ACCENTURE EXAM SOLUTIONS

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Array A length n code

C++

magic Number Code python 3 All test cases passed

#include <bits/stdc++.h> using namespace std; int count(string s) { int N, i, cnt = 0, ans = 0; N = s.length(); for (i = 0; i < N; i++) { if (s[i] == 'R') cnt++; if (s[i] == 'L') ans += cnt; } return ans; } int main() { string s = "RRLL"; cout << count(s) << endl; return 0; } C++

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if (n > k && n > a)   {         printf("N is the Biggest number is %d", n);         return n;     }     if (k > n && k > a)     {         printf("k is the Biggest number is %d", k);         return k;     }     if (a > n && a > k)      {      printf("a is the Biggest number is %d", a);         return a; }

def getLargestString(s, k):     frequency_array = [0] * 26     for i in range(len(s)):         frequency_array[ord(s[i]) -                         ord('a')] += 1     ans = ""     i = 25     while i >= 0:         if (frequency_array[i] > k):             temp = k             st = chr( i + ord('a'))                          while (temp > 0):                 ans += st                 temp -= 1                        frequency_array[i] -= k             j = i - 1                          while (frequency_array[j] <= 0 and                    j >= 0):                 j -= 1             if (frequency_array[j] > 0 and                 j >= 0):                 str1 = chr(j + ord( 'a'))                 ans += str1                 frequency_array[j] -= 1                          else:                 break         elif (frequency_array[i] > 0):             temp = frequency_array[i]             frequency_array[i] -= temp             st = chr(i + ord('a'))             while (temp > 0):                 ans += st                 temp -= 1         else:             i -= 1                  return ans           if name == "main":        S = input()     k = 3     print (getLargestString(S, k)) Python Bob code

from itertools import permutations def count(arr):     z=[]     perm = permutations(arr)          for i in list(perm):         z.append(list(i))     q=[]          for i in range(len(arr)-1):         x,y=arr[i],arr[i+1]                  for j in range(len(z)):             if z[j].index(x)!=len(z[j])-1:                 if z[j][z[j].index(x)+1]==y:                     q.append(z[j])                          for i in range(len(q)):          if q[i] in z:              z.remove(q[i])     return len(z) a= int(input()) b=list(map(int,input().strip().split())) print(count(b))

Java