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All coding Solution
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All coding Solution (@allcodingsolution) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 11 220 obunachidan iborat bo'lib, Taʼlim toifasida 17 985-o'rinni va Hindiston mintaqasida 37 554-o'rinni egallagan.
📊 Auditoriya ko‘rsatkichlari va dinamika
невідомо sanasidan buyon loyiha tez o‘sib, 11 220 obunachiga ega bo‘ldi.
07 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -154 ga, so‘nggi 24 soatda esa -7 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.
- Tasdiqlash holati: Tasdiqlanmagan
- Jalb etish (ER): Auditoriya o‘rtacha 1.45% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni to‘playdi.
- Post qamrovi: Har bir post o‘rtacha 0 marta ko‘riladi; birinchi sutkada odatda 0 ta ko‘rish yig‘iladi.
- Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.
📝 Tavsif va kontent siyosati
Kanal uchun tavsif kiritilmagan.
Yuqori yangilanish chastotasi (oxirgi ma’lumot 08 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Taʼlim toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
11 220
Obunachilar
-724 soatlar
-297 kunlar
-15430 kunlar
Postlar arxiv
11 227
class Food:
def init(self,name,protien,fat,carb):
self.name=name
self.protien=protien
self.fat=fat
self.carb=carb
class Nutrition:
def init(self,status,lfood):
self.status=status
self.lfood=lfood
def setEnergy(self):
result=[]
for i in lfood:
for k,v in status.items():
temp=(i.protien+i.fat+i.carb)
if(temp>=v[0] and temp<=v[1]):
result.append(str(i.name)+" - "+str(temp)+" - "+k)
if(len(result)==0):
return None
else:
return result
def getEnergyRichFood(self,checkenergy):
ans=[]
for i in lfood:
temp=(i.protien+i.fat+i.carb)
if(temp<=checkenergy):
ans.append(i.name+" : "+str(temp))
if(len(ans)==0):
return None
else:
return ans
n=int(input())
lfood=[]
for i in range(n):
name=input()
protien=float(input())
fat=float(input())
carb=float(input())
lfood.append(Food(name,protien,fat,carb))
status={}
cnt=int(input())
for i in range(cnt):
st=input()
l=[]
l.append(int(input()))
l.append(int(input()))
status[st]=tuple(l)
checkenergy=int(input())
obj=Nutrition(status,lfood)
result=obj.setEnergy()
ans=obj.getEnergyRichFood(checkenergy)
if(result!=None):
print("Energy of Food:")
for i in result:
print(i)
if(ans!=None):
print("Food within given criteria:")
for i in ans:
print(i)
else:
print("No Food Found")
Food code
python
Telegram- https://t.me/Allcodingsolution
11 227
awk ' BEGIN{FS=#;count=0;}{
if($4>300){
count=count+$3;}
}END{
print "Total count:" count;}
else
{
print "No soap found with cost above 300";
}
}'
Soap management unix
Telegram- https://t.me/Allcodingsolution
11 227
class Employee:
def _init_(self,n,d,s,lb):
self.name=n
self.designation=d
self.salary=s
self.leavesbalance=lb
class Organization:
def _init_(self,elist):
self.employee_list=elist
def display_leaves(self,name):
for i in self.employee_list:
if i.name==name:
for a,b in i.leavesbalance.items():
print(a,":",b)
def checkLeaveEligibility(self,ename,tl,nol):
for i in self.employee_list:
if i.name==ename:
for a,b in i.leavesbalance.items():
if a==tl:
if b>=nol:
i.leavesbalance[a]=b-nol
return 'True'
else:
return 'False'
return 'not found'
if _name_ == '_main_':
elist=[]
num=int(input())
for i in range(num):
leaves={}
name=input()
designation=input()
salary=int(input())
ltype=int(input())
for i in range(ltype):
key=input()
value=int(input())
leaves[key]=value
elist.append(Employee(name,designation,salary,leaves))
obj=Organization(elist)
empname=input()
Itype=input()
nol=int(input())
if(obj.checkLeaveEligibility(empname,Itype,nol)=='True'):
print("leave granted")
obj.display_leaves(empname)
elif(o.checkLeaveEligibility(empname,Itype,nol)=='False'):
print("leave not granted")
