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ACCENTURE EXAM HELP ! CISCO EXAM !

ACCENTURE EXAM HELP ! CISCO EXAM !

前往频道在 Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

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📈 Telegram 频道 ACCENTURE EXAM HELP ! CISCO EXAM ! 的分析概览

频道 ACCENTURE EXAM HELP ! CISCO EXAM ! (@coding_are) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 13 208 名订阅者,在 教育 类别中位列第 15 294,并在 印度 地区排名第 31 490

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 13 208 名订阅者。

根据 30 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -144,过去 24 小时变化为 6,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 3.08%。内容发布后 24 小时内通常能获得 1.29% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 407 次浏览,首日通常累积 170 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 2
  • 主题关注点: 内容集中在 placement, gaurntee, suree, capgemini, infosy 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

凭借高频更新(最新数据采集于 01 七月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

13 208
订阅者
+624 小时
-127
-14430
帖子存档
def mirror_reflection(digits, side): images = { '0': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image1.png', '1': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image2.png', '2': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image3.png', '3': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image4.png', '4': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image5.png', '5': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image6.png', '6': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image7.png', '7': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image8.png', '8': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image9.png', '9': 'com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@a7e2d9d:image0.png', } result = [] for d, s in zip(digits, side): if s == 'L': result.append(images[d]) else: # For U, D, R, and S, print the seven segment display result.append(d) return ''.join(result) # Input parsing digits = input().strip() side = input().strip() # Output print(mirror_reflection(digits, side)) Mirror reflection code .... python✅✅✅✅ Full passes ✅✅✅

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import numpy as np def find_widest_valley(n, A, B): def surface_equation(x): return sum(np.sin(a*x + b) for a, b in zip(A, B)) def find_local_maxima(): maxima = [] for i in range(1, n-1): if surface_equation(i-1) < surface_equation(i) > surface_equation(i+1): maxima.append(i) return maxima def find_valley_width(left, right): return right - left maxima = find_local_maxima() widest_valley_width = 0 widest_valley_index = 0 for i in range(len(maxima)-1): left_maxima = maxima[i] right_maxima = maxima[i+1] current_valley_width = find_valley_width(left_maxima, right_maxima) if current_valley_width > widest_valley_width: widest_valley_width = current_valley_width widest_valley_index = left_maxima + 1 return widest_valley_index # Input parsing n = int(input()) A = list(map(int, input().split())) B = list(map(int, input().split())) # Output print(find_widest_valley(n, A, B))

Sending answer

I am waittingg everyone ✅✅✅✅ Please do fast 5k ✅✅✅ @codeing_area Code are ready everyone ✅✅

I am waittingg everyone ✅✅✅✅ Please do fast 5k ✅✅✅ @codeing_area

Now share everyone ✅✅✅✅✅✅ @codeing_area

def convert(expression): stack = [] tokens = expression.split() for token in reversed(tokens): if is_operand(token): stack.append(int(token)) elif is_operator(token): if len(stack) < 2: return float('-inf') operand2 = stack.pop() operand1 = stack.pop() if token == "+": stack.append(operand1 + operand2) elif token == "-": stack.append(operand1 - operand2) elif token == "*": stack.append(operand1 * operand2) elif token == "/": stack.append(operand1 / operand2) elif token == "^": stack.append(operand1 ** operand2) elif token == "%": stack.append(operand1 % operand2) if len(stack) != 1: return float('-inf') return stack.pop() def is_operand(token): return token.lstrip('-').isdigit() def is_operator(token): return token in {"+", "-", "*", "/", "^", "%"} def main(): prefix = input() word_map = { "zero": "0", "one": "1", "two": "2", "three": "3", "four": "4", "five": "5", "six": "6", "seven": "7", "eight": "8", "nine": "9", "mul": "*", "add": "+", "sub": "-", "div": "/", "rem": "%", "pow": "^" } words = prefix.split() real_prefix = "" for word in words: if word in word_map: real_prefix += word_map[word] + " " continue small_words = word.split("c") for s in small_words: if s: if s not in word_map: print("expression evaluation stopped invalid words present") return real_prefix += word_map[s] real_prefix += " " infix = convert(real_prefix) if infix == float('-inf'): print("expression is not complete or invalid") else: print(int(infix)) if name == "main": main() No more suffle✅✅✅✅✅(python All passsd ✅✅✅ Share everyone ✅✅✅

Please make it 5k fasttt everyone ✅✅✅ Then i will post all code....and fully correct ✅✅✅✅

