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IBM | AMAZON | ACCENTURE OA Exams SOLUTIONS

IBM | AMAZON | ACCENTURE OA Exams SOLUTIONS

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šŸ’¢ IBM,AMAZON, ACCENTURE and any OA/Placements exam help available 100% clearance will be provided Full exam help will be provided To book slot contact @UrTrusty
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IPV6 Code Java IBM public static String convertToIpv6(String ipv4Address) { String[] octets = ipv4Address.split("\\."); if (octets.length != 4) { return "Invalid input"; } if (octets[0].equals("127")) { return "::1"; } StringBuilder ipv6 = new StringBuilder("::FFFF:"); try { for (int i = 0; i < 4; i++) { int octet = Integer.parseInt(octets[i]); if (octet < 0 || octet > 255) { return "Invalid input"; } String hex = String.format("%02X", octet); ipv6.append(hex); if (i == 1) { ipv6.append(":"); } } } catch (NumberFormatException e) { return "Invalid input"; } return ipv6.toString(); } IPV6 Code Java IBM Triangle Code C++ IBM double calculate_area(int a, int b, int c) { double p = (a + b + c) / 2.0; return (p * (p - a) * (p - b) * (p - c)); } int compare(const void* a, const void* b) { triangle* t1 = (triangle*)a; triangle* t2 = (triangle*)b; if (t1->area < t2->area) return -1; else if (t1->area > t2->area) return 1; else return 0; } int sort_by_area(triangle* tr, int n) { if (tr == NULL || n <= 0) { return -1; } for (int i = 0; i < n; i++) { tr[i].area = calculate_area(tr[i].a, tr[i].b, tr[i].c); } qsort(tr, n, sizeof(triangle), compare); return 0; } Triangle Code C++ IBM
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public static String convertToIpv6(String ipv4Address) { String[] octets = ipv4Address.split("\\."); if (octets.length != 4) { return "Invalid input"; } if (octets[0].equals("127")) { return "::1"; } StringBuilder ipv6 = new StringBuilder("::FFFF:"); try { for (int i = 0; i < 4; i++) { int octet = Integer.parseInt(octets[i]); if (octet < 0 || octet > 255) { return "Invalid input"; } String hex = String.format("%02X", octet); ipv6.append(hex); if (i == 1) { ipv6.append(":"); } } } catch (NumberFormatException e) { return "Invalid input"; } return ipv6.toString(); } IPV6 Code Java IBM Triangle Code C++ IBM https://telegram.me/+Q_kf6B6EFexiNmU9 double calculate_area(int a, int b, int c) { double p = (a + b + c) / 2.0; return (p * (p - a) * (p - b) * (p - c)); } int compare(const void* a, const void* b) { triangle* t1 = (triangle*)a; triangle* t2 = (triangle*)b; if (t1->area < t2->area) return -1; else if (t1->area > t2->area) return 1; else return 0; } int sort_by_area(triangle* tr, int n) { if (tr == NULL || n <= 0) { return -1; } for (int i = 0; i < n; i++) { tr[i].area = calculate_area(tr[i].a, tr[i].b, tr[i].c); } qsort(tr, n, sizeof(triangle), compare); return 0; } Triangle Code C++ IBM
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šŸ’¢ INFOSYS Ā  IBM,ACCENTURE,WALMART and any OA/Placements exam help available 100% clearance will be provided Full exam help will be provided To book slot contact @UrTrusty Take remote access/mode help and pay after code pass
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No text...
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#include <iostream> #include <vector> #include <numeric> #define MOD 1000000007 using namespace std; long long mod_inv(long long x, long long mod) { Ā Ā Ā  long long result = 1; Ā Ā Ā  long long power = mod - 2; Ā Ā Ā  while (power) { Ā Ā Ā Ā Ā Ā Ā  if (power % 2) { Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā  result = result * x % mod; Ā Ā Ā Ā Ā Ā Ā  } Ā Ā Ā Ā Ā Ā Ā  x = x * x % mod; Ā Ā Ā Ā Ā Ā Ā  power /= 2; Ā Ā Ā  } Ā Ā Ā  return result; } vector<long long> factorial(int n, long long mod) { Ā Ā Ā  vector<long long> fact(n + 1, 1); Ā Ā Ā  for (int i = 2; i <= n; ++i) { Ā Ā Ā Ā Ā Ā Ā  fact[i] = fact[i - 1] * i % mod; Ā Ā Ā  } Ā Ā Ā  return fact; } long long binomial_coeff(int n, int k, const vector<long long>& fact, long long mod) { Ā Ā Ā  if (k > n || k < 0) { Ā Ā Ā Ā Ā Ā Ā  return 0; Ā Ā Ā  } Ā Ā Ā  return fact[n] * mod_inv(fact[k], mod) % mod * mod_inv(fact[n - k], mod) % mod; } long long count_ways(int N, int K, const vector<int>& A) { Ā Ā Ā  int sum_A = accumulate(A.begin(), A.end(), 0); Ā Ā Ā  int M = K - sum_A; Ā Ā Ā  vector<long long> fact = factorial(M + N - 1, MOD); Ā Ā Ā  return binomial_coeff(M + N - 1, N - 1, fact, MOD); } int main() { Ā Ā Ā  int N, K; Ā Ā Ā  cin >> N >> K; Ā Ā Ā  vector<int> A(N); Ā Ā Ā  for (int i = 0; i < N; ++i) { Ā Ā Ā Ā Ā Ā Ā  cin >> A[i]; Ā Ā Ā  } Ā Ā Ā  cout << count_ways(N, K, A) << endl; Ā Ā Ā  return 0; } DISTURBUTING BOOKS āœ…
1 705
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Infosys Permutation tree code āœ… Tree LIS āœ… Yet to subsequence āœ… Strange Strings āœ… Longest Beautiful Prefix āœ… Cleared šŸ’Æ+1
Infosys Permutation tree code āœ… Tree LIS āœ… Yet to subsequence āœ… Strange Strings āœ… Longest Beautiful Prefix āœ… Cleared šŸ’Æ
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https://www.linkedin.com/posts/prabhatnayak31_software-engineer-activity-7222528992656941056-2yCW
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IBM Front end developer https://careers.ibm.com/job/20687087/front-end-developer-bangalore-in/?codes=SN_LinkedIn&Codes=SN_LinkedIn
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