obj.display_leaves(empname)
elif(obj.checkLeaveEligibility(empname,Itype,nol)=='not found'):
print("leave not granted")
print("Employee not found")
Employee code
Telegram- https://t.me/Allcodingsolution
11 227
Python
1. C
2. A
3. B
4. A
5. B
6. C
7. A
8. D
9. B
10. A
11. A
12. C
47. D
48. A
49. D
50. B
26. A
27. B
28. B
29. 1
30.1
31.b
32.b
43.a
44.a
45.a
46.d
Telegram- https://t.me/Allcodingsolution
11 227
Java
1. 2018
2.option 1 and 2
4.true
5. No
7. Value added service
8.allofthe above
9. a, b, c
10. 1354
20. True
14. Path
15.B
23. B
25.b
26. B
27. C
28. D
29. B
30. True
31. B
32. D
33.C
34. B
35. A
38. A
39. Default
44.byte code
45.runtime environment
47. A
50. Compilation error
48 . D
43 c
14.path
Telegram- https://t.me/Allcodingsolution
11 227
Java
1. 2018
2.option 1 and 2
4.true
5. No
7. Value added service
8.allofthe above
9. a, b, c
10. 1354
20. True
15.B
26. B
27. C
28. D
29. B
30. True
31. B
32. D
33.C
34. B
35. A
38. A
39. Default
44.byte code
45.runtime environment
47. A
Telegram- https://t.me/Allcodingsolution
11 227
PYTHON IRA
1. 2003
2. All of the options
3. Reinforcement learning
4. All the evidence
5.D
6.C
27.allof the above
44.byte code
45. Runtime environment
Telegram- https://t.me/Allcodingsolution
11 227
Java
1. 2018
2.option 1 and 2
4.true
5. No
7. Value added service
8.allofthe above
9. a, b, c
10. 1354
13.entire record
Telegram- https://t.me/Allcodingsolution
11 227
Java Ira
1. 2018
2.option 1 and 2
4.true
5. No
7. Value added service
https://t.me/Allcodingsolution
11 227
ZOHO Question 3 Code
Language: C++
Telegram:- https://t.me/Allcodingsolution
11 227
ZOHO Question NO 2 Code
Language: C++
Telegram:- https://t.me/Allcodingsolution
11 227
ZOHO Question No 1 Code
Language: C++
Telegram:- https://t.me/Allcodingsolution
11 227
awk 'BEGIN{FS="|", count=0;}
{
if($3>20)
{count+=$3;}
}
END { if(count!=0){print "Total count: " count;
}
else
{
print "No record found with matching criteria.";
}}'
Telegram:- https://t.me/Allcodingsolution
11 227
awk 'BEGIN{FS=",", count=0;}
{
if($3>=60)
count++;
{print $2,"#",$3;}
}
END { if(count!=0){print count;
}
else
{
print "No records found";
}}'
Telegram:- https://t.me/Allcodingsolution
11 227
TCS Java PRA
fill this sheet sequence will be same..
1.bvszbcd
2.b grep tech
3.cp programs
4.pat$
5.sort -r
6.1
7. A
8.select distinct d name
9. Truncate
10.
11.
12.
13.
14.
15.
16.B
17.C object
18.all of above
19.A
20.C
21.C
22 44
23.B
24. Nonevof these
25.radio button
26.b new
27.c
28.b
29.false
30.true
Telegram:- https://t.me/Allcodingsolution
11 227
TCS Java
1.bvszbcd
2.b grep tech
3.cp programs
4.pat$
5.sort -r
6.
7. A
8.
9. Truncate
10.
11.
12.
13.
14.
15.
16.
17.
18.
19.
20.
21.C
22 44
23.
24. Nonevof these
25.radio button
26.b new
27.c
28.b
29.false
30.
Telegram :- https://t.me/Allcodingsolution
11 227
TCS Python PRA
1.b
2.d
3.a
4.d
5.a
6.c
7.d
8.d
9.d
10.a
11.d
12.a
13.c
14.c
15.b
16.b
17.c
18.a
19.a
20.a
21.b
22.d
23.
24.
25.c
26.c
27.a
28.c
29.a
30.c
21 B
22 D
23 A
24 C
25 C
Telegram:- https://t.me/Allcodingsolution
11 227
TCS IRA
Java
1. All
2. Excellence
3. All the evidence
4. Deployment lctn
5. Truesophisticated
6.
7.
8.
9.
10. Knife in right
11.
12.
13.
14.
15.
16.
17.
18.
19. Returns all rows from left
20. 21
Telegram- https://t.me/Allcodingsolution
11 227
TCS IRA
Python
1. C
2. A
3. B
4. A
5. B
6. C
7. A
8. D
9. B
10. A
11. A
12. C
47. D
48. A
49. D
50. B
26. A
27. B
28. B
29. 1
30.1
31.b
32.b
43.a
44.a
45.a
46.d
Telegram :- https://t.me/Allcodingsolution
11 227
TCS IRA
Java
1. All
2. Excellence
3. All the evidence
4. Deployment lctn
5. Truesophisticated
6.
7.
8.
9.
10.
11.
12.
13.
14.
15.
16.
17.
18.
19.
20.
21.
22.
23.
24.
25.
26.
27.
28.
29.
30.
31.
32.
33.
34.
35.
36.
37.
38.
39.
40.
41.
42.
43.
44.
45.
46.
47.
48.
49.
50.
Telegram :- https://t.me/Allcodingsolution
