S0ER
Архитектура | Программирование | Профессиональное развитие Соер.Клуб - https://t.me/soer_live По всем вопросам писать на @soerdev
Show more📈 Analytical overview of Telegram channel S0ER
Channel S0ER (@softwareengineervlog) in the Russian language segment is an active participant. Currently, the community unites 10 465 subscribers, ranking 11 392 in the Technologies & Applications category and 61 000 in the Russia region.
📊 Audience metrics and dynamics
Since its creation on невідомо, the project has demonstrated rapid growth, gathering an audience of 10 465 subscribers.
According to the latest data from 03 September, 2026, the channel demonstrates stable activity. Although there has been a change in the number of participants by 15 over the last 30 days and by 1 over the last 24 hours, overall reach remains high.
- Verification status: Not verified
- Engagement rate (ER): The average audience engagement rate is 49.72%. Within the first 24 hours after publication, content typically collects N/A% reactions from the total number of subscribers.
- Post reach: On average, each post receives 0 views. Within the first day, a publication typically gains 0 views.
- Reactions and interaction: The audience actively supports content: the average number of reactions per post is 0.
- Thematic interests: Content is focused on key topics such as rbp, архитектура, callme, mov, указатель.
📝 Description and content policy
The author describes the resource as a platform for expressing subjective opinions:
“Архитектура | Программирование | Профессиональное развитие
Соер.Клуб - https://t.me/soer_live
По всем вопросам писать на @soerdev”
Thanks to the high frequency of updates (latest data received on 04 September, 2026), the channel maintains relevance and a high level of publication reach. Analytics show that the audience actively interacts with content, making it an important point of influence in the Technologies & Applications category.
for i in {1..39}; do find ./ -name '*.ts' | xargs ctags -x --verbose=no | awk '{print($1)}' | awk -v numSym=$i ' { if ( length == numSym ) {print($0) } }' | wc -l; done
