allcoding1_official
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📈 Analytical overview of Telegram channel allcoding1_official
Channel allcoding1_official (@allcoding1_official) in the English language segment is an active participant. Currently, the community unites 84 502 subscribers, ranking 1 495 in the Technologies & Applications category and 3 530 in the India region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 84 502 subscribers.
According to the latest data from 12 July, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -1 602 over the last 30 days and by -68 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 2.00%. Within the first 24 hours after publication, content typically collects 0.84% reactions from the total number of subscribers.
- Post reach: On average, each post receives 1 688 views. Within the first day, a publication typically gains 712 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 1.
- Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, dev.
📝 Description and content policy
Channel description not provided.
Thanks to the high frequency of updates (latest data received on 13 July, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
84 502
Subscribers
-6824 hours
-3987 days
-1 60230 days
Posts Archive
84 444
// Infosys
// N flowers on a Recatangular pana
int ans = 100000000;
void solve(vector a, int n, int k, int index, int sum,
int maxsum)
{
if (k == 1)
{
maxsum = max(maxsum, sum);
sum = 0;
for (int i = index; i < n; i++)
{
sum += a[i];
}
maxsum = max(maxsum, sum);
ans = min(ans, maxsum);
return;
}
sum = 0;
for (int i = index; i < n; i++)
{
sum += a[i];
maxsum = max(maxsum, sum);
solve(a, n, k - 1, i + 1, sum, maxsum);
}
}
int GetMaxBeauty(int N, int K, vector A)
{
solve(A, N, K, 0, 0, 0);
return ans;
}
C++
84 444
def getLargestString(s, k):
frequency_array = [0] * 26
for i in range(len(s)):
frequency_array[ord(s[i]) -
ord('a')] += 1
ans = ""
i = 25
while i >= 0:
if (frequency_array[i] > k):
temp = k
st = chr( i + ord('a'))
while (temp > 0):
ans += st
temp -= 1
frequency_array[i] -= k
j = i - 1
while (frequency_array[j] <= 0 and
j >= 0):
j -= 1
if (frequency_array[j] > 0 and
j >= 0):
str1 = chr(j + ord( 'a'))
ans += str1
frequency_array[j] -= 1
else:
break
elif (frequency_array[i] > 0):
temp = frequency_array[i]
frequency_array[i] -= temp
st = chr(i + ord('a'))
while (temp > 0):
ans += st
temp -= 1
else:
i -= 1
return ans
if name == "main":
S = input()
k = 3
print (getLargestString(S, k))
Python
Bob code
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1_official
@allcoding1_official
discussion group:- @Infosys_examAns
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
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84 444
![#include Int main(){ Int n,x; Scanf(”%d",&n); int n=x; For (int i=0;i<=n-1;i++){ scanf(''%d'',&a[i]); x=2*x-a[i];](https://cdn.tlmtr.io/_next/static/media/empty-channel.35ed232f.svg)
#include<stdio.h>
Int main(){
Int n,x;
Scanf(”%d",&n);
int n=x;
For (int i=0;i<=n-1;i++){
scanf(''%d'',&a[i]);
x=2*x-a[i];
}
Printf("%d",x);
}
C language
84 444
Python
Once check it out put
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1_official
@allcoding1_official
discussion group:- @Infosys_examAns
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
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84 444
+1Python
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1_official
@allcoding1_official
discussion group:- @Infosys_examAns
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
84 444
+1Java
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1_official
@allcoding1_official
discussion group:- @Infosys_examAns
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
84 444
Java
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1_official
@allcoding1_official
discussion group:- @Infosys_examAns
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
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84 444
def next_stepping_number(N):
N = str(N)
for i in range(len(N) - 1):
if abs(int(N[i]) - int(N[i+1])) != 1:
return int(N[:i+1] + str(int(N[i]) + 1 if int(N[i]) < int(N[i+1]) else int(N[i]) - 1) + '9'*(len(N)-i-1))
return int(N) + 1
print(next_stepping_number(4)) # should return 5
84 444
def shortest_subarray(colors, C):
n = len(colors)
color_count = [0] * (C+1)
left, right = 0, 0
min_length = float('inf')
count = 0
while right < n:
color_count[colors[right]] += 1
if color_count[colors[right]] == 1:
count += 1
while count == C:
min_length = min(min_length, right - left + 1)
color_count[colors[left]] -= 1
if color_count[colors[left]] == 0:
count -= 1
left += 1
right += 1
if min_length == float('inf'):
return -1
else:
return min_length
Python3
84 444
def shortest_subarray(colors, C):
n = len(colors)
color_count = [0] * (C+1)
left, right = 0, 0
min_length = float('inf')
count = 0
while right < n:
color_count[colors[right]] += 1
if color_count[colors[right]] == 1:
count += 1
while count == C:
min_length = min(min_length, right - left + 1)
color_count[colors[left]] -= 1
if color_count[colors[left]] == 0:
count -= 1
left += 1
right += 1
if min_length == float('inf'):
return -1
else:
return min_length
Python3
84 444
#include <bits/stdc++.h>
using namespace std;
int main() {
string S;
cin >> S;
int n = S.length();
int dp[n + 1];
memset(dp, 0x3f, sizeof dp);
dp[0] = 0;
for (int i = 0; i < n; i++) {
int digit = S[i] - '0';
for (int j = max(0, i - 2); j < i; j++) {
int sum = 0;
for (int k = j; k <= i; k++) {
sum += S[k] - '0';
}
if (sum % 3 == 0) {
int cost = digit;
for (int k = j; k <= i; k++) {
cost = min(cost, S[k] - '0');
//@allcoding1
}
dp[i + 1] = min(dp[i + 1], dp[j] + cost);
}
}
}
cout << dp[n] << endl;
return 0;
}
C++
84 444
+1Python
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1_official
@allcoding1_official
discussion group:- @Infosys_examAns
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
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