Untold Coding
前往频道在 Telegram
|| जय श्री राम || #100dayschallenge Sharing HTML, CSS and JS magic ✨ Join our Creative Journey!🎉
显示更多📈 Telegram 频道 Untold Coding 的分析概览
频道 Untold Coding (@untoldcoding) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 31 445 名订阅者，在 技术与应用 类别中位列第 3 405，并在 印度 地区排名第 15 035 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 31 445 名订阅者。
根据 10 八月, 2025 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -416，过去 24 小时变化为 0，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 0%。内容发布后 24 小时内通常能获得 N/A% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 0 次浏览，首日通常累积 0 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 0。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“|| जय श्री राम ||
#100dayschallenge
Sharing HTML, CSS and JS magic ✨
Join our Creative Journey!🎉”
凭借高频更新（最新数据采集于 11 八月, 2025），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 技术与应用 类别中的关键影响点。
31 445
订阅者
无数据24 小时
-747 天
-41630 天
帖子存档
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Explanation1. Initialization : The loop starts with
++i, which increments i from -1 to 0.
2. Condition : The condition i++ is checked next. Since i++ returns the value of i before incrementing, the loop checks if 0 is true, which it is not (0 is considered false in C).
3. Increment: If the condition were true, the loop would proceed to increment i with i++ again, but this part doesn't get executed in this case because the condition i++ evaluates to false on the first check.
Due to the condition i++ being false when i is 0, the loop doesn't execute even once. Therefore, "Untoldcoding" is never printed.31 445
#include <stdio.h>
int main() {
int i = -1;
for (++i; i++; i++)
printf("Untoldcoding");
return 0;
}
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In this question we use formal
-(2^n -k) here k is the number and n is the no. of bit
Therefore
We have n = 8 , (char size)
K = 21
- ( 2⁸ -168) = - (256-168)
= -88
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What is the output of this program?
#include<stdio.h>
int main() {
printf("%d", printf("ABCD"));
return 0;
}
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Char ch = 21;
ch = ch<<3;
printf("%d",ch); What is the output ( ) //Ignore typing error
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