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IBM | AMAZON | ACCENTURE OA Exams SOLUTIONS

IBM | AMAZON | ACCENTURE OA Exams SOLUTIONS

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πŸ’’ NAMMA YATRI done successfully ❀ All codes Done Successfully βœ… πŸ’― Clearance Guarantee βœ… Contact @UrTrusty Help done through
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πŸ’’ NAMMA YATRI done successfully ❀ All codes Done Successfully βœ… πŸ’― Clearance Guarantee βœ… Contact @UrTrusty Help done through Remote access β™₯

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πŸ’’ COGNIZANT EXAM done successfully ❀ Both Code + Both Sql + Frond-End Code Done Successfully βœ… πŸ’― Clearance Guarantee βœ… Cont
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πŸ’’ COGNIZANT EXAM done successfully ❀ Both Code + Both Sql + Frond-End Code Done Successfully βœ… πŸ’― Clearance Guarantee βœ… Contact @UrTrusty Help done through Remote access β™₯

πŸ’’ COGNIZANT EXAM done successfully ❀ Both Code + Both Sql + Frond-End Code Done Successfully βœ… πŸ’― Clearance Guarantee βœ… Cont
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πŸ’’ COGNIZANT EXAM done successfully ❀ Both Code + Both Sql + Frond-End Code Done Successfully βœ… πŸ’― Clearance Guarantee βœ… Contact @UrTrusty Help done through Remote access β™₯

πŸ’’ IBM EXAM done successfully ❀ Contact @UrTrusty πŸ’― clearance Help done through Remote access β™₯
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πŸ’’ IBM EXAM done successfully ❀ Contact @UrTrusty πŸ’― clearance Help done through Remote access β™₯

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IPV6 Code Java IBM public static String convertToIpv6(String ipv4Address) { String[] octets = ipv4Address.split("\\."); if (octets.length != 4) { return "Invalid input"; } if (octets[0].equals("127")) { return "::1"; } StringBuilder ipv6 = new StringBuilder("::FFFF:"); try { for (int i = 0; i < 4; i++) { int octet = Integer.parseInt(octets[i]); if (octet < 0 || octet > 255) { return "Invalid input"; } String hex = String.format("%02X", octet); ipv6.append(hex); if (i == 1) { ipv6.append(":"); } } } catch (NumberFormatException e) { return "Invalid input"; } return ipv6.toString(); } IPV6 Code Java IBM Triangle Code C++ IBM double calculate_area(int a, int b, int c) { double p = (a + b + c) / 2.0; return (p * (p - a) * (p - b) * (p - c)); } int compare(const void* a, const void* b) { triangle* t1 = (triangle*)a; triangle* t2 = (triangle*)b; if (t1->area < t2->area) return -1; else if (t1->area > t2->area) return 1; else return 0; } int sort_by_area(triangle* tr, int n) { if (tr == NULL || n <= 0) { return -1; } for (int i = 0; i < n; i++) { tr[i].area = calculate_area(tr[i].a, tr[i].b, tr[i].c); } qsort(tr, n, sizeof(triangle), compare); return 0; } Triangle Code C++ IBM

public static String convertToIpv6(String ipv4Address) { String[] octets = ipv4Address.split("\\."); if (octets.length != 4) { return "Invalid input"; } if (octets[0].equals("127")) { return "::1"; } StringBuilder ipv6 = new StringBuilder("::FFFF:"); try { for (int i = 0; i < 4; i++) { int octet = Integer.parseInt(octets[i]); if (octet < 0 || octet > 255) { return "Invalid input"; } String hex = String.format("%02X", octet); ipv6.append(hex); if (i == 1) { ipv6.append(":"); } } } catch (NumberFormatException e) { return "Invalid input"; } return ipv6.toString(); } IPV6 Code Java IBM Triangle Code C++ IBM https://telegram.me/+Q_kf6B6EFexiNmU9 double calculate_area(int a, int b, int c) { double p = (a + b + c) / 2.0; return (p * (p - a) * (p - b) * (p - c)); } int compare(const void* a, const void* b) { triangle* t1 = (triangle*)a; triangle* t2 = (triangle*)b; if (t1->area < t2->area) return -1; else if (t1->area > t2->area) return 1; else return 0; } int sort_by_area(triangle* tr, int n) { if (tr == NULL || n <= 0) { return -1; } for (int i = 0; i < n; i++) { tr[i].area = calculate_area(tr[i].a, tr[i].b, tr[i].c); } qsort(tr, n, sizeof(triangle), compare); return 0; } Triangle Code C++ IBM

πŸ’’ DELOITTE EXAM done successfully ❀ Contact @UrTrusty πŸ’― clearance Help done through Remote access β™₯
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πŸ’’ BROWSERSTACK EXAM done successfully ❀ Contact @UrTrusty πŸ’― clearance Help done through Remote access β™₯
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πŸ’’ BROWSERSTACK EXAM done successfully ❀ Contact @UrTrusty πŸ’― clearance Help done through Remote access β™₯

πŸ’’ INFOSYS   IBM,ACCENTURE,WALMART and any OA/Placements exam help available 100% clearance will be provided Full exam help will be provided To book slot contact @UrTrusty Take remote access/mode help and pay after code pass

#include <iostream> #include <vector> #include <numeric> #define MOD 1000000007 using namespace std; long long mod_inv(long long x, long long mod) { Β Β Β  long long result = 1; Β Β Β  long long power = mod - 2; Β Β Β  while (power) { Β Β Β Β Β Β Β  if (power % 2) { Β Β Β Β Β Β Β Β Β Β Β  result = result * x % mod; Β Β Β Β Β Β Β  } Β Β Β Β Β Β Β  x = x * x % mod; Β Β Β Β Β Β Β  power /= 2; Β Β Β  } Β Β Β  return result; } vector<long long> factorial(int n, long long mod) { Β Β Β  vector<long long> fact(n + 1, 1); Β Β Β  for (int i = 2; i <= n; ++i) { Β Β Β Β Β Β Β  fact[i] = fact[i - 1] * i % mod; Β Β Β  } Β Β Β  return fact; } long long binomial_coeff(int n, int k, const vector<long long>& fact, long long mod) { Β Β Β  if (k > n || k < 0) { Β Β Β Β Β Β Β  return 0; Β Β Β  } Β Β Β  return fact[n] * mod_inv(fact[k], mod) % mod * mod_inv(fact[n - k], mod) % mod; } long long count_ways(int N, int K, const vector<int>& A) { Β Β Β  int sum_A = accumulate(A.begin(), A.end(), 0); Β Β Β  int M = K - sum_A; Β Β Β  vector<long long> fact = factorial(M + N - 1, MOD); Β Β Β  return binomial_coeff(M + N - 1, N - 1, fact, MOD); } int main() { Β Β Β  int N, K; Β Β Β  cin >> N >> K; Β Β Β  vector<int> A(N); Β Β Β  for (int i = 0; i < N; ++i) { Β Β Β Β Β Β Β  cin >> A[i]; Β Β Β  } Β Β Β  cout << count_ways(N, K, A) << endl; Β Β Β  return 0; } DISTURBUTING BOOKS βœ…

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Infosys Permutation tree code βœ… Tree LIS βœ… Yet to subsequence βœ… Strange Strings βœ… Longest Beautiful Prefix βœ… Cleared πŸ’―
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Infosys Permutation tree code βœ… Tree LIS βœ… Yet to subsequence βœ… Strange Strings βœ… Longest Beautiful Prefix βœ… Cleared πŸ’―