Code With Virus
Kanalga Telegramβda oβtish
Coding channel @codewithvirus. π Main group @avirustech π Accenture @Accenturavirustech π IBM. @IBMavirustech π Tech Mahindra. @TechMavirustech π
Ko'proq ko'rsatishπ Telegram kanali Code With Virus analitikasi
Code With Virus (@codewithvirus) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 10 559 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 10 501-o'rinni va Hindiston mintaqasida 43 593-o'rinni egallagan.
π Auditoriya koβrsatkichlari va dinamika
Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ sanasidan buyon loyiha tez oβsib, 10 559 obunachiga ega boβldi.
04 Dekabr, 2025 dagi oxirgi maβlumotlarga koβra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -87 ga, soβnggi 24 soatda esa 0 ga oβzgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya oβrtacha 0% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni toβplaydi.
- Post qamrovi: Har bir post oβrtacha 0 marta koβriladi; birinchi sutkada odatda 0 ta koβrish yigβiladi.
- Reaksiyalar va oβzaro taβsir: Auditoriya faol: har bir postga oβrtacha 0 ta reaksiya keladi.
π Tavsif va kontent siyosati
Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida taβriflaydi:
βCoding channel @codewithvirus. π
Main group @avirustech π
Accenture @Accenturavirustech π
IBM. @IBMavirustech π
Tech Mahindra. @TechMavirustech πβ
Yuqori yangilanish chastotasi (oxirgi maβlumot 05 Dekabr, 2025 da olingan) sababli kanal doimo dolzarb va katta qamrovli boβlib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim taβsir nuqtasiga aylantirishini koβrsatadi.
10 559
Obunachilar
Ma'lumot yo'q24 soatlar
-227 kun
-8730 kun
Postlar arxiv
10 559
If you want to start at 11:08 am they it's also okay
but
Start your exam before 11:10 am
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And if you don't know
Then send me your full question with proper input and output
And make sure it is visible
Then i will provide you solution π₯
10 559
Guys in IBM exam in you need to pass at least 3 test case if you passed at least 3 test case then you are elegbal for next round π₯
Os try to paas at least 3 test case
10 559
You have IBM exam on 4 May π€ you need help in coding section
Then Join our IBM group
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄
10 559
You have IBM exam on 4 May π€ you need help in coding section
Then Join our IBM group
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄
10 559
Given a string S, check if it is palindrome or not.
Example 1:
Input: S = "abba"
Output: 1
Explanation: S is a palindrome
Example 2:
Input: S = "abc"
Output: 0
Explanation: S is not a palindrome
10 559
You have IBM exam on 4 May π€ you need help in coding section
Then Join our IBM group
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π₯π₯ @IBMavirustech π₯π₯
π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄
10 559
Coding channel @codewithvirus. π
Main group @avirustech π΄ π
Accenture. @Accenturavirustechπ
IBM. @IBMavirustech π
Tech Mahindra. @TechMavirustech π
Infosys. @Infosyavirustech π
TCS. @TCSavirustech π
Amazon. @Amazonavirustech π
10 559
Coding channel @codewithvirus. π
Main group @avirustech π΄ π
Accenture. @Accenturavirustechπ
IBM. @IBMavirustech π
Tech Mahindra. @TechMavirustech π
Infosys. @Infosyavirustech π
TCS. @TCSavirustech π
Amazon. @Amazonavirustech π
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Guys if you have any query then you can Also asked to Payal mam she is Also expert π₯
https://www.instagram.com/payalpatel_85/
10 559
Coding channel @codewithvirus. π
Main group @avirustech π΄ π
Accenture. @Accenturavirustechπ
IBM. @IBMavirustech π
Tech Mahindra. @TechMavirustech π
Infosys. @Infosyavirustech π
TCS. @TCSavirustech π
Amazon. @Amazonavirustech π
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import java.util.Scanner;
public class Solution {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner sc = new Scanner(System.in);
int n = 4;
// search on telegram @codewithvirus
Crop codewithvirus[] = new Crop[n];
for (int i = 0; i < codewithvirus.length; i++) {
String ctype = sc.nextLine();
String cname = sc.nextLine();
String hmonth = sc.nextLine();
double period = sc.nextDouble();
sc.nextLine();
codewithvirus[i] = new Crop(ctype, cname, hmonth, period);
}
String fs1 = sc.nextLine();
double fs2 = sc.nextDouble();
double ans1 = codewithvirus2(codewithvirus, fs1);
if (ans1 != 0) {
System.out.println(ans1);
} else {
System.out.println("There is no such Crop available.");
}
Crop temp = null;
for (int i = 0; i < codewithvirus.length; i++) {
for (int j = i + 1; j < codewithvirus.length; j++) {
if (codewithvirus[i].getPeriod() > codewithvirus[j].getPeriod()) {
temp = codewithvirus[i];
codewithvirus[i] = codewithvirus[j];
codewithvirus[j] = temp;
}
}
}
int c = 0;
for (int i = 0; i < codewithvirus.length; i++) {
if (codewithvirus[i].getPeriod() <= fs2) {
System.out.println(codewithvirus[i].getCname());
System.out.println(codewithvirus[i].getHmonth());
c++;
}
}
if (c == 0) {
System.out.println("No Crop found.");
}
}
public static double codewithvirus2(Crop[] d, String s) {
double p = 0;
int ab = 0;
for (int i = 0; i < d.length; i++) {
if (d[i].getCtype().equalsIgnoreCase(s)) {
p += d[i].getPeriod();
ab++;
}
}
if (ab == 0)
return 0;
return p / ab;
}
}
class Crop {
private String ctype;
private String cname;
private String hmonth;
private double period;
public Crop(String ctype, String cname, String hmonth, double period) {
super();
this.ctype = ctype;
this.cname = cname;
this.hmonth = hmonth;
this.period = period;
}
public String getCtype() {
return ctype;
}
public void setCtype(String ctype) {
this.ctype = ctype;
}
public String getCname() {
return cname;
}
public void setCname(String cname) {
this.cname = cname;
}
public String getHmonth() {
return hmonth;
}
public void setHmonth(String hmonth) {
this.hmonth = hmonth;
}
public double getPeriod() {
return period;
}
public void setPeriod(double period) {
this.period = period;
}
}
///////////////////// UNIX /////////////////////
/*
* awk 'BEGIN{FS=":", deep=0;} { if(tolower($3)=="may") { print $0; deep++;} }
* END { if(deep==0){ print "No record found with matching criteria"; } }'
*
*
*/
////////////////////////////////////////////////
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2nd function in
You need to print
Crop name and months
Who are bolenge to less and equal to given a periods moths
