uz
Feedback
Untold Coding

Untold Coding

Kanalga Telegram’da o‘tish

|| जय श्री राम || #100dayschallenge Sharing HTML, CSS and JS magic ✨ Join our Creative Journey!🎉

Ko'proq ko'rsatish

📈 Telegram kanali Untold Coding analitikasi

Untold Coding (@untoldcoding) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 31 445 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 3 405-o'rinni va Hindiston mintaqasida 15 035-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 31 445 obunachiga ega bo‘ldi.

10 Avgust, 2025 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -416 ga, so‘nggi 24 soatda esa 0 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 0% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining N/A% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 0 marta ko‘riladi; birinchi sutkada odatda 0 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 0 ta reaksiya keladi.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“|| जय श्री राम || #100dayschallenge Sharing HTML, CSS and JS magic ✨ Join our Creative Journey!🎉”

Yuqori yangilanish chastotasi (oxirgi ma’lumot 11 Avgust, 2025 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

31 445
Obunachilar
Ma'lumot yo'q24 soatlar
-747 kun
-41630 kun
Postlar arxiv
Explanation
1. Initialization : The loop starts with ++i, which increments i from -1 to 0. 2. Condition : The condition i++ is checked next. Since i++ returns the value of i before incrementing, the loop checks if 0 is true, which it is not (0 is considered false in C). 3. Increment: If the condition were true, the loop would proceed to increment i with i++ again, but this part doesn't get executed in this case because the condition i++ evaluates to false on the first check. Due to the condition i++ being false when i is 0, the loop doesn't execute even once. Therefore, "Untoldcoding" is never printed.

Think and give answer ... In quiz

How many time loop will executed ?
Anonymous voting

#include <stdio.h> int main() { int i = -1; for (++i; i++; i++) printf("Untoldcoding"); return 0; }

In this question we use formal -(2^n -k) here k is the number and n is the no. of bit Therefore We have n = 8 , (char size) K = 21 - ( 2⁸ -168) = - (256-168) = -88

Output of above program is ?
Anonymous voting

What is the output of this program? #include<stdio.h> int main() { printf("%d", printf("ABCD")); return 0; }

Char ch = 21; ch = ch<<3; printf("%d",ch); What is the output ( ) //Ignore typing error
Anonymous voting

We should start imp gate questions quiz?
Anonymous voting

Here is website link : https://www.hackerrank.com/skills-verification Join our WhatsApp channel or group for more updates https://chat.whatsapp.com/HXh5cAaCfpT9qmWgy2uYyG Link is in bio 📍❤️

List of All Companies that hire Freshers Off Campus 📈 1.Adobe: www.adobe.com/careers.html 2.Accolite: www.accolite.com/careers/ 3.Airtel: www.airtel.in/careers/ 4.Amazon: www.amazon.jobs/ 5.Cadence Design Systems: www.cadence.com/en_US/company/careers.html 6.CleverTap: clevertap.com/careers/ 7.Cisco: jobs.cisco.com/ 8.Capgemini: www.capgemini.com/careers/ 9.Cognizant: careers.cognizant.com/global/en 10.Zoho: www.zoho.com/careers/

Choose which videos you want on Untoldcoding channel 👆👆👆

Now we are ready as freelancers again

Let's connect on LinkedIn 👇👇 https://www.linkedin.com/company/untoldcoding

?
Anonymous voting

According to you which is better Learning from YouTube or Offline Coaching in affordable price?

Full Stack UntoldCoding.pdf