allcoding1_official

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India3 531 Technologies & Applications1 499...

📈 Analytical overview of Telegram channel allcoding1_official

Channel allcoding1_official (@allcoding1_official) in the English language segment is an active participant. Currently, the community unites 84 516 subscribers, ranking 1 499 in the Technologies & Applications category and 3 531 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 84 516 subscribers.

According to the latest data from 11 July, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -1 593 over the last 30 days and by -70 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 2.09%. Within the first 24 hours after publication, content typically collects 0.84% reactions from the total number of subscribers.
Post reach: On average, each post receives 1 769 views. Within the first day, a publication typically gains 712 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 1.
Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, dev.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 12 July, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

84 516

Subscribers

-7024 hours

-4307 days

-1 59330 days

1 769

Post views

~ 71224 hours

~ 1 07848 hours

2.09%

Engagement rate

~ 1

Posts per day

Ads index

beta

Posts Archive

84 516

16 🔗 Telegram: @allcoding1 🔔Unmute this channel to never miss any updates

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Black box testing 🔗 Telegram: @allcoding1 🔔Unmute this channel to never miss any updates

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155 🔗 Telegram: @allcoding1 🔔Unmute this channel to never miss any updates

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Repost from allcoding1_official

🎯Company name: Apple Inc Job Position: Security Engineer Location: Hyderabad Job Type: Full time Experience: Freshers Qualification: BE/ B.Tech/ ME/ M.Tech Batch: 2017/ 2018/ 2019/ 2020/ 2021 Salary: Min 10 LPA (Expected) Apply:- https://www.joboffersadda.com/2022/04/apple-recruitment-be-btech-me-mtech.html 🔗 Telegram: @allcoding1 🔔Unmute this channel to never miss any updates

84 516

Repost from allcoding1_official

Apply:- https://www.joboffersadda.com/2022/04/wipro-recruitment-any-graduate.html 🔗 Telegram: @allcoding1 🔔Unmute this channel to never miss any updates

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Repost from allcoding1_official

🎯 Cognizant Recruitment For Process Executive - Data Location: Hyderabad Qualification: Any Graduate Work Experience: 0 - 2 Year Apply - https://www.joboffersadda.com/2022/04/cognizant-recruitment-2022-for-process.html 🔗 Telegram: @allcoding1 🔔Unmute this channel to never miss any updates

84 516

Repost from allcoding1_official

🎯Capgemini Engineering Off Campus Drive For Software Analyst Location: Bangalore Work Experience: Fresher Apply - https://www.joboffersadda.com/2022/04/capgemini-engineering-off-campus-drive.html 🔗 Telegram: @allcoding1 🔔Unmute this channel to never miss any updates

84 516

Repost from allcoding1_official

🎯IBM OFF CAMPUS DRIVE Degree: B.Tech/BE, MCA, M.Tech/ME 📌 link:- https://www.joboffersadda.com/2022/04/ibm-off-campus-drive.html 🔗 Telegram: @allcoding1 🔔Unmute this channel to never miss any updates

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2nd code in Python

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2nd code in C++

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Executed 1st code python

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TCS & Infosys Exam Ans (10AM) 3PM Infosys & 2:30 TCS https://www.joboffersadda.com/2022/04/infosys-tcs-exam-answers.html https://www.joboffersadda.com/2022/04/infosys-tcs-exam-answers.html https://www.joboffersadda.com/2022/04/infosys-tcs-exam-answers.html

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def smallest(n): arr = list() x = 0 for i in range(n): x = int(input()) arr.append(x) arr = sorted(arr) count = 1 temp = list() for j in range(1, n): if arr[j] == arr[j-1] + 1: count += 1 else: temp.append(count) count = 1 temp.append(count) return min(temp) n = int(input()) res = smallest(n) print(res) def isP(n): if n<=3: return True if ((n%2==0)|(n%3==0)): return False for d in range(5,int(n*5)+1,6): if ((n%d==0)|(n%(d+2)==0)): return False return True def getP(m): P=[1,2] for n in range(3,m+1,2): if isP(n): P.append(n) return P P=getP(int(105+1000)) g = int(input().strip()) for a0 in range(g): n = int(input().strip()) for i in range(len(P)): if P[i]>n: c=i-1 break if c%2==1: print("Alice") else: print("Bob") Python Alice & Bob Code TCS answers 🔗 Telegram: @allcoding1 🔔Unmute this channel to never miss any updates

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Pseudo: 1) True 2)12 38 3) compilation error 4)the valve of each 5)Construction of prototype 6)Prototyping 7)bytes 8) weighted 9)any greedy .... 10) option A

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Test of Knowledge 1.True