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Coding_knowledge (@coding_knwledge01) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 81 635 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 579-o'rinni va Hindiston mintaqasida 3 881-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 81 635 obunachiga ega bo‘ldi.

15 Iyun, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni 3 430 ga, so‘nggi 24 soatda esa 17 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 6.97% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 2.92% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 5 694 marta ko‘riladi; birinchi sutkada odatda 2 382 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 13 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent q&a, goody, api, stack, analyst kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
💡 Your Coding Journey Starts Here! Get free courses, coding resources, internships, job updates & much more. Stay ahead in tech with us! ❤️🚀 Join our WhatsApp group👇 https://whatsapp.com/channel/0029Vaa7CVhCRs1rxJzy1n3D

Yuqori yangilanish chastotasi (oxirgi ma’lumot 16 Iyun, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

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Postlar arxiv
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public class BinaryTreeToDLL { //Represent a node of the binary tree public static class Node{ int data; Node left; Node right; public Node(int data) { this.data = data; this.left = null; this.right = null; } } //Represent the root of the binary tree public Node root; //Represent the head and tail of the doubly linked list Node head, tail = null; //convertbtToDLL() will convert the given binary tree to corresponding doubly linked list public void convertbtToDLL(Node node) { //Checks whether node is null if(node == null) return; //Convert left subtree to doubly linked list convertbtToDLL(node.left); //If list is empty, add node as head of the list if(head == null) { //Both head and tail will point to node head = tail = node; } //Otherwise, add node to the end of the list else { //node will be added after tail such that tail's right will point to node tail.right = node; //node's left will point to tail node.left = tail; //node will become new tail tail = node; } //Convert right subtree to doubly linked list convertbtToDLL(node.right); } //display() will print out the nodes of the list public void display() { //Node current will point to head Node current = head; if(head == null) { System.out.println("List is empty"); return; } System.out.println("Nodes of generated doubly linked list: "); while(current != null) { //Prints each node by incrementing the pointer. System.out.print(current.data + " "); current = current.right; } System.out.println(); } public static void main(String[] args) { BinaryTreeToDLL bt = new BinaryTreeToDLL(); //Add nodes to the binary tree bt.root = new Node(1); bt.root.left = new Node(2); bt.root.right = new Node(3); bt.root.left.left = new Node(4); bt.root.left.right = new Node(5); bt.root.right.left = new Node(6); bt.root.right.right = new Node(7); //Converts the given binary tree to doubly linked list bt.convertbtToDLL(bt.root); //Displays the nodes present in the list bt.display(); } }

Java program to convert a given binary tree to doubly linked list In this program, we need to convert the given binary tree to corresponding doubly liked list. The binary tree is a tree data structure in which each node has at most two children node. This can