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✅ANSWER FOR THE QUESTION 📖📖📖📖📖📖📖📖📖📖📖📖 👉Nine identical balls numbered 1 through 9 are placed in a bag. A ball is randomly drawn and replaced. Then, a second ball is randomly drawn. What is the probability that the first ball drawn and the second ball drawn are both even numbered? 📝SOLUTION Step 1: Determine the total number of possible outcomes. Since there are 9 balls in the bag, the total number of possible outcomes (sample space) is 9. S = {1, 2, 3, 4, 5, 6, 7, 8, 9} Step 2: Determine the number of favorable outcomes. To find the number of favorable outcomes (events), we need to consider the even-numbered balls. In this case, we have 4 even-numbered balls: E = {2, 4, 6, 8} When drawing the first ball, the probability of drawing an even-numbered ball is 4 out of 9. Probability =n(E)/n(S)=4/9. 📚Since the ball is replaced after each draw, the same 4 even-numbered balls are still in the bag for the second draw. Therefore, the probability of drawing an even-numbered ball on the second draw is also 4 out of 9. Step 3: Calculate the probability. The probability of two independent events occurring is the product of their individual probabilities. 📚So, we multiply the probabilities from Step 2 to find the probability of both events happening. Probability of drawing an even-numbered ball on the first draw = 4/9 Probability of drawing an even-numbered ball on the second draw, given that an even-numbered ball was drawn on the first draw = 4/9 Probability of both events happening = (4/9) * (4/9) = 16/81 Therefore, the probability that the first ball drawn and the second ball drawn are both even-numbered is 16/81.📚📚📚 📌Join, Share 👇 https://t.me/tutorialpointeth

ANSWER FOR THE QUESTION📖 👉Two six sided dice are thrown together. What is the probability that a total of 10 is thrown? SOLUTION 📝To find the probability of getting two numbers with sum 10, we need to count the number of ways we can roll and get two numbers that add up to 10 and divide by the total number of possible outcomes. 👉The total number of outcomes when two dice are thrown are:- (1,1)(1,2)(1,3)(1,4)(1,5)(1,6) (2,1)(2,2)(2,3)(2,4)(2,5)(2,6) (3,1)(3,2)(3,3)(3,4)(3,5)(3,6) (4,1)(4,2)(4,3)(4,4)(4,5)(4,6) (5,1)(5,2)(5,3)(5,4)(5,5)(5,6) (6,1)(6,2)(6,3)(6,4)(6,5)(6,6) Hence, n(S)=36(number of sample space) Sum of 10 in pair of die can be: ✅ Roll a 4 on the first die and a 6 on the second die (4,6), ✅ Roll a 5 on the first die and a 5 on the second die (5, 5), and ✅ Roll a 6 on the first die and a 4 on the second die (6,4). SO, the possible events are three: (4, 6),(5, 5),(6, 4) n(E)=3 ∴ Probability is =n(E)/n(S) =3/36=1/12. 📌Join, Share 👇 https://t.me/tutorialpointeth

If the ratio of red, green, and black lollies in a packet is 2:3:5, this means that for every 2 red lollies, there are 3 green lollies and 5 black lollies. If there are 10 red lollies, we can use this ratio to find the number of green and black lollies: - For every 2 red lollies, there are 3 green lollies. So for 10 red lollies, there are (10/2) x 3 = 15 green lollies. - For every 2 red lollies, there are 5 black lollies. So for 10 red lollies, there are (10/2) x 5 = 25 black lollies. Therefore, there are 15 green lollies and 25 black lollies in the packet.

✅[2014 Aptitude ESSLCE] At a restaurant the bill came to 82 dollars. If you leave 119.72 dollars, what is the percentage of the tip? A) 31.5. B) 46. C) 64. D) 38 📝Solution: To find the percentage of the tip, we need to first calculate the amount of the tip. The amount of the tip is the difference between the total amount paid and the cost of the meal. 👉Total amount paid = cost of the meal + tip Tip = total amount paid - cost of the meal In this case, the cost of the meal is $82 and the total amount paid is $119.72. Tip = $119.72 - $82 = $37.72 To find the percentage of the tip, we divide the amount of the tip by the cost of the meal and multiply by 100. 👉Percentage of tip = (Tip / Cost of the meal) x 100 Percentage of tip = (37.72 / 82) x 100 Percentage of tip = 46% 📚Therefore, the percentage of the tip is approximately 46%.