IBM | AMAZON | ACCENTURE OA Exams SOLUTIONS
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X from Y Code
C++ Language
✅ Done
TCS Codevita
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define freakperson vector<int>
#define all(a) (a).begin() , (a).end()
#define sz(a) ((int)((a).size()))
const ll INF = 4e18;
vector<freakperson> dp(1e4+1 , freakperson(1e4+1 , -1));
int f(int i , int j , int s , int r , string &x , string &y , string &y1)
{
if(i>j)return 0;
if(dp[i][j] != -1)return dp[i][j];
int mini = 1e9;
for(int k=i; k<=j; k++)
{
if(y1.find(x.substr(i , k-i+1)) != string::npos)mini = min(mini , r+f(k+1 , j , s , r , x , y , y1));
if(y.find(x.substr(i , k-i+1)) != string::npos)mini = min(mini , s+f(k+1 , j , s , r , x , y , y1));
}
return mini;
}
int solve(int s , int r , string x, string y)
{
string y1 = y;
reverse(all(y1));
return f(0 , sz(x)-1 , s, r , x , y , y1);
}
int32_t main(){
ios_base::sync_with_stdio(false);
cin.tie(NULL);
string x , y;
cin >> x >> y;
int s, r;
cin >> s >> r;
int ans = solve(s , r, x , y);
cout << ans;
return 0;
}
X from Y
C++ Language
100% Working ✅
TCS Codevita
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C++
Problem of the Day
3 December
Geeks for Geeks
class Solution
{
public:
void inorder(Node *root,vector&v){
if(!root)return;
inorder(root->left,v);
v.push_back(root->data);
inorder(root->right,v);
}
int countPairs(Node* root1, Node* root2, int x)
{
vectorv1,v2;
inorder(root1,v1);
inorder(root2,v2);
unordered_set s(v1.begin(),v1.end());
int ct = 0;
for(int i = 0; i < v2.size(); i++){
if(s.find(x - v2[i]) != s.end()) ct++;
}
return ct;
}
};
C++
Problem of the Day
3 December
Geeks for Geeks
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