allcoding1_official

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India3 460 Technologies & Applications1 507...

📈 Analytical overview of Telegram channel allcoding1_official

Channel allcoding1_official (@allcoding1_official) in the English language segment is an active participant. Currently, the community unites 85 295 subscribers, ranking 1 507 in the Technologies & Applications category and 3 460 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 85 295 subscribers.

According to the latest data from 28 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -1 494 over the last 30 days and by -77 over the last 24 hours, overall reach remains high.

Verification status: Not verified
Engagement rate (ER): The average audience engagement rate is 2.71%. Within the first 24 hours after publication, content typically collects 0.84% reactions from the total number of subscribers.
Post reach: On average, each post receives 2 308 views. Within the first day, a publication typically gains 713 views.
Reactions and interaction: The audience actively supports content: the average number of reactions per post is 3.
Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, dev.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 29 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

85 295

Subscribers

-7724 hours

-3927 days

-1 49430 days

2 308

Post views

~ 71324 hours

~ 1 09648 hours

2.71%

Engagement rate

No data

Posts per day

Ads index

beta

Posts Archive

85 284

def getLargestString(s, k): frequency_array = [0] * 26 for i in range(len(s)): frequency_array[ord(s[i]) - ord('a')] += 1 ans = "" i = 25 while i >= 0: if (frequency_array[i] > k): temp = k st = chr( i + ord('a')) while (temp > 0): ans += st temp -= 1 frequency_array[i] -= k j = i - 1 while (frequency_array[j] <= 0 and j >= 0): j -= 1 if (frequency_array[j] > 0 and j >= 0): str1 = chr(j + ord( 'a')) ans += str1 frequency_array[j] -= 1 else: break elif (frequency_array[i] > 0): temp = frequency_array[i] frequency_array[i] -= temp st = chr(i + ord('a')) while (temp > 0): ans += st temp -= 1 else: i -= 1 return ans if name == "main": S = input() k = 3 print (getLargestString(S, k)) Python Bob code INFOSYS EXAM ANS 10AM ALL Slots are available Telegram:- @allcoding1_official @allcoding1_official discussion group:- @Infosys_examAns Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE= Share with your friends

85 284

#include<stdio.h> Int main(){ Int n,x; Scanf(”%d",&n); int n=x; For (int i=0;i<=n-1;i++){ scanf(''%d'',&a[i]); x=2*x-a[i]; } Printf("%d",x); } C language

85 284

Python Once check it out put INFOSYS EXAM ANS 10AM ALL Slots are available Telegram:- @allcoding1_official @allcoding1_official discussion group:- @Infosys_examAns Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE= Share with your friends

85 284

Python INFOSYS EXAM ANS 10AM ALL Slots are available Telegram:- @allcoding1_official @allcoding1_official discussion group:- @Infosys_examAns Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE= Share with your friends

85 284

Java INFOSYS EXAM ANS 10AM ALL Slots are available Telegram:- @allcoding1_official @allcoding1_official discussion group:- @Infosys_examAns Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE= Share with your friends

85 284

Java

85 284

def next_stepping_number(N): N = str(N) for i in range(len(N) - 1): if abs(int(N[i]) - int(N[i+1])) != 1: return int(N[:i+1] + str(int(N[i]) + 1 if int(N[i]) < int(N[i+1]) else int(N[i]) - 1) + '9'*(len(N)-i-1)) return int(N) + 1 print(next_stepping_number(4)) # should return 5

85 284

def shortest_subarray(colors, C): n = len(colors) color_count = [0] * (C+1) left, right = 0, 0 min_length = float('inf') count = 0 while right < n: color_count[colors[right]] += 1 if color_count[colors[right]] == 1: count += 1 while count == C: min_length = min(min_length, right - left + 1) color_count[colors[left]] -= 1 if color_count[colors[left]] == 0: count -= 1 left += 1 right += 1 if min_length == float('inf'): return -1 else: return min_length Python3

85 284

Java 8

85 284

#include <bits/stdc++.h> using namespace std; int main() { string S; cin >> S; int n = S.length(); int dp[n + 1]; memset(dp, 0x3f, sizeof dp); dp[0] = 0; for (int i = 0; i < n; i++) { int digit = S[i] - '0'; for (int j = max(0, i - 2); j < i; j++) { int sum = 0; for (int k = j; k <= i; k++) { sum += S[k] - '0'; } if (sum % 3 == 0) { int cost = digit; for (int k = j; k <= i; k++) { cost = min(cost, S[k] - '0'); //@allcoding1 } dp[i + 1] = min(dp[i + 1], dp[j] + cost); } } } cout << dp[n] << endl; return 0; } C++

85 284

Python

85 284

Infosys exam coding Ans http://www.joboffersadda.com/2022/01/infosys-exam-answer.html http://www.joboffersadda.com/2022/01/infosys-exam-answer.html Allcoding Ans are available Telegram:- @Infosys_Ans

85 284

WWW.allcoding1.com

85 284

INFOSYS EXAM ANS 10AM ALL Slots are available Telegram:- @allcoding1_official @allcoding1_official discussion group:- @Infosys_examAns Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE= Share with your friends