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AddMath Spmnetic!™⚡️

AddMath Spmnetic!™⚡️

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This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

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📈 Analytical overview of Telegram channel AddMath Spmnetic!™⚡️

Channel AddMath Spmnetic!™⚡️ (@addmathspmnotes) in the English language segment is an active participant. Currently, the community unites 33 724 subscribers, ranking 5 675 in the Education category and 12 513 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 33 724 subscribers.

According to the latest data from 14 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 691 over the last 30 days and by 32 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 12.42%. Within the first 24 hours after publication, content typically collects 6.37% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 4 190 views. Within the first day, a publication typically gains 2 148 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 11.
  • Thematic interests: Content is focused on key topics such as addmath, untuk, 629/4, math, eqn.

📝 Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
This channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises 🤘🏻 For any enquiries, please directly ask in our discussion group ✨

Thanks to the high frequency of updates (latest data received on 15 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.

33 724
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Posts Archive
Red Curve: y = 2x³ - x² - 14x Blue Curve: y = 4x - x² Find the area of the shaded region.
Red Curve: y = 2x³ - x² - 14x Blue Curve: y = 4x - x² Find the area of the shaded region.

All Pulau Pinang 09 and 10 students can join...

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Day 02 of studying addmaths everyday

Try this guys. This should be easy
Try this guys. This should be easy

Here is the solution.
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Here is the solution.

It is given that the diameter of the circle is divided into 4 equal parts, find the area of the shaded region if the radius o
It is given that the diameter of the circle is divided into 4 equal parts, find the area of the shaded region if the radius of the circle = 4.

Recently I saw a few videos talking about ambiguous case of the law of sine for solutions of triangle. Question: When you are learning this topic, do you find it difficult to understand it? And why?
Anonymous voting

Repost from Sembang Maths
Percayalah cakap saya, mula lah sekarang. Jangan tunggu saat akhir. Pesanan yang sama dari saya, sebab saya dah tengok pelbag
Percayalah cakap saya, mula lah sekarang. Jangan tunggu saat akhir. Pesanan yang sama dari saya, sebab saya dah tengok pelbagai situasi pelajar saat2 last nak spm

wahh

day 1 of studying addmaths everyday...🔥🔥

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Let x=length of the rectangle h = height of the rectangle Black line = h/tan(60°) = (h√3)/3 Using Pythagoras' Theorem, [(h√3)/3 + x]² + h² = 36 h²/3 + (2xh√3)/3 + x² + h² - 36 = 0 h²(4/3) + [(2x√3)/3]h + (x²-36) = 0 h = [-(2x√3)/3 + √[(4x²/3)-(16/3)(x²-36)]]/(8/3) h = [-x√3 + 3√(48-x²)]/4 Area of the rectangle, A = xh = x([-x√3 + 3√(48-x²)]/4) dA/dx = (72-3x²-x√(144-3x²))/(2√(48-x²)) At Maximum, dA/dx = 0 (72-3x²-x√(144-3x²))/(2√(48-x²)) = 0 72-3x²-x√(144-3x²) = 0 => x=-6 or x=2√3 Max A = 6√3

Kepada batch 09 juga, good luck for your upcoming exams, especially spm 2026. Be ready with every subject, conquer the chapter, jangan belajar last minit, dengar cakap cikgu dan jangan skip sekolah/kelas tambahan

Kepada batch 08 yang still ada dalam channel ni, mintak semua untuk bawa bertenang dan ada perasaan redha dengan keputusan spm anda. Saya doa dan pasti anda semua calon spm 2025 akan dapat straight A!! Amin🤲❤️

JANJANG/PROGRESSIONS •gp C5F4
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JANJANG/PROGRESSIONS •gp C5F4