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[#Physics ESSLCE MCQs]
13. Two objects move toward each other, collide, and separate. If there was no net external force acting on the objects, but some kinetic energy was lost, then
[#Physics ESSLCE MCQs]
12. Object 1 moves toward Object 2, whose mass is twice that of Object 1 and which is initially at rest. After their impact, the objects lock together and move with what fraction of Object 1's initial kinetic energy?
[#Physics ESSLCE MCQs]
11. An object of mass 2 kg has a linear momentum of magnitude 6 kg · m/s. What is this object's kinetic energy?
[#Physics ESSLCE MCQs]
10. The x-component of vector A is -42, and the angle it makes with the positive x-direction is 130°. What is the y-component of vector A ?
[#Physics ESSLCE MCQs]
9. The magnitude of vector A is 10. Which of the following could be the components of A ?
[#Physics ESSLCE MCQs]
8. Two vectors, A and B, have the same magnitude, m, but vector A points north whereas vector B points east. What is the sum, A + B ?
[#Physics ESSLCE MCQs]
7. If all of the forces acting on an object balance so that the net force is zero, then
[#Physics ESSLCE MCQs]
6. A person who weighs 800 N steps onto a scale that is on the floor of an elevator car. If the elevator accelerates upward at a rate of 5 m/s2, what will the scale read?
✅Solution Question 2👆(Physics). We use the work-energy principle to solve this problem. The work-energy principle states that the net work done on an object is equal to its change in kinetic energy. Mathematically, this can be expressed as:
W net = (1/2) * m * (vf^2 - vi^2)
where W net is the net work done, m is the mass of the object, vf is the final velocity, and vi is the initial velocity.
In this case, the mass of the object is 4 kg, the initial velocity is 3 m/s, and the final velocity is 6 m/s. Plugging these values into the formula, we get:
W net = (1/2) * 4 kg * (6 m/s)^2 - (3 m/s)^2
W net = (1/2) 4 kg (36 m^2/s^2 - 9 m^2/s^2)
W net = (1/2) * 4 kg * 27 m^2/s^2
W net = 54 J
📕Therefore, the net work done on the object during this time is 54 J. The answer is choice B.
use the work-energy principle to solve this problem. The work-energy principle states that the net work done on an object is equal to its change in kinetic energy. Mathematically, this can be expressed as:
Wnet = (1/2) * m * (vf^2 - vi^2)
where Wnet is the net work done, m is the mass of the object, vf is the final velocity, and vi is the initial velocity.
In this case, the mass of the object is 4 kg, the initial velocity is 3 m/s, and the final velocity is 6 m/s. Plugging these values into the formula, we get:
Wnet = (1/2) * 4 kg * (6 m/s)^2 - (3 m/s)^2
Wnet = (1/2) 4 kg (36 m^2/s^2 - 9 m^2/s^2)
Wnet = (1/2) * 4 kg * 27 m^2/s^2
Wnet = 54 J
Therefore, the net work done on the object during this time is 54 J. The answer is B. 54 J.
[#Physics ESSLCE MCQs]
5. A block of mass 3.5 kg slides down a frictionless inclined plane of length 6.4 m that makes an angle of 30° with the horizontal. If the block is released from rest at the top of the incline, what is its speed at the bottom?
[📚Physics MCQs ESSLCE]
4. While a person lifts a book of mass 2 kg from the floor to a tabletop, 1.5 m above the floor, how much work does the gravitational force do on the book?
[📚Physics MCQs ESSLCE]
3. A box of mass m slides down a frictionless inclined plane of length L and vertical height h. What is the change in its gravitational potential energy?
[#Physics ESSLCE MCQs]
2. Under the influence of a force, an object of mass 4 kg accelerates from 3 m/s to 6 m/s in 8 s. How much work was done on the object during this time?
[✅️Physics 📚MCQs ESSLCE]
1. A force F of strength 20 N acts on an object of mass 3 kg as it moves a distance of 4 m. If F is perpendicular to the 4 m displacement, the work it does is equal to:
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[#Chemistry MCQs #ESSLCE]
20. A gas can be liquefied:___________________
[#Chemistry MCQs #ESSLCE]
19. The density of a gas A is twice that of gas B. Molecular mass of A is half of the molecular mass of B. The ratio of the partial pressure of A and B is ———
[#Chemistry MCQs #ESSLCE]
18. The kinetic theory of gases predicts that total kinetic energy of gas depends on——–
[#Chemistry MCQs #ESSLCE]
17. At 25 degrees celsius and 730 mm pressure, 380 ml of dry oxygen was collected. If the temperature is constant, what volume will oxygen occupy at 760 mm pressure?
