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Code With Virus

Code With Virus

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Coding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ‘ˆ Accenture @Accenturavirustech πŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆ

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India43 593Technologies & Applications10 501

πŸ“ˆ Analytical overview of Telegram channel Code With Virus

Channel Code With Virus (@codewithvirus) in the English language segment is an active participant. Currently, the community unites 10 559 subscribers, ranking 10 501 in the Technologies & Applications category and 43 593 in the India region.

πŸ“Š Audience metrics and dynamics

Since its creation on Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 10 559 subscribers.

According to the latest data from 04 December, 2025, the channel demonstrates stable activity. Although there has been a change in the number of participants by -87 over the last 30 days and by 0 over the last 24 hours, overall reach remains high.

  • Verification status: Not verified
  • Engagement rate (ER): The average audience engagement rate is 0%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
  • Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 0 views.
  • Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.

πŸ“ Description and content policy

The author describes the resource as a platform for expressing subjective opinions:
β€œCoding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ‘ˆ Accenture @Accenturavirustech πŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆβ€

Thanks to the high frequency of updates (latest data received on 05 December, 2025), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.

10 559
Subscribers
No data24 hours
-227 days
-8730 days
Posts Archive
Code With Virus
Code With Virus
10 559
photo content

Code With Virus
Code With Virus
10 559
photo content

Code With Virus
Code With Virus
10 559
Or same karo same question

Code With Virus
Code With Virus
10 559
Don't send question pic guys I Also Don't want to post solution

Code With Virus
Code With Virus
10 559
During a exam if you faced any error then don't text in group Like I get error Directly show me your error PIC Then i will understand where you get error

Code With Virus
Code With Virus
10 559
Gus start your exam and fill your all details

Code With Virus
Code With Virus
10 559
And if you don't know How to pass open test case then don't Worry Send me proper question with input and output make sure your questions is visible for me πŸ”₯

Code With Virus
Code With Virus
10 559
If you want to qualify IBM coding exam then just try to pass open test case That's it's if you passed all open test case and your at least 3 test case passed then you are eligible for next round πŸ”₯

Code With Virus
Code With Virus
10 559
How many people today have IBM exam ? πŸ€”

Code With Virus
Code With Virus
10 559
You have IBM exam on 18 May πŸ€” you need help in coding section Then Join our IBM group πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄

Code With Virus
Code With Virus
10 559
You have IBM exam on 18 May πŸ€” you need help in coding section Then Join our IBM group πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄

Code With Virus
Code With Virus
10 559
Coding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ”΄ πŸ‘ˆ Accenture. @AccenturavirustechπŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆ Infosys. @Infosyavirustech πŸ‘ˆ TCS. @TCSavirustech πŸ‘ˆ Amazon. @Amazonavirustech πŸ‘ˆ

Code With Virus
Code With Virus
10 559

Code With Virus
Code With Virus
10 559

Code With Virus
Code With Virus
10 559
Coding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ”΄ πŸ‘ˆ Accenture. @AccenturavirustechπŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆ Infosys. @Infosyavirustech πŸ‘ˆ TCS. @TCSavirustech πŸ‘ˆ Amazon. @Amazonavirustech πŸ‘ˆ

Code With Virus
Code With Virus
10 559
/* There are N people standing in a circle. On every pass, the kth person was killed. This cycle continues till only one person remains alive. Find out the alive person. TC -> o(N) SC -> o(N) */ #include <bits/stdc++.h> using namespace std; void alive_last_person(vector<int> person, int kth_number_killed, int index) { if (person.size() == 1) { cout << person[0]; return; } // finding in vector which person killed first index = ((index + kth_number_killed) % person.size()); // removing first person which personl killed first person.erase(person.begin() + index); // here im using recursive call for number_of_person -1 alive_last_person(person, kth_number_killed, index); } int main() { int number_of_person, kth_number_killed; cin >> number_of_person >> kth_number_killed; kth_number_killed--; // staring porint int index = 0; // in vector im filling all person postion vector<int> person; for (int i = 1; i <= number_of_person; i++) { person.push_back(i); } alive_last_person(person, kth_number_killed, index); }

Code With Virus
Code With Virus
10 559
Coding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ”΄ πŸ‘ˆ Accenture. @AccenturavirustechπŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆ Infosys. @Infosyavirustech πŸ‘ˆ TCS. @TCSavirustech πŸ‘ˆ Amazon. @Amazonavirustech πŸ‘ˆ

Code With Virus
Code With Virus
10 559

Code With Virus
Code With Virus
10 559

Code With Virus
Code With Virus
10 559