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Firibgarlarga uchmang! Telemetrio bunday kanallarni topadi va belgilaydi πŸ‘‰ Belgini koβ€˜rmoqchi boβ€˜lsangiz, obuna boβ€˜ling

Code With Virus

Code With Virus

Kanalga Telegram’da oβ€˜tish

Coding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ‘ˆ Accenture @Accenturavirustech πŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆ

Ko'proq ko'rsatish
Hindiston43 593Texnologiyalar & Aralashmalar10 501

πŸ“ˆ Telegram kanali Code With Virus analitikasi

Code With Virus (@codewithvirus) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 10 559 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 10 501-o'rinni va Hindiston mintaqasida 43 593-o'rinni egallagan.

πŸ“Š Auditoriya koβ€˜rsatkichlari va dinamika

Π½Π΅Π²Ρ–Π΄ΠΎΠΌΠΎ sanasidan buyon loyiha tez oβ€˜sib, 10 559 obunachiga ega boβ€˜ldi.

04 Dekabr, 2025 dagi oxirgi ma’lumotlarga koβ€˜ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -87 ga, soβ€˜nggi 24 soatda esa 0 ga oβ€˜zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya oβ€˜rtacha 0% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni toβ€˜playdi.
  • Post qamrovi: Har bir post oβ€˜rtacha 0 marta koβ€˜riladi; birinchi sutkada odatda 0 ta koβ€˜rish yigβ€˜iladi.
  • Reaksiyalar va oβ€˜zaro ta’sir: Auditoriya faol: har bir postga oβ€˜rtacha 0 ta reaksiya keladi.

πŸ“ Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
β€œCoding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ‘ˆ Accenture @Accenturavirustech πŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆβ€

Yuqori yangilanish chastotasi (oxirgi ma’lumot 05 Dekabr, 2025 da olingan) sababli kanal doimo dolzarb va katta qamrovli boβ€˜lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini koβ€˜rsatadi.

10 559
Obunachilar
Ma'lumot yo'q24 soatlar
-227 kun
-8730 kun
Postlar arxiv
Code With Virus
Code With Virus
10 559
photo content

Code With Virus
Code With Virus
10 559
photo content

Code With Virus
Code With Virus
10 559
Or same karo same question

Code With Virus
Code With Virus
10 559
Don't send question pic guys I Also Don't want to post solution

Code With Virus
Code With Virus
10 559
During a exam if you faced any error then don't text in group Like I get error Directly show me your error PIC Then i will understand where you get error

Code With Virus
Code With Virus
10 559
Gus start your exam and fill your all details

Code With Virus
Code With Virus
10 559
And if you don't know How to pass open test case then don't Worry Send me proper question with input and output make sure your questions is visible for me πŸ”₯

Code With Virus
Code With Virus
10 559
If you want to qualify IBM coding exam then just try to pass open test case That's it's if you passed all open test case and your at least 3 test case passed then you are eligible for next round πŸ”₯

Code With Virus
Code With Virus
10 559
How many people today have IBM exam ? πŸ€”

Code With Virus
Code With Virus
10 559
You have IBM exam on 18 May πŸ€” you need help in coding section Then Join our IBM group πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄

Code With Virus
Code With Virus
10 559
You have IBM exam on 18 May πŸ€” you need help in coding section Then Join our IBM group πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”₯πŸ”₯ @IBMavirustech πŸ”₯πŸ”₯ πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄πŸ”΄

Code With Virus
Code With Virus
10 559
Coding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ”΄ πŸ‘ˆ Accenture. @AccenturavirustechπŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆ Infosys. @Infosyavirustech πŸ‘ˆ TCS. @TCSavirustech πŸ‘ˆ Amazon. @Amazonavirustech πŸ‘ˆ

Code With Virus
Code With Virus
10 559

Code With Virus
Code With Virus
10 559

Code With Virus
Code With Virus
10 559
Coding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ”΄ πŸ‘ˆ Accenture. @AccenturavirustechπŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆ Infosys. @Infosyavirustech πŸ‘ˆ TCS. @TCSavirustech πŸ‘ˆ Amazon. @Amazonavirustech πŸ‘ˆ

Code With Virus
Code With Virus
10 559
/* There are N people standing in a circle. On every pass, the kth person was killed. This cycle continues till only one person remains alive. Find out the alive person. TC -> o(N) SC -> o(N) */ #include <bits/stdc++.h> using namespace std; void alive_last_person(vector<int> person, int kth_number_killed, int index) { if (person.size() == 1) { cout << person[0]; return; } // finding in vector which person killed first index = ((index + kth_number_killed) % person.size()); // removing first person which personl killed first person.erase(person.begin() + index); // here im using recursive call for number_of_person -1 alive_last_person(person, kth_number_killed, index); } int main() { int number_of_person, kth_number_killed; cin >> number_of_person >> kth_number_killed; kth_number_killed--; // staring porint int index = 0; // in vector im filling all person postion vector<int> person; for (int i = 1; i <= number_of_person; i++) { person.push_back(i); } alive_last_person(person, kth_number_killed, index); }

Code With Virus
Code With Virus
10 559
Coding channel @codewithvirus. πŸ‘ˆ Main group @avirustech πŸ”΄ πŸ‘ˆ Accenture. @AccenturavirustechπŸ‘ˆ IBM. @IBMavirustech πŸ‘ˆ Tech Mahindra. @TechMavirustech πŸ‘ˆ Infosys. @Infosyavirustech πŸ‘ˆ TCS. @TCSavirustech πŸ‘ˆ Amazon. @Amazonavirustech πŸ‘ˆ

Code With Virus
Code With Virus
10 559

Code With Virus
Code With Virus
10 559

Code With Virus
Code With Virus
10 559