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Code With Virus

Code With Virus

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Coding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ‘ˆ Accenture @Accenturavirustech πŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆ

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πŸ“ˆ Analytical overview of Telegram channel Code With Virus

Channel Code With Virus (@codewithvirus) in the English language segment is an active participant. Currently, the community unites 10 559 subscribers, ranking 10 501 in the Technologies & Applications category and 43 593 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 10 559 subscribers.

According to the latest data from 04 December, 2025, the channel demonstrates stable activity. Although there has been a change in the number of participants by -87 over the last 30 days and by 0 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 0%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 0 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œCoding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ‘ˆ Accenture @Accenturavirustech πŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆβ€

Thanks to the high frequency of updates (latest data received on 05 December, 2025), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

10 559
Subscribers
No data24 hours
-227 days
-8730 days
Posts Archive
If you want to start at 11:08 am they it's also okay but Start your exam before 11:10 am

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And if you don't know Then send me your full question with proper input and output And make sure it is visible Then i will provide you solution πŸ”₯

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Given a string S, check if it is palindrome or not. Example 1: Input: S = "abba" Output: 1 Explanation: S is a palindrome Example 2: Input: S = "abc" Output: 0 Explanation: S is not a palindrome

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Coding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ”΄ πŸ‘ˆ Accenture. @AccenturavirustechπŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆ Infosys. @Infosyavirustech πŸ‘ˆ TCS. @TCSavirustech πŸ‘ˆ Amazon. @Amazonavirustech πŸ‘ˆ

Coding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ”΄ πŸ‘ˆ Accenture. @AccenturavirustechπŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆ Infosys. @Infosyavirustech πŸ‘ˆ TCS. @TCSavirustech πŸ‘ˆ Amazon. @Amazonavirustech πŸ‘ˆ

Guys if you have any query then you can Also asked to Payal mam she is Also expert πŸ”₯ https://www.instagram.com/payalpatel_85/

Coding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ”΄ πŸ‘ˆ Accenture. @AccenturavirustechπŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆ Infosys. @Infosyavirustech πŸ‘ˆ TCS. @TCSavirustech πŸ‘ˆ Amazon. @Amazonavirustech πŸ‘ˆ

import java.util.Scanner; public class Solution { public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc = new Scanner(System.in); int n = 4; // search on telegram @codewithvirus Crop codewithvirus[] = new Crop[n]; for (int i = 0; i < codewithvirus.length; i++) { String ctype = sc.nextLine(); String cname = sc.nextLine(); String hmonth = sc.nextLine(); double period = sc.nextDouble(); sc.nextLine(); codewithvirus[i] = new Crop(ctype, cname, hmonth, period); } String fs1 = sc.nextLine(); double fs2 = sc.nextDouble(); double ans1 = codewithvirus2(codewithvirus, fs1); if (ans1 != 0) { System.out.println(ans1); } else { System.out.println("There is no such Crop available."); } Crop temp = null; for (int i = 0; i < codewithvirus.length; i++) { for (int j = i + 1; j < codewithvirus.length; j++) { if (codewithvirus[i].getPeriod() > codewithvirus[j].getPeriod()) { temp = codewithvirus[i]; codewithvirus[i] = codewithvirus[j]; codewithvirus[j] = temp; } } } int c = 0; for (int i = 0; i < codewithvirus.length; i++) { if (codewithvirus[i].getPeriod() <= fs2) { System.out.println(codewithvirus[i].getCname()); System.out.println(codewithvirus[i].getHmonth()); c++; } } if (c == 0) { System.out.println("No Crop found."); } } public static double codewithvirus2(Crop[] d, String s) { double p = 0; int ab = 0; for (int i = 0; i < d.length; i++) { if (d[i].getCtype().equalsIgnoreCase(s)) { p += d[i].getPeriod(); ab++; } } if (ab == 0) return 0; return p / ab; } } class Crop { private String ctype; private String cname; private String hmonth; private double period; public Crop(String ctype, String cname, String hmonth, double period) { super(); this.ctype = ctype; this.cname = cname; this.hmonth = hmonth; this.period = period; } public String getCtype() { return ctype; } public void setCtype(String ctype) { this.ctype = ctype; } public String getCname() { return cname; } public void setCname(String cname) { this.cname = cname; } public String getHmonth() { return hmonth; } public void setHmonth(String hmonth) { this.hmonth = hmonth; } public double getPeriod() { return period; } public void setPeriod(double period) { this.period = period; } } ///////////////////// UNIX ///////////////////// /* * awk 'BEGIN{FS=":", deep=0;} { if(tolower($3)=="may") { print $0; deep++;} } * END { if(deep==0){ print "No record found with matching criteria"; } }' * * */ ////////////////////////////////////////////////

2nd function in You need to print Crop name and months Who are bolenge to less and equal to given a periods moths

First function in you need to print average. It's very very easy

Guys asked me to logic I will tell you But full code ☹️

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