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Accenture exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

Accenture exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

الذهاب إلى القناة على Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

إظهار المزيد

📈 نظرة تحليلية على قناة تيليجرام Accenture exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

تُعد قناة Accenture exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 13 218 مشتركاً، محتلاً المرتبة 15 335 في فئة التعليم والمرتبة 31 821 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 13 218 مشتركاً.

بحسب آخر البيانات بتاريخ 22 يونيو, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -155، وفي آخر 24 ساعة بمقدار -11، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 2.68‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 0.95‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 354 مشاهدة. وخلال اليوم الأول يجمع عادةً 125 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 1.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل placement, gaurntee, suree, capgemini, infosy.

📝 الوصف وسياسة المحتوى

يصف المؤلف القناة بأنها مساحة للتعبير عن الآراء الذاتية:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 23 يونيو, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التعليم.

13 218
المشتركون
-1124 ساعات
-407 أيام
-15530 أيام
أرشيف المشاركات
Infosys codes❤️ 1) Army invasion 2) Disturbuting books 3) Count subtree factors code 4) Task management Contact @srksvk
All test cases passed

#include <iostream> #include <vector> #include <numeric> #define MOD 1000000007 using namespace std; long long mod_inv(long long x, long long mod) { long long result = 1; long long power = mod - 2; while (power) { if (power % 2) { result = result * x % mod; } x = x * x % mod; power /= 2; } return result; } vector<long long> factorial(int n, long long mod) { vector<long long> fact(n + 1, 1); for (int i = 2; i <= n; ++i) { fact[i] = fact[i - 1] * i % mod; } return fact; } long long binomial_coeff(int n, int k, const vector<long long>& fact, long long mod) { if (k > n || k < 0) { return 0; } return fact[n] * mod_inv(fact[k], mod) % mod * mod_inv(fact[n - k], mod) % mod; } long long count_ways(int N, int K, const vector<int>& A) { int sum_A = accumulate(A.begin(), A.end(), 0); int M = K - sum_A; vector<long long> fact = factorial(M + N - 1, MOD); return binomial_coeff(M + N - 1, N - 1, fact, MOD); } int main() { int N, K; cin >> N >> K; vector<int> A(N); for (int i = 0; i < N; ++i) { cin >> A[i]; } cout << count_ways(N, K, A) << endl; return 0; } DISTURBUTING BOOKS

#include<bits/stdc++.h> using namespace std; #define int long long int findMax(vector<int>& a, vector<int>& height, int n, int i, int h, vector<vector<int>>& dp) {     if (i >= n) return 0;     if (dp[i][h] != -1) return dp[i][h];         int vol = height[i] * a[i] * a[i];     int inc = 0;     int exc = 0;         if (vol > h) {         inc = vol + findMax(a, height, n, i + 1, vol, dp);     }     exc = findMax(a, height, n, i + 1, h, dp);         return dp[i][h] = max(inc, exc); } int32_t main() {     int n;     cin >> n;     vector<int> a(n);     for (int i = 0; i < n; i++) cin >> a[i];     vector<int> height(n);     for (int i = 0; i < n; i++) cin >> height[i];         int maxVol = 0;     for (int i = 0; i < n; i++) {         maxVol = max(maxVol, height[i] * a[i] * a[i]);     }     // Using the maximum possible value of h to size the dp table     vector<vector<int>> dp(n, vector<int>(maxVol + 1, -1));     int ans = findMax(a, height, n, 0, 0, dp);     cout << ans << endl;     return 0; } Volume of cylinder(c++ Share https://t.me/codeing_are https://t.me/codeing_are

Don't send me questions personally...if I am done code then j will share...so please don't message me everyone's Only everyone share group ohk

📢 𝐇𝐞𝐲 𝐞𝐯𝐞𝐫𝐲𝐨𝐧𝐞! 𝐁𝐢𝐠 𝐧𝐞𝐰𝐬! 𝐎𝐧 𝐀𝐮𝐠𝐮𝐬𝐭 4𝐭𝐡, 𝐈'𝐥𝐥 𝐛𝐞 𝐨𝐟𝐟𝐞𝐫𝐢𝐧𝐠 𝐅𝐑𝐄𝐄 and Paid 𝐈𝐧𝐟𝐨𝐬𝐲𝐬 𝐜𝐨𝐝𝐢𝐧𝐠 𝐡𝐞𝐥𝐩 🆓🆓💻. Join here 👇👇👇👇👇👇👇👇👇 https://t.me/codeing_are https://t.me/codeing_are https://t.me/codeing_are https://t.me/codeing_are 𝐈'𝐥𝐥 𝐬𝐡𝐚𝐫𝐞 𝐚𝐥𝐥 𝐭𝐡𝐞 𝐜𝐨𝐝𝐞𝐬 𝐫𝐢𝐠𝐡𝐭 𝐡𝐞𝐫𝐞, 𝐬𝐨 𝐦𝐚𝐤𝐞 𝐬𝐮𝐫𝐞 𝐭𝐨 𝐭𝐞𝐥𝐥 𝐚𝐥𝐥 𝐲𝐨𝐮𝐫 𝐟𝐫𝐢𝐞𝐧𝐝𝐬! 🚀 🔄 𝐏𝐥𝐞𝐚𝐬𝐞 𝐬𝐡𝐚𝐫𝐞 𝐨𝐮𝐫 𝐜𝐡𝐚𝐧𝐧𝐞𝐥, 𝐚𝐧𝐝 𝐝𝐨𝐧'𝐭 𝐟𝐨𝐫𝐠𝐞𝐭 𝐭𝐨 𝐭𝐰𝐞𝐚𝐤 𝐭𝐡𝐞 𝐯𝐚𝐫𝐢𝐚𝐛𝐥𝐞 𝐧𝐚𝐦𝐞𝐬 𝐢𝐧 𝐭𝐡𝐞 𝐜𝐨𝐝𝐞𝐬 𝐭𝐨 𝐦𝐚𝐤𝐞 𝐭𝐡𝐞𝐦 𝐲𝐨𝐮𝐫 𝐨𝐰𝐧! 👨‍💻👩‍💻

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