Don't get caught by a cheater! Telemetrio finds and tags such channels 👉 If you want to see the tag, subscribe

ACCENTURE EXAM SOLUTIONS

Open in Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

India28 153Education14 642...

📈 Analytical overview of Telegram channel ACCENTURE EXAM SOLUTIONS

Channel ACCENTURE EXAM SOLUTIONS (@coding_are) in the English language segment is an active participant. Currently, the community unites 13 954 subscribers, ranking 14 642 in the Education category and 28 153 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 13 954 subscribers.

According to the latest data from 02 November, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -150 over the last 30 days and by -1 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 3.64%. Within the first 24 hours after publication, content typically collects 1.39% reactions from the total number of subscribers.
Post reach: On average, each post receives 508 views. Within the first day, a publication typically gains 194 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 2.
Thematic interests: Content is focused on key topics such as placement, gaurntee, suree, capgemini, infosy.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
“🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...”

Thanks to the high frequency of updates (latest data received on 03 November, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

13 954

Subscribers

-124 hours

-317 days

-15030 days

508

Post views

~ 19424 hours

~ 26748 hours

3.64%

Engagement rate

~ 3

Posts per day

Ads index

Posts Archive

13 954

We pray to God that you❤️ 😊 always be happy and😚 keep your family happy. And there will always be💥 happiness in your life.🥰 Happy diwali everyone.....❤️❤️🥰

13 954

Those who have TCS, COGNIZANT, HEXAWARE,TECH MAHINDRA,FEDEX,ZOHO, ACCENTURE OR ANY OTHER EXAM help available Scroll up and check past results 😃 Both Coding and Aptitude help available Contact @srksvkfor help 🙏 💯 Clearance and genuine help Note: it's paid help

13 954

SML EXAM DON Placements Help Available 👍👍 If you also want to crack your current placements Contact: @srksvk Book your slots ASAP Scroll above and check the work 💯 Clearence @https://t.me/rituyr Note: It's paid💶🤑 ✅Share✅Share✅Share ✅share✅

13 954

Placements Help Available 👍👍 If you also want to crack your current placements Contact: @srksvk Book your slots ASAP Scroll above and check the work 💯 Clearence @https://t.me/rituyr Note: It's paid💶🤑 ✅Share✅Share✅Share ✅share✅

13 954

🎯Hitachi off campus drive 🧑‍🎓Qualification : Freshers 💻 Role : Software Development Engineer 🧑‍🎓Eligibility : Bachelor's / Graduation / Equivalent 📌Apply : https://bit.ly/3giGjRA

13 954

IBM Campus Drive 2022 | For Associate Systems Engineer 🎖 Degree: BE, B Tech, ME, M Tech, MCA 🔰 Batch: 2018 To 2022 💰 CTC - ₹ 4.2 LPA* ⭕ Apply Link - https://bit.ly/3sktV

13 954

Array A length n code

13 954

C++

13 954

magic Number Code python 3 All test cases passed

13 954

#include <bits/stdc++.h> using namespace std; int count(string s) { int N, i, cnt = 0, ans = 0; N = s.length(); for (i = 0; i < N; i++) { if (s[i] == 'R') cnt++; if (s[i] == 'L') ans += cnt; } return ans; } int main() { string s = "RRLL"; cout << count(s) << endl; return 0; } C++

13 954

Share the group everyone

13 954

if (n > k && n > a) { printf("N is the Biggest number is %d", n); return n; } if (k > n && k > a) { printf("k is the Biggest number is %d", k); return k; } if (a > n && a > k) { printf("a is the Biggest number is %d", a); return a; }

13 954

def getLargestString(s, k): frequency_array = [0] * 26 for i in range(len(s)): frequency_array[ord(s[i]) - ord('a')] += 1 ans = "" i = 25 while i >= 0: if (frequency_array[i] > k): temp = k st = chr( i + ord('a')) while (temp > 0): ans += st temp -= 1 frequency_array[i] -= k j = i - 1 while (frequency_array[j] <= 0 and j >= 0): j -= 1 if (frequency_array[j] > 0 and j >= 0): str1 = chr(j + ord( 'a')) ans += str1 frequency_array[j] -= 1 else: break elif (frequency_array[i] > 0): temp = frequency_array[i] frequency_array[i] -= temp st = chr(i + ord('a')) while (temp > 0): ans += st temp -= 1 else: i -= 1 return ans if name == "main": S = input() k = 3 print (getLargestString(S, k)) Python Bob code

13 954

from itertools import permutations def count(arr): z=[] perm = permutations(arr) for i in list(perm): z.append(list(i)) q=[] for i in range(len(arr)-1): x,y=arr[i],arr[i+1] for j in range(len(z)): if z[j].index(x)!=len(z[j])-1: if z[j][z[j].index(x)+1]==y: q.append(z[j]) for i in range(len(q)): if q[i] in z: z.remove(q[i]) return len(z) a= int(input()) b=list(map(int,input().strip().split())) print(count(b))

13 954

Java

13 954