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allcoding1_official

allcoding1_official

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📈 Analytical overview of Telegram channel allcoding1_official

Channel allcoding1_official (@allcoding1_official) in the English language segment is an active participant. Currently, the community unites 85 424 subscribers, ranking 1 497 in the Technologies & Applications category and 3 469 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 85 424 subscribers.

According to the latest data from 26 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -1 404 over the last 30 days and by -20 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 2.55%. Within the first 24 hours after publication, content typically collects 0.86% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 2 176 views. Within the first day, a publication typically gains 738 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 4.
  • Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, dev.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 27 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

85 424
Subscribers
-2024 hours
-2967 days
-1 40430 days
Posts Archive
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string getLongestRegex(string a, string b, string c) {   const size_t n = a.size();   int idx = -1;   for (int
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string getLongestRegex(string a, string b, string c) {   const size_t n = a.size();   int idx = -1;   for (int i = 0; i < n; i++) {     if (c[i] != a[i] && c[i] != b[i]) { idx = i; }   }   if (idx == -1) return "-1";   string res;   for (int i = 0; i < n; i++) {         if (i == idx) {       string cur = "[";       for (int j = 'A'; j <= 'Z'; j++)  if (j != c[i]) cur += j;       cur += "]";       res += cur;     } else {       res += "[ABCDEFGHIJKLMNOPQRSTUVWXYZ]";     }   }   return res; } C++ Amazon

def minimumCost(price): n = len(price) price.append(0) ans = float('inf') last = {price[0]: 0} for i in range(1, n): v = pric
def minimumCost(price):     n = len(price)     price.append(0)     ans = float('inf')     last = {price[0]: 0}     for i in range(1, n):         v = price[i]         price[i] += price[i - 1]         if last.get(v) != None:             ans = min(ans, price[i] - price[last[v]] + v)         last[v] = i     return ans if ans != float('inf') else -1 n = int(input()) price = list(map(int,input().split(' '))) print(minimumCost(price)) Python 3 Amazon

#include <bits/stdc++.h> using namespace std; bool checkbit(int n,int i){     return n&(1<<i); } bool cmp(const pair<int,int> &a,const pair<int,int>&b){     return a.second<b.second; } int main() {     int n;cin>>n;   int a[n];   for(int i=0;i<n;i++) cin>>a[i];   vector<pair<int,int>> v;   for(int i=0;i<n;i++){       int c=0;       for(int j=0;j<31;j++){           if(checkbit(a[i],j)) c++;       }       v.push_back({a[i],c});   }   int idx = 0;   sort(v.begin(),v.end(),cmp);   for(auto it : v){       a[idx++] = it.first;       cout<<it.second<<" ";   }   for(int i=0;i<n;i++){       cout<<a[i]<<" ";   }   return 0; } C++ Telegram:- @allcoding1_official

def cardinalitySort(nums): return sorted(nums, key=lambda num: [bin(num).count('1'), num]) Cardinality sorting
def cardinalitySort(nums):     return sorted(nums, key=lambda num: [bin(num).count('1'), num]) Cardinality sorting

Distinct digital number Python 3 JP Morgan
Distinct digital number Python 3 JP Morgan

#include <bits/stdc++.h> using namespace std; bool checkbit(int n,int i){     return n&(1<<i); } bool cmp(const pair<int,int> &a,const pair<int,int>&b){     return a.second<b.second; } int main() {   // your code goes here   int n;cin>>n;   int a[n];   for(int i=0;i<n;i++) cin>>a[i];   vector<pair<int,int>> v;   for(int i=0;i<n;i++){       int c=0;       for(int j=0;j<31;j++){           if(checkbit(a[i],j)) c++;       }       v.push_back({a[i],c});   }   int idx = 0;   sort(v.begin(),v.end(),cmp);   for(auto it : v){       a[idx++] = it.first;       cout<<it.second<<" ";   }   for(int i=0;i<n;i++){       cout<<a[i]<<" ";   }   return 0; } C++

def cardinalitySort(nums): return sorted(nums, key=lambda num: [bin(num).count('1'), num]) Cardinality sorting JP Morgan
def cardinalitySort(nums):     return sorted(nums, key=lambda num: [bin(num).count('1'), num]) Cardinality sorting JP Morgan

def gameWinner(colors):     currPlayer = "wendy"     prevPlayer = ""     winner = ""     while True:         moveMade = False         if currPlayer == "wendy":             whiteIndex = colors.find("www")             if whiteIndex = -1:                 # 3 consecutive whites found, remove the middle one                 colorsBuilder = list(colors)                 colorsBuilder.pop(whiteIndex + 1)                 colors = "".join(colorsBuilder)                 moveMade = True                 prevPlayer = currPlayer                 currPlayer = "bob"         else:             blackIndex = colors.find("bbb")             if blackIndex != -1:                 # 3 consecutive blacks found, remove the middle one                 colorsBuilder = list(colors)                 colorsBuilder.pop(blackIndex + 1)                 colors = "".join(colorsBuilder)                 moveMade = True                 prevPlayer = currPlayer                 currPlayer = "wendy"         # if no moves possible break         if not moveMade:             winner = prevPlayer             break     return winner print(gameWinner("wwwbb")) Python 3 Game Winner JP Morgan

Amazon seller anybody there in our group

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import requests import json def getCaptialCity(country): api_request = requests.get(''//@allcoding1 name='+country) data = ap
import requests import json def getCaptialCity(country): api_request = requests.get(''//@allcoding1 name='+country) data = api_request.json()['data'] if(len(data[0]['capital'])==0) return -1 return data[0]['capital'] country = input() print(getCapitalCity(country)) Python IBM exam Ans Telegram:- @allcoding1_official

Python IBM exam And Telegram:- @allcoding1_official
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Python IBM exam And Telegram:- @allcoding1_official