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Channel Mathematics Spmnetic!β’ π’ (@mathematicspmnotes) in the Malay language segment is an active participant. Currently, the community unites 35 104 subscribers, ranking 5 403 in the Education category and 944 in the Malaysia region.
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Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 35 104 subscribers.
According to the latest data from 01 July, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 570 over the last 30 days and by 26 over the last 24 hours, overall reach remains high.
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- Post reach: On average, each post receives 2 019 views. Within the first day, a publication typically gains 1 779 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 11.
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The author describes the resource as a platform for expressing subjective opinions:
βThis channel belongs to @thespmneticofficial, and a platform for sharing notes and exercises π€π»
For any enquiries, please directly ask in our discussion group β¨β
Thanks to the high frequency of updates (latest data received on 02 July, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
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jomm vote kejapp. korang nak tahu result by check online or pergi sekolah ? and drop comment why u choose that
I am sorry for teaching wrongly, the correct answer to this question is , you cannot determine if the object is accelerating or decelerating , because the initial velocity of object is not given, if lets say the initial velocity was -3ms-1, or in words 3 meters per second to the left(assuming right as positive and left as negative) then it would be deceleration because acceleration works like a push force. lets say u are moving to the right with speed of 2ms-1 and if your acceleration is 2 ms-2, then its acceleration because the push direction and the direction of your initial motion is same, but if lets say the u are moving left with the speed of 2ms-1 and if your acceleration is 2 ms-2, then its deceleration because the push direction and the direction of your initial motion is not same, so to determine if an object is accelerating or decelerating, we have a formula av>0 means acceleration or av<0 means deceleration, where a is acceleration and v is velocity.
Saya minta maaf kerana sebelum ini tersilap mengajar. Jawapan yang betul untuk soalan ini ialah: kita tidak boleh tentukan sama ada objek itu sedang memecut atau mengalami nyahpecutan kerana halaju awal objek tidak diberikan.
Sebabnya, pecutan bertindak seperti daya tolakan (push force). Katakanlah halaju awal ialah -3 ms-1 (iaitu bergerak 3 meter sesaat ke kiri, jika kita anggap kanan sebagai positif dan kiri sebagai negatif):
Jika kita bergerak ke kanan dengan halaju 2 ms-1 dan pecutan kita juga 2 ms-2 (ke kanan sebab anggap kanan sebagai positif dan kiri sebagai negatifi),
maka itu adalah Pecutan. Ini kerana arah tolakan dan arah gerakan asal adalah sama.
Jika kita bergerak ke kiri dengan halaju 2 ms-1 tetapi pecutan kita adalah 2 ms-2 (ke kanan), maka itu adalah Nyahpecutan. Ini kerana arah tolakan bertentangan dengan arah gerakan asal, menyebabkan objek menjadi perlahan.
Jadi, untuk menentukan sama ada sesuatu objek itu memecut atau mengalami nyahpecutan, kita gunakan formula ini:
av > 0 bermaksud Pecutan (Laju bertambah).
av < 0 bermaksud Nyahpecutan (Laju berkurang).
Di mana a ialah pecutan dan v ialah halaju.
Asslamualaikum dan Hai esok Siapa nak ilmu free matematik tingkatan 4 bab 2 dalam google meet.
Repost from AddMath Spmnetic!β’β‘οΈ
I am sorry for teaching wrongly, the correct answer to this question is , you cannot determine if the object is accelerating or decelerating , because the initial velocity of object is not given, if lets say the initial velocity was -3ms-1, or in words 3 meters per second to the left(assuming right as positive and left as negative) then it would be deceleration because acceleration works like a push force. lets say u are moving to the right with speed of 2ms-2 and if your acceleration is 2 ms-2, then its acceleration because the push direction and the direction of your initial motion is same, but if lets say the u are moving left with the speed of 2ms-1 and if your acceleration is 2 ms-2, then its deceleration because the push direction and the direction of your initial motion is not same, so to determine if an object is accelerating or decelerating, we have a formula av>0 means acceleration or av<0 means deceleration, where a is acceleration and v is velocity.
Saya minta maaf kerana sebelum ini tersilap mengajar. Jawapan yang betul untuk soalan ini ialah: kita tidak boleh tentukan sama ada objek itu sedang memecut atau mengalami nyahpecutan kerana halaju awal objek tidak diberikan.
Sebabnya, pecutan bertindak seperti daya tolakan (push force). Katakanlah halaju awal ialah -3 ms-1 (iaitu bergerak 3 meter sesaat ke kiri, jika kita anggap kanan sebagai positif dan kiri sebagai negatif):
Jika kita bergerak ke kanan dengan halaju 2 ms-1 dan pecutan kita juga 2 ms-2 (ke kanan sebab anggap kanan sebagai positif dan kiri sebagai negatifi),
maka itu adalah Pecutan. Ini kerana arah tolakan dan arah gerakan asal adalah sama.
Jika kita bergerak ke kiri dengan halaju 2 ms-1 tetapi pecutan kita adalah 2 ms-2 (ke kanan), maka itu adalah Nyahpecutan. Ini kerana arah tolakan bertentangan dengan arah gerakan asal, menyebabkan objek menjadi perlahan.
Jadi, untuk menentukan sama ada sesuatu objek itu memecut atau mengalami nyahpecutan, kita gunakan formula ini:
av > 0 bermaksud Pecutan (Laju bertambah).
av < 0 bermaksud Nyahpecutan (Laju berkurang).
Di mana a ialah pecutan dan v ialah halaju.
Hi guys. Min finally siap nota pendek bagi Chapter 5 Form 5. Jika ada soalan berkaitan nota ini, boleh tanya. π€©
