stack.append(operand1 % operand2)
if len(stack) != 1:
return float('-inf')
return stack.pop()
def is_operand(token):
return token.lstrip('-').isdigit()
def is_operator(token):
return token in {"+", "-", "*", "/", "^", "%"}
def main():
prefix = input()
word_map = {
"zero": "0", "one": "1", "two": "2", "three": "3", "four": "4",
"five": "5", "six": "6", "seven": "7", "eight": "8", "nine": "9",
"mul": "*", "add": "+", "sub": "-", "div": "/", "rem": "%", "pow": "^"
}
words = prefix.split()
real_prefix = ""
for word in words:
if word in word_map:
real_prefix += word_map[word] + " "
continue
small_words = word.split("c")
for s in small_words:
if s:
if s not in word_map:
print("expression evaluation stopped invalid words present")
return
real_prefix += word_map[s]
real_prefix += " "
infix = convert(real_prefix)
if infix == float('-inf'):
print("expression is not complete or invalid")
else:
print(int(infix))
if name == "main":
main()
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#include <iostream>
#include <vector>
using namespace std;
int main() {
int n;
cin >> n;
vector<tuple<int, int, int>> stocks;
for (int i = 0; i < n; ++i) {
int a, b, c;
cin >> a >> b >> c;
stocks.push_back(make_tuple(a, b, c));
}
int m;
cin >> m;
int real = 0;
int unreal = 0;
vector<vector<int>> prices;
for (int i = 0; i < n; ++i) {
vector<int> arr(m);
for (int j = 0; j < m; ++j) {
cin >> arr[j];
}
prices.push_back(arr);
}
int day;
cin >> day;
for (int i = 0; i < n; ++i) {
int a, b, c;
tie(a, b, c) = stocks[i];
if (b > day) {
continue;
} else if (c > day || !c) {
unreal += a * (prices[i][day - 1] - prices[i][b - 1]);
} else {
real += a * (prices[i][c - 1] - prices[i][b - 1]);
}
}
cout << real << endl;
cout << unreal << endl;
return 0;
}
Roi code fully passsd β
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def toggle(num):
result = ""
for bit in num:
if bit == "0":
result += "1"
else:
result += "0"
return result
def get_max_sum(arr, k):
max_val = max(arr)
max_index = arr.index(max_val)
left = max(0, max_index-k)
right = min(len(arr)-1, max_index+k)
selected = arr[left:max_index+1] + arr[max_index:right+1]
arr = [x for x in arr if x not in selected]
return sum(selected), arr
# Input
arr = list(map(int, input().split()))
a1, b1 = input().split()
a2, b2 = input().split()
k = int(input())
sum1, sum2 = 0, 0
while arr:
s1, arr = get_max_sum(arr, k)
sum1 += s1
if not arr:
break
s2, arr = get_max_sum(arr, k)
sum2 += s2
if sum1 > sum2:
a1 = toggle(a1)
b2 = toggle(b2)
else:
a2 = toggle(a2)
b1 = toggle(b1)
xor1 = int(a1, 2) ^ int(b1, 2)
xor2 = int(a2, 2) ^ int(b2, 2)
if xor1 > xor2:
print("Rahul",end="")
elif xor2 > xor1:
print("Rupesh",end="")
else:
print("both",end="")
Who is Lucky
def hamming_distance(str1, str2):
return sum(c1 != c2 for c1, c2 in zip(str1, str2))
def minimize_cost_and_print_distance(binary_string, a, b):
# Count occurrences of "01" and "10"
count_01 = binary_string.count("01")
count_10 = binary_string.count("10")
# Calculate costs
cost_01 = count_01 * a
cost_10 = count_10 * b
# Determine rearranged string for minimum cost
if cost_01 < cost_10:
rearranged_string = "01" * count_01 + "0" * (len(binary_string) - 2 * count_01)
else:
rearranged_string = "10" * count_10 + "1" * (len(binary_string) - 2 * count_10)
# Calculate and print hamming distance
distance = hamming_distance(binary_string, rearranged_string)
print(distance)
# Input reading and processing
T = int(input("Enter the number of test cases: "))
for _ in range(T):
binary_string = input("Enter the binary string: ")
a, b = map(int, input("Enter A and B separated by space: ").split())
minimize_cost_and_print_distance(binary_string, a, b)
Hamming distance
Share @codeing_area
Tcs code vitaaa passed successfully β
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Share everyone i will post soon
Share our channel One more code soon
Need your support guys
Sitting from last 3 hours to share Codes in free
Share it
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Hlo everyone share group only β
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ROI
100% Working β
Python
TCS Codevita
@codeing_area
n = int(input())
stocks = []
for _ in range(n):
a, b, c = map(int, input().split())
stocks.append((a, b, c))
m = int(input())
real = 0
unreal = 0
placementlelo = []
for i in range(n):
arr = [int(i) for i in input().split()]
placementlelo.append(arr)
day = int(input())
for i in range(n):
a, b, c = stocks[i]
if b > day: continue
elif c > day or not c: unreal += a * (placementlelo[i][day - 1] - placementlelo[i][b - 1])
else: real += a * (placementlelo[i][c - 1] - placementlelo[i][b - 1])
print(real)
print(unreal)
ROI
100% Working β
Python
TCS Codevita
@codeing_area
def toggle(num):
result = ""
for bit in num:
if bit == "0":
result += "1"
else:
result += "0"
return result
def get_max_sum(arr, k):
max_val = max(arr)
max_index = arr.index(max_val)
left = max(0, max_index-k)
right = min(len(arr)-1, max_index+k)
selected = arr[left:max_index+1] + arr[max_index:right+1]
arr = [x for x in arr if x not in selected]
return sum(selected), arr
# Input
arr = list(map(int, input().split()))
a1, b1 = input().split()
a2, b2 = input().split()
k = int(input())
sum1, sum2 = 0, 0
while arr:
s1, arr = get_max_sum(arr, k)
sum1 += s1
if not arr:
break
s2, arr = get_max_sum(arr, k)
sum2 += s2
if sum1 > sum2:
a1 = toggle(a1)
b2 = toggle(b2)
else:
a2 = toggle(a2)
b1 = toggle(b1)
xor1 = int(a1, 2) ^ int(b1, 2)
xor2 = int(a2, 2) ^ int(b2, 2)
if xor1 > xor2:
print("Rahul",end="")
elif xor2 > xor1:
print("Rupesh",end="")
else:
print("both",end="")
Who is Lucky
Pasedd β
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https://t.me/ibmsolution