Share fasttt everyone ✅✅✅✅✅ @codeing_area

#include <iostream> #include <vector> using namespace std; int main() { int n; cin >> n; vector<tuple<int, int, int>> stocks; for (int i = 0; i < n; ++i) { int a, b, c; cin >> a >> b >> c; stocks.push_back(make_tuple(a, b, c)); } int m; cin >> m; int real = 0; int unreal = 0; vector<vector<int>> prices; for (int i = 0; i < n; ++i) { vector<int> arr(m); for (int j = 0; j < m; ++j) { cin >> arr[j]; } prices.push_back(arr); } int day; cin >> day; for (int i = 0; i < n; ++i) { int a, b, c; tie(a, b, c) = stocks[i]; if (b > day) { continue; } else if (c > day || !c) { unreal += a * (prices[i][day - 1] - prices[i][b - 1]); } else { real += a * (prices[i][c - 1] - prices[i][b - 1]); } } cout << real << endl; cout << unreal << endl; return 0; } Roi code fully passsd ✅✅✅✅✅ Share @codeing_area

def toggle(num): result = "" for bit in num: if bit == "0": result += "1" else: result += "0" return result def get_max_sum(arr, k): max_val = max(arr) max_index = arr.index(max_val) left = max(0, max_index-k) right = min(len(arr)-1, max_index+k) selected = arr[left:max_index+1] + arr[max_index:right+1] arr = [x for x in arr if x not in selected] return sum(selected), arr # Input arr = list(map(int, input().split())) a1, b1 = input().split() a2, b2 = input().split() k = int(input()) sum1, sum2 = 0, 0 while arr: s1, arr = get_max_sum(arr, k) sum1 += s1 if not arr: break s2, arr = get_max_sum(arr, k) sum2 += s2 if sum1 > sum2: a1 = toggle(a1) b2 = toggle(b2) else: a2 = toggle(a2) b1 = toggle(b1) xor1 = int(a1, 2) ^ int(b1, 2) xor2 = int(a2, 2) ^ int(b2, 2) if xor1 > xor2: print("Rahul",end="") elif xor2 > xor1: print("Rupesh",end="") else: print("both",end="") Who is Lucky

def hamming_distance(str1, str2): return sum(c1 != c2 for c1, c2 in zip(str1, str2)) def minimize_cost_and_print_distance(binary_string, a, b): # Count occurrences of "01" and "10" count_01 = binary_string.count("01") count_10 = binary_string.count("10") # Calculate costs cost_01 = count_01 * a cost_10 = count_10 * b # Determine rearranged string for minimum cost if cost_01 < cost_10: rearranged_string = "01" * count_01 + "0" * (len(binary_string) - 2 * count_01) else: rearranged_string = "10" * count_10 + "1" * (len(binary_string) - 2 * count_10) # Calculate and print hamming distance distance = hamming_distance(binary_string, rearranged_string) print(distance) # Input reading and processing T = int(input("Enter the number of test cases: ")) for _ in range(T): binary_string = input("Enter the binary string: ") a, b = map(int, input("Enter A and B separated by space: ").split()) minimize_cost_and_print_distance(binary_string, a, b) Hamming distance Share @codeing_area

Tcs code vitaaa passed successfully ✅✅✅ Share everyone i will post soon
Tcs code vitaaa passed successfully ✅✅✅ Share everyone i will post soon

Share our channel One more code soon Need your support guys Sitting from last 3 hours to share Codes in free Share it @codeing_area

Hlo everyone share group only ✅✅✅ Share group --- @codeing_area

ROI 100% Working ✅ Python TCS Codevita @codeing_area n = int(input()) stocks = [] for _ in range(n): a, b, c = map(int, input().split()) stocks.append((a, b, c)) m = int(input()) real = 0 unreal = 0 placementlelo = [] for i in range(n): arr = [int(i) for i in input().split()] placementlelo.append(arr) day = int(input()) for i in range(n): a, b, c = stocks[i] if b > day: continue elif c > day or not c: unreal += a * (placementlelo[i][day - 1] - placementlelo[i][b - 1]) else: real += a * (placementlelo[i][c - 1] - placementlelo[i][b - 1]) print(real) print(unreal) ROI 100% Working ✅ Python TCS Codevita @codeing_area

def toggle(num): result = "" for bit in num: if bit == "0": result += "1" else: result += "0" return result def get_max_sum(arr, k): max_val = max(arr) max_index = arr.index(max_val) left = max(0, max_index-k) right = min(len(arr)-1, max_index+k) selected = arr[left:max_index+1] + arr[max_index:right+1] arr = [x for x in arr if x not in selected] return sum(selected), arr # Input arr = list(map(int, input().split())) a1, b1 = input().split() a2, b2 = input().split() k = int(input()) sum1, sum2 = 0, 0 while arr: s1, arr = get_max_sum(arr, k) sum1 += s1 if not arr: break s2, arr = get_max_sum(arr, k) sum2 += s2 if sum1 > sum2: a1 = toggle(a1) b2 = toggle(b2) else: a2 = toggle(a2) b1 = toggle(b1) xor1 = int(a1, 2) ^ int(b1, 2) xor2 = int(a2, 2) ^ int(b2, 2) if xor1 > xor2: print("Rahul",end="") elif xor2 > xor1: print("Rupesh",end="") else: print("both",end="") Who is Lucky

Pasedd ✅✅✅✅✅✅ Sahre only group everyone ✅✅✅🎉🎉🎉🎉
Pasedd ✅✅✅✅✅✅ Sahre only group everyone ✅✅✅🎉🎉🎉🎉

Join Fast will share One more code soon👇👇👇👇 https://t.me/ibmsolution