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allcoding1_official

allcoding1_official

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📈 Analytical overview of Telegram channel allcoding1_official

Channel allcoding1_official (@allcoding1_official) in the English language segment is an active participant. Currently, the community unites 85 483 subscribers, ranking 1 507 in the Technologies & Applications category and 3 480 in the India region.

📊 Audience metrics and dynamics

Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 85 483 subscribers.

According to the latest data from 24 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -1 369 over the last 30 days and by -35 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 2.60%. Within the first 24 hours after publication, content typically collects 0.55% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 2 222 views. Within the first day, a publication typically gains 474 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 3.
  • Thematic interests: Content is focused on key topics such as dsa, stack, namaste, javascript, dev.

📝 Description and content policy

Channel description not provided.

Thanks to the high frequency of updates (latest data received on 25 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

85 483
Subscribers
-3524 hours
-2687 days
-1 36930 days
Posts Archive
function ArithGeoll(arr) { let arith = true; let d = Math.abs(arr[0]- arr[1]); for (let i = 2; i < arr.length; i++) { if (
function ArithGeoll(arr) { let arith = true; let d = Math.abs(arr[0]- arr[1]); for (let i = 2; i < arr.length; i++) { if (Math.abs(arr[i] - arr[i - 1]) !== d) { arith = false; } } if (arith) { return "Arithmetic"; } let geo = true; d = arr[1]/ arr[0]; for (let i = 2; i < arr.length; i++) if (Math.abs(arr[i] / arr[i- { 1]) !== d) { geo = false; } } if (geo) { return "Geometric"; } if (larith && !geo) { return "-1"; } }

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function ArithGeoll(arr) { let arith = true; let d = Math.abs(arr[0]- arr[1]); for (let i = 2; i < arr.length; i++) { if (Math.abs(arr[i] - arr[i - 1]) !== d) { arith = false; } } if (arith) { return "Arithmetic"; } let geo = true; d = arr[1]/ arr[0]; for (let i = 2; i < arr.length; i++) if (Math.abs(arr[i] / arr[i- { 1]) !== d) { geo = false; } }

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500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intel
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500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources ( English🏴󐁧󐁢󐁥󐁮󐁧󐁿 , French🇨🇵 , German🇩🇪 ) ₹300 Contact:- @meterials_available

struct Request { string id; string start_time; string end_time; }; bool compare(Request a, Request b) { return a.start_time &
struct Request { string id; string start_time; string end_time; }; bool compare(Request a, Request b) { return a.start_time < b.start_time; } int solve(vector requests) { sort(requests.begin(), requests.end(), compare); int max_concurrent = 0; int current_concurrent = 0; string current_end_time = "00:00:00"; for (Request request : requests) { if (request.start_time >= current_end_time) { current_concurrent--; } else { current_concurrent++; if (current_concurrent > max_concurrent) { max_concurrent = current_concurrent; } } if (request.end_time > current_end_time) { current_end_time = request.end_time; } } return max_concurrent; }

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500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intel
+2
500 TB Tutorials + Books + Courses + Trainings + Workshops + Educational Resources 🔹Data science 🔹Python 🔹Artificial Intelligence 🔹AWS Certified 🔹Cloud 🔹BIG DATA 🔹Data Analytics 🔹BI 🔹Google Cloud Platform 🔹IT Training 🔹MBA 🔹Machine Learning 🔹Deep Learning 🔹Ethical Hacking 🔹SPSS 🔹Statistics 🔹Data Base 🔹Learning language resources ( English🏴󐁧󐁢󐁥󐁮󐁧󐁿 , French🇨🇵 , German🇩🇪 ) ₹300 Contact:- @meterials_available

