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All coding Solution
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π Analytical overview of Telegram channel All coding Solution
Channel All coding Solution (@allcodingsolution) in the English language segment is an active participant. Currently, the community unites 11 220 subscribers, ranking 17 985 in the Education category and 37 554 in the India region.
π Audience metrics and dynamics
Since its creation on Π½Π΅Π²ΡΠ΄ΠΎΠΌΠΎ, the project has demonstrated rapid growth, gathering an audience of 11 220 subscribers.
According to the latest data from 07 June, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by -154 over the last 30 days and by -7 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 1.45%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
- Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 0 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
π Description and content policy
Channel description not provided.
Thanks to the high frequency of updates (latest data received on 08 June, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Education category.
11 220
Subscribers
-724 hours
-297 days
-15430 days
Posts Archive
11 227
class Food:
def init(self,name,protien,fat,carb):
self.name=name
self.protien=protien
self.fat=fat
self.carb=carb
class Nutrition:
def init(self,status,lfood):
self.status=status
self.lfood=lfood
def setEnergy(self):
result=[]
for i in lfood:
for k,v in status.items():
temp=(i.protien+i.fat+i.carb)
if(temp>=v[0] and temp<=v[1]):
result.append(str(i.name)+" - "+str(temp)+" - "+k)
if(len(result)==0):
return None
else:
return result
def getEnergyRichFood(self,checkenergy):
ans=[]
for i in lfood:
temp=(i.protien+i.fat+i.carb)
if(temp<=checkenergy):
ans.append(i.name+" : "+str(temp))
if(len(ans)==0):
return None
else:
return ans
n=int(input())
lfood=[]
for i in range(n):
name=input()
protien=float(input())
fat=float(input())
carb=float(input())
lfood.append(Food(name,protien,fat,carb))
status={}
cnt=int(input())
for i in range(cnt):
st=input()
l=[]
l.append(int(input()))
l.append(int(input()))
status[st]=tuple(l)
checkenergy=int(input())
obj=Nutrition(status,lfood)
result=obj.setEnergy()
ans=obj.getEnergyRichFood(checkenergy)
if(result!=None):
print("Energy of Food:")
for i in result:
print(i)
if(ans!=None):
print("Food within given criteria:")
for i in ans:
print(i)
else:
print("No Food Found")
Food code
python
Telegram- https://t.me/Allcodingsolution
11 227
awk ' BEGIN{FS=#;count=0;}{
if($4>300){
count=count+$3;}
}END{
print "Total count:" count;}
else
{
print "No soap found with cost above 300";
}
}'
Soap management unix
Telegram- https://t.me/Allcodingsolution
11 227
class Employee:
def _init_(self,n,d,s,lb):
self.name=n
self.designation=d
self.salary=s
self.leavesbalance=lb
class Organization:
def _init_(self,elist):
self.employee_list=elist
def display_leaves(self,name):
for i in self.employee_list:
if i.name==name:
for a,b in i.leavesbalance.items():
print(a,":",b)
def checkLeaveEligibility(self,ename,tl,nol):
for i in self.employee_list:
if i.name==ename:
for a,b in i.leavesbalance.items():
if a==tl:
if b>=nol:
i.leavesbalance[a]=b-nol
return 'True'
else:
return 'False'
return 'not found'
if _name_ == '_main_':
elist=[]
num=int(input())
for i in range(num):
leaves={}
name=input()
designation=input()
salary=int(input())
ltype=int(input())
for i in range(ltype):
key=input()
value=int(input())
leaves[key]=value
elist.append(Employee(name,designation,salary,leaves))
obj=Organization(elist)
empname=input()
Itype=input()
nol=int(input())
if(obj.checkLeaveEligibility(empname,Itype,nol)=='True'):
print("leave granted")
obj.display_leaves(empname)
elif(o.checkLeaveEligibility(empname,Itype,nol)=='False'):
print("leave not granted")
obj.display_leaves(empname)
elif(obj.checkLeaveEligibility(empname,Itype,nol)=='not found'):
print("leave not granted")
print("Employee not found")
Employee code
Telegram- https://t.me/Allcodingsolution
11 227
Python
1. C
2. A
3. B
4. A
5. B
6. C
7. A
8. D
9. B
10. A
11. A
12. C
47. D
48. A
49. D
50. B
26. A
27. B
28. B
29. 1
30.1
31.b
32.b
43.a
44.a
45.a
46.d
Telegram- https://t.me/Allcodingsolution
11 227
Java
1. 2018
2.option 1 and 2
4.true
5. No
7. Value added service
8.allofthe above
9. a, b, c
10. 1354
20. True
14. Path
15.B
23. B
25.b
26. B
27. C
28. D
29. B
30. True
31. B
32. D
33.C
34. B
35. A
38. A
39. Default
44.byte code
45.runtime environment
47. A
50. Compilation error
48 . D
43 c
14.path
Telegram- https://t.me/Allcodingsolution
11 227
Java
1. 2018
2.option 1 and 2
4.true
5. No
7. Value added service
8.allofthe above
9. a, b, c
10. 1354
20. True
15.B
26. B
27. C
28. D
29. B
30. True
31. B
32. D
33.C
34. B
35. A
38. A
39. Default
44.byte code
45.runtime environment
47. A
Telegram- https://t.me/Allcodingsolution
11 227
PYTHON IRA
1. 2003
2. All of the options
3. Reinforcement learning
4. All the evidence
5.D
6.C
27.allof the above
44.byte code
45. Runtime environment
Telegram- https://t.me/Allcodingsolution
11 227
Java
1. 2018
2.option 1 and 2
4.true
5. No
7. Value added service
8.allofthe above
9. a, b, c
10. 1354
13.entire record
Telegram- https://t.me/Allcodingsolution
11 227
Java Ira
1. 2018
2.option 1 and 2
4.true
5. No
7. Value added service
https://t.me/Allcodingsolution
11 227
ZOHO Question 3 Code
Language: C++
Telegram:- https://t.me/Allcodingsolution
11 227
ZOHO Question NO 2 Code
Language: C++
Telegram:- https://t.me/Allcodingsolution
11 227
ZOHO Question No 1 Code
Language: C++
Telegram:- https://t.me/Allcodingsolution
11 227
awk 'BEGIN{FS="|", count=0;}
{
if($3>20)
{count+=$3;}
}
END { if(count!=0){print "Total count: " count;
}
else
{
print "No record found with matching criteria.";
}}'
Telegram:- https://t.me/Allcodingsolution
11 227
awk 'BEGIN{FS=",", count=0;}
{
if($3>=60)
count++;
{print $2,"#",$3;}
}
END { if(count!=0){print count;
}
else
{
print "No records found";
}}'
Telegram:- https://t.me/Allcodingsolution
11 227
TCS Java PRA
fill this sheet sequence will be same..
1.bvszbcd
2.b grep tech
3.cp programs
4.pat$
5.sort -r
6.1
7. A
8.select distinct d name
9. Truncate
10.
11.
12.
13.
14.
15.
16.B
17.C object
18.all of above
19.A
20.C
21.C
22 44
23.B
24. Nonevof these
25.radio button
26.b new
27.c
28.b
29.false
30.true
Telegram:- https://t.me/Allcodingsolution
11 227
TCS Java
1.bvszbcd
2.b grep tech
3.cp programs
4.pat$
5.sort -r
6.
7. A
8.
9. Truncate
10.
11.
12.
13.
14.
15.
16.
17.
18.
19.
20.
21.C
22 44
23.
24. Nonevof these
25.radio button
26.b new
27.c
28.b
29.false
30.
Telegram :- https://t.me/Allcodingsolution
11 227
TCS Python PRA
1.b
2.d
3.a
4.d
5.a
6.c
7.d
8.d
9.d
10.a
11.d
12.a
13.c
14.c
15.b
16.b
17.c
18.a
19.a
20.a
21.b
22.d
23.
24.
25.c
26.c
27.a
28.c
29.a
30.c
21 B
22 D
23 A
24 C
25 C
Telegram:- https://t.me/Allcodingsolution
11 227
TCS IRA
Java
1. All
2. Excellence
3. All the evidence
4. Deployment lctn
5. Truesophisticated
6.
7.
8.
9.
10. Knife in right
11.
12.
13.
14.
15.
16.
17.
18.
19. Returns all rows from left
20. 21
Telegram- https://t.me/Allcodingsolution
11 227
TCS IRA
Python
1. C
2. A
3. B
4. A
5. B
6. C
7. A
8. D
9. B
10. A
11. A
12. C
47. D
48. A
49. D
50. B
26. A
27. B
28. B
29. 1
30.1
31.b
32.b
43.a
44.a
45.a
46.d
Telegram :- https://t.me/Allcodingsolution
11 227
TCS IRA
Java
1. All
2. Excellence
3. All the evidence
4. Deployment lctn
5. Truesophisticated
6.
7.
8.
9.
10.
11.
12.
13.
14.
15.
16.
17.
18.
19.
20.
21.
22.
23.
24.
25.
26.
27.
28.
29.
30.
31.
32.
33.
34.
35.
36.
37.
38.
39.
40.
41.
42.
43.
44.
45.
46.
47.
48.
49.
50.
Telegram :- https://t.me/Allcodingsolution
