allcoding1_official
前往频道在 Telegram
📈 Telegram 频道 allcoding1_official 的分析概览
频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 78 690 名订阅者,在 技术与应用 类别中位列第 1 624,并在 印度 地区排名第 3 768 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 78 690 名订阅者。
根据 31 十月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 635,过去 24 小时变化为 -91,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 1.60%。内容发布后 24 小时内通常能获得 0.61% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 263 次浏览,首日通常累积 481 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 0。
- 主题关注点: 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新(最新数据采集于 01 十一月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
78 690
订阅者
-9124 小时
-3887 天
-1 63530 天
帖子存档
78 690
🎯Google Internship 2024 | Software Student Training in Engineering Program | Apply Now
Job Role : Software Student Training in Engineering Program
Qualification : B.E/B.Tech/B.Sc
Experience : Freshers
Last Date : 19 January 2024
Apply Now:- www.allcoding1.com
Telegram:- @allcoding1_official
78 690
🎯Google Internship 2024 | Software Student Training in Engineering Program | Apply Now
Job Role : Software Student Training in Engineering Program
Qualification : B.E/B.Tech/B.Sc
Experience : Freshers
Last Date : 19 January 2024
Apply Now:- www.allcoding1.com
Telegram:- @allcoding1_official
78 690
🎯Phone pe hiring
Job role:- Advisor,ONDC
Qualification:- Any
Experience:- 0-2years
Location:- Bangalore
Apply Now:- www.allcoding1.com
Telegram:- @allcoding1_official
78 690
#scammer
Please report 👇
@offical1allcoding , Vds , @Allcodingoffical, @coding1officalyyh
The changing names
Guys ♥️ be careful don't pay money
78 690
Guys ♥️
@allcoding, @Allcodingoffical1, @offical1allcoding @Allcodingoffical, @codingoffical and @coding1officalyyh @Allcodingofficalmain it's not me don't lose your money
#scammer
Please report
Please share with your friends and telegram Group's
78 690
🎯Phone pe hiring
Job role:- Advisor,ONDC
Qualification:- Any
Experience:- 0-2years
Location:- Bangalore
Apply Now:- www.allcoding1.com
Telegram:- @allcoding1_official
78 690
Repost from allcoding1_official
#scammer
Please report 👇
@offical1allcoding , Vds , @Allcodingoffical
The changing names
Guys ♥️ be careful don't pay money
78 690
Repost from allcoding1_official
Guys ♥️
@allcoding, @Allcodingoffical1, @offical1allcoding @Allcodingoffical, @codingoffical and @Allcodingofficalmain it's not me don't lose your money
#scammer
Please report
Please share with your friends and telegram Group's
78 690
Repost from allcoding1_official
#scammer
Please report 👇
@offical1allcoding , Vds , @Allcodingoffical
The changing names
78 690
Repost from allcoding1_official
Guys ♥️
@allcoding, @Allcodingoffical1, @offical1allcoding @Allcodingoffical, @codingoffical and @Allcodingofficalmain it's not me don't lose your money
#scammer
Please report
Please share with your friends and telegram Group's
78 690
🎯 IBM Off Campus Drive Hiring 2024 | Sofware Developer | 6-20 LPA
Job Role : Software Developer
Qualification : BE/ B.Tech/ ME/ M.Tech
Experience : 0-3 years
Package : 6-20 LPA*
Apply Now:- www.allcoding1.com
Telegram:- @allcoding1_official
78 690
🎯 IBM Off Campus Drive Hiring 2024 | Sofware Developer | 6-20 LPA
Job Role : Software Developer
Qualification : BE/ B.Tech/ ME/ M.Tech
Experience : 0-3 years
Package : 6-20 LPA*
Apply Now:- www.allcoding1.com
Telegram:- @allcoding1_official
78 690
Accenture Work From Home
🎯Position: HR Partner Analyst
Qualification: Any Graduate
Experience: 0-3 Years
Location: Remote (Bangalore Office)
Salary: 3 LPA – 5 LPA
Apply Now:- www.allcoding1.com
Telegram:- @allcoding1_official
78 690
🎯Ford Off Campus Drive Hiring 2024 | 2022/2023 Batches | 4 LPA
Job Role : Multiple Roles
Qualification : B.E/B.Tech
Batch : 2022/2023
Package : 4 LPA+
Apply Fast :- www.allcoding1.com
Telegram:- @allcoding1_official
78 690
int solve(vector> arr) {
int n = arr.size();
vector> dp(n, vector(n));
int maxi = 0;
for(int i = 0; i < n; i++) {
for(int j = 0; j < n; j++) {
if(i == 0 || j == 0) {
dp[i][j] = arr[i][j];
} else if(arr[i][j] == 1) {
dp[i][j] = min({dp[i-1][j], dp[i][j-1], dp[i-1][j-1]}) + 1;
}
maxi = max(maxi, dp[i][j]);
}
}
return maxi;
}
IBM
