Accenture exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

India31 821 Education15 335...

📈 Analytical overview of Telegram channel Accenture exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

Channel Accenture exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) in the English language segment is an active participant. Currently, the community unites 13 218 subscribers, ranking 15 335 in the Education category and 31 821 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 13 218 subscribers.

According to the latest data from 22 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -155 over the last 30 days and by -11 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 2.68%. Within the first 24 hours after publication, content typically collects 0.95% reactions from the total number of subscribers.
Post reach: On average, each post receives 354 views. Within the first day, a publication typically gains 125 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 1.
Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Thanks to the high frequency of updates (latest data received on 23 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

13 218

Subscribers

-1124 hours

-407 days

-15530 days

354

Post views

~ 12524 hours

~ 15948 hours

2.68%

Engagement rate

~ 3

Posts per day

Ads index

beta

Posts Archive

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Infosys codes❤️ 1) Army invasion 2) Disturbuting books 3) Count subtree factors code 4) Task management Contact @srksvk

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Join here 👇👇👇👇👇👇👇👇👇 https://t.me/codeing_are https://t.me/codeing_are https://t.me/codeing_are https://t.me/codeing_are Shared Chanel and take code

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#include <iostream> #include <vector> #include <numeric> #define MOD 1000000007 using namespace std; long long mod_inv(long long x, long long mod) { long long result = 1; long long power = mod - 2; while (power) { if (power % 2) { result = result * x % mod; } x = x * x % mod; power /= 2; } return result; } vector<long long> factorial(int n, long long mod) { vector<long long> fact(n + 1, 1); for (int i = 2; i <= n; ++i) { fact[i] = fact[i - 1] * i % mod; } return fact; } long long binomial_coeff(int n, int k, const vector<long long>& fact, long long mod) { if (k > n || k < 0) { return 0; } return fact[n] * mod_inv(fact[k], mod) % mod * mod_inv(fact[n - k], mod) % mod; } long long count_ways(int N, int K, const vector<int>& A) { int sum_A = accumulate(A.begin(), A.end(), 0); int M = K - sum_A; vector<long long> fact = factorial(M + N - 1, MOD); return binomial_coeff(M + N - 1, N - 1, fact, MOD); } int main() { int N, K; cin >> N >> K; vector<int> A(N); for (int i = 0; i < N; ++i) { cin >> A[i]; } cout << count_ways(N, K, A) << endl; return 0; } DISTURBUTING BOOKS

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Change' variable

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#include<bits/stdc++.h> using namespace std; #define int long long int findMax(vector<int>& a, vector<int>& height, int n, int i, int h, vector<vector<int>>& dp) { if (i >= n) return 0; if (dp[i][h] != -1) return dp[i][h]; int vol = height[i] * a[i] * a[i]; int inc = 0; int exc = 0; if (vol > h) { inc = vol + findMax(a, height, n, i + 1, vol, dp); } exc = findMax(a, height, n, i + 1, h, dp); return dp[i][h] = max(inc, exc); } int32_t main() { int n; cin >> n; vector<int> a(n); for (int i = 0; i < n; i++) cin >> a[i]; vector<int> height(n); for (int i = 0; i < n; i++) cin >> height[i]; int maxVol = 0; for (int i = 0; i < n; i++) { maxVol = max(maxVol, height[i] * a[i] * a[i]); } // Using the maximum possible value of h to size the dp table vector<vector<int>> dp(n, vector<int>(maxVol + 1, -1)); int ans = findMax(a, height, n, 0, 0, dp); cout << ans << endl; return 0; } Volume of cylinder(c++ Share https://t.me/codeing_are https://t.me/codeing_are

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