sticker.webp0.13 KB

#define vv(a) vector<vector<int>>(a) int solve(int n, int m, vector<vector<int>> &a) { vv(right)(n, vector<int>(m, 0)); vv(down)(n, vector<int>(m, 0)); vv(left)(n, vector<int>(m, 0)); for (int i = 0; i < n; i++) { int cnt = 0; for (int j = m - 1; j >= 0; j--) { right[i][j] = cnt; if (a[i][j] == 1) cnt++; } } for (int i = 0; i < n; i++) { int cnt = 0; for (int j = 0; j < m; j++) { left[i][j] = cnt; if (a[i][j] == 1) cnt++; } } for (int j = 0; j < m; j++) { int cnt = 0; for (int i = n - 1; i >= 0; i--) { down[i][j] = cnt; if (a[i][j] == 1) cnt++; } } int ans = 0; for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { if (a[i][j] == 1) { ans += (right[i][j] * down[i][j]); ans += (left[i][j] * down[i][j]); } } } return ans; } C++ Telegram:- @allcoding1_official

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URL Hashing
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URL Hashing

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int solve(int n, vector&amp; arr) { &nbsp;&nbsp;&nbsp; while (arr.size() &gt; 1) { &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
int solve(int n, vector& arr) {     while (arr.size() > 1) {         int len = INT_MAX;         int idx = -1;         for (int i = 0; i < arr.size() - 1; ++i) {             int d = arr[i + 1];             if (d == 0 || arr[i] == 0) {                 continue;             }             int r = min(arr[i] % d, d % arr[i]);             if (r < len) {                 len = r;                 idx = i;             }         }         if (idx == -1) {             break;         }         int d = arr[idx + 1];         if (d != 0) {             arr[idx] = min(arr[idx] % d, d % arr[idx]);         }         arr.erase(arr.begin() + idx + 1);     }     return arr.size(); } Women Day Mathematics Challenge Telegram:-

#include <iostream>
#include <sql.h>
#include <sqlext.h>

#define MAX_QUERY_LEN 1000

int main() {
    // Declare variables for ODBC connection
    SQLHENV henv;
    SQLHDBC hdbc;
    SQLHSTMT hstmt;
    SQLRETURN retcode;

    // Allocate environment handle
    retcode = SQLAllocHandle(SQL_HANDLE_ENV, SQL_NULL_HANDLE, &amp;henv);

    // Set the ODBC version to use
    retcode = SQLSetEnvAttr(henv, SQL_ATTR_ODBC_VERSION, (SQLPOINTER)SQL_OV_ODBC3, 0);

    // Allocate connection handle
    retcode = SQLAllocHandle(SQL_HANDLE_DBC, henv, &amp;hdbc);

    // Connect to the data source
    retcode = SQLConnect(hdbc, (SQLCHAR*)"your_datasource", SQL_NTS, (SQLCHAR*)"username", SQL_NTS, (SQLCHAR*)"password", SQL_NTS);

    // Allocate statement handle
    retcode = SQLAllocHandle(SQL_HANDLE_STMT, hdbc, &amp;hstmt);

    // Prepare the SQL query
    char query[MAX_QUERY_LEN] = "SELECT DATE_FORMAT(date_column, '%Y-%m') AS month_year, source, COUNT(*) AS total_number FROM your_table WHERE YEAR(date_column) = '2022' AND (source = 'Jobs' OR source = 'Freelancers') GROUP BY month_year, source ORDER BY month_year ASC, source ASC";

    // Execute the SQL query
    retcode = SQLExecDirect(hstmt, (SQLCHAR*)query, SQL_NTS);

    // Fetch and process the results
    while (SQLFetch(hstmt) == SQL_SUCCESS) {
        // Process the retrieved data here
    }

    // Free the handles
    SQLFreeHandle(SQL_HANDLE_STMT, hstmt);
    SQLDisconnect(hdbc);
    SQLFreeHandle(SQL_HANDLE_DBC, hdbc);
    SQLFreeHandle(SQL_HANDLE_ENV, henv);

    return 0;
}
Please note that the above code provides a basic framework for executing SQL queries in C++. You will need to replace your_datasource, username, password, your_table, and date_column with your actual database connection details, table name, and column name.

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