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不要被骗子欺骗!Telemetrio 会找到并标记这些频道 👉 如果想查看标记,请订阅

allcoding1_official

allcoding1_official

前往频道在 Telegram

📈 Telegram 频道 allcoding1_official 的分析概览

频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 78 821 名订阅者,在 技术与应用 类别中位列第 1 627,并在 印度 地区排名第 3 772 位。

📊 受众指标与增长动态

自 невідомо 创建以来,项目保持高速增长,吸引了 78 821 名订阅者。

根据 29 十月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 610,过去 24 小时变化为 -51,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 2.18%。内容发布后 24 小时内通常能获得 0.61% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 1 718 次浏览,首日通常累积 478 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 0。
  • 主题关注点: 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。

📝 描述与内容策略

尚未提供频道描述。

凭借高频更新(最新数据采集于 30 十月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。

78 821
订阅者
-5124 小时
-3677 天
-1 61030 天
帖子存档
photo content
+1

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8) H

7) 3

6) both I and 3

1) BUSMUF 2) KXVTL 3) D 4) CANNOT BE DETERMINED 5) E WA SITTING FRONT OF I

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+8
All this 300 rupees only Contact:- @meterials_available

if not intervals:         return 0         intervals.sort(ke
if not intervals:
        return 0
    
    intervals.sort(key=lambda x: x[0])  # Sort intervals based on start points
    merged_intervals = [intervals[0]]  # Initialize merged intervals with the first interval
    
    for interval in intervals[1:]:
        prev_interval = merged_intervals[-1]
        
        if interval[0] <= prev_interval[1]:  # If overlapping with previous interval
            prev_interval[1] = max(prev_interval[1], interval[1])  # Merge intervals
        else:
            merged_intervals.append(interval)  # Add non-overlapping interval
    
    total_length = sum(end - start for start, end in merged_intervals)
    return total_length

# Example usage:
intervals = [(1, 3), (2, 6), (8, 10), (15, 18)]
total_length_covered = merge_intervals(intervals)
print("Total length covered after merging overlapping intervals:", total_length_covered)