allcoding1_official
前往频道在 Telegram
📈 Telegram 频道 allcoding1_official 的分析概览
频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 84 516 名订阅者，在 技术与应用 类别中位列第 1 499，并在 印度 地区排名第 3 531 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 84 516 名订阅者。
根据 11 七月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -1 593，过去 24 小时变化为 -70，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 2.09%。内容发布后 24 小时内通常能获得 0.84% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 1 769 次浏览，首日通常累积 712 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 1。
- 主题关注点： 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新（最新数据采集于 12 七月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 技术与应用 类别中的关键影响点。
84 516
订阅者
-7024 小时
-4307 天
-1 59330 天
帖子存档
84 516
Repost from allcoding1_official
🎯Company name: Apple Inc
Job Position: Security Engineer
Location: Hyderabad
Job Type: Full time
Experience: Freshers
Qualification: BE/ B.Tech/ ME/ M.Tech
Batch: 2017/ 2018/ 2019/ 2020/ 2021
Salary: Min 10 LPA (Expected)
Apply:- https://www.joboffersadda.com/2022/04/apple-recruitment-be-btech-me-mtech.html
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
84 516
Repost from allcoding1_official
Apply:- https://www.joboffersadda.com/2022/04/wipro-recruitment-any-graduate.html
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
84 516
Repost from allcoding1_official
🎯 Cognizant Recruitment For Process Executive - Data
Location: Hyderabad
Qualification: Any Graduate
Work Experience: 0 - 2 Year
Apply - https://www.joboffersadda.com/2022/04/cognizant-recruitment-2022-for-process.html
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
84 516
Repost from allcoding1_official
🎯Capgemini Engineering Off Campus Drive For Software Analyst
Location: Bangalore
Work Experience: Fresher
Apply - https://www.joboffersadda.com/2022/04/capgemini-engineering-off-campus-drive.html
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
84 516
Repost from allcoding1_official
🎯IBM OFF CAMPUS DRIVE
Degree: B.Tech/BE, MCA, M.Tech/ME
📌 link:- https://www.joboffersadda.com/2022/04/ibm-off-campus-drive.html
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
84 516
TCS & Infosys Exam Ans (10AM)
3PM Infosys & 2:30 TCS
https://www.joboffersadda.com/2022/04/infosys-tcs-exam-answers.html
https://www.joboffersadda.com/2022/04/infosys-tcs-exam-answers.html
https://www.joboffersadda.com/2022/04/infosys-tcs-exam-answers.html
84 516
def smallest(n):
arr = list()
x = 0
for i in range(n):
x = int(input())
arr.append(x)
arr = sorted(arr)
count = 1
temp = list()
for j in range(1, n):
if arr[j] == arr[j-1] + 1:
count += 1
else:
temp.append(count)
count = 1
temp.append(count)
return min(temp)
n = int(input())
res = smallest(n)
print(res)
def isP(n):
if n<=3:
return True
if ((n%2==0)|(n%3==0)):
return False
for d in range(5,int(n*5)+1,6):
if ((n%d==0)|(n%(d+2)==0)):
return False
return True
def getP(m):
P=[1,2]
for n in range(3,m+1,2):
if isP(n):
P.append(n)
return P
P=getP(int(105+1000))
g = int(input().strip())
for a0 in range(g):
n = int(input().strip())
for i in range(len(P)):
if P[i]>n:
c=i-1
break
if c%2==1:
print("Alice")
else:
print("Bob")
Python
Alice & Bob Code
TCS answers
🔗 Telegram: @allcoding1
🔔Unmute this channel to never miss any updates
84 516
Pseudo:
1) True
2)12 38
3) compilation error
4)the valve of each
5)Construction of prototype
6)Prototyping
7)bytes
8) weighted
9)any greedy ....
10) option A
84 516
TCS & Infosys Exam Ans (10AM)
3PM Infosys & 2:30 TCS
https://www.joboffersadda.com/2022/04/infosys-tcs-exam-answers.html
https://www.joboffersadda.com/2022/04/infosys-tcs-exam-answers.html
https://www.joboffersadda.com/2022/04/infosys-tcs-exam-answers.html
