ch
Feedback
Coding_knowledge

Coding_knowledge

前往频道在 Telegram

💡 Your Coding Journey Starts Here! Get free courses, coding resources, internships, job updates & much more. Stay ahead in tech with us! ❤️🚀 Join our WhatsApp group👇 https://whatsapp.com/channel/0029Vaa7CVhCRs1rxJzy1n3D

显示更多

📈 Telegram 频道 Coding_knowledge 的分析概览

频道 Coding_knowledge (@coding_knwledge01) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 81 635 名订阅者,在 技术与应用 类别中位列第 1 579,并在 印度 地区排名第 3 881

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 81 635 名订阅者。

根据 15 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 3 430,过去 24 小时变化为 17,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 6.97%。内容发布后 24 小时内通常能获得 2.92% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 5 694 次浏览,首日通常累积 2 382 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 13
  • 主题关注点: 内容集中在 q&a, goody, api, stack, analyst 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
💡 Your Coding Journey Starts Here! Get free courses, coding resources, internships, job updates & much more. Stay ahead in tech with us! ❤️🚀 Join our WhatsApp group👇 https://whatsapp.com/channel/0029Vaa7CVhCRs1rxJzy1n3D

凭借高频更新(最新数据采集于 16 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。

81 635
订阅者
+1724 小时
+1647
+3 43030
帖子存档
TOP 50 DATA STRUCTURES INTERVIEW◾QUE & ANS.pdf3.86 KB

800+ SQL Server Interview Questions and Answers .pdf1.02 MB

SQL Handwritten Notes -1.pdf3.37 MB

SQL Handwritten Notes .pdf20.62 MB

HTML, CSS, JavaScript Material.pdf2.57 MB

HTML, CSS, Bootstrap, Javascript and_jQuery.pdf1.02 MB

public class BinaryTreeToDLL { //Represent a node of the binary tree public static class Node{ int data; Node left; Node right; public Node(int data) { this.data = data; this.left = null; this.right = null; } } //Represent the root of the binary tree public Node root; //Represent the head and tail of the doubly linked list Node head, tail = null; //convertbtToDLL() will convert the given binary tree to corresponding doubly linked list public void convertbtToDLL(Node node) { //Checks whether node is null if(node == null) return; //Convert left subtree to doubly linked list convertbtToDLL(node.left); //If list is empty, add node as head of the list if(head == null) { //Both head and tail will point to node head = tail = node; } //Otherwise, add node to the end of the list else { //node will be added after tail such that tail's right will point to node tail.right = node; //node's left will point to tail node.left = tail; //node will become new tail tail = node; } //Convert right subtree to doubly linked list convertbtToDLL(node.right); } //display() will print out the nodes of the list public void display() { //Node current will point to head Node current = head; if(head == null) { System.out.println("List is empty"); return; } System.out.println("Nodes of generated doubly linked list: "); while(current != null) { //Prints each node by incrementing the pointer. System.out.print(current.data + " "); current = current.right; } System.out.println(); } public static void main(String[] args) { BinaryTreeToDLL bt = new BinaryTreeToDLL(); //Add nodes to the binary tree bt.root = new Node(1); bt.root.left = new Node(2); bt.root.right = new Node(3); bt.root.left.left = new Node(4); bt.root.left.right = new Node(5); bt.root.right.left = new Node(6); bt.root.right.right = new Node(7); //Converts the given binary tree to doubly linked list bt.convertbtToDLL(bt.root); //Displays the nodes present in the list bt.display(); } }

Java program to convert a given binary tree to doubly linked list In this program, we need to convert the given binary tree to corresponding doubly liked list. The binary tree is a tree data structure in which each node has at most two children node. This can be achieved by traversing the tree in the in-order manner that is, left the child -> root ->right node. Traverse left sub-tree and convert it into the doubly linked list by adding nodes to the end of the list. In this way, leftmost node will become head of the list. Then, convert the right sub-tree into the doubly linked list. Algorithm Define a Node class which represents a node in the binary tree. It will have three properties: data left, and right where the left and right represent two children of a node. Root will represent the root of the binary tree. Head and tail node represent the head and tail of the doubly linked list. BinaryTreeToDLL() will convert the given binary tree to corresponding doubly linked list. Perform inorder traversal of the binary tree by converting the left subtree first. If the list is empty, both head and tail will point to a node. If the list is not empty, the node will be inserted at the end of the list. Here, pointer left, and right will represent the previous and next pointer of the doubly linked list. Now, recursively call BinaryTreeToDLL() to convert the right subtree. a. display() will show all the nodes present in the list. Define a new node 'current' that will point to the head. Print current.data till current points to null. Current will point to the next node in the list in each iteration.

All keyboard shortcuts for data scientist .pdf3.15 MB

SQL-Cheat-Sheet.pdf2.43 MB

DSA in Real Life.pdf5.41 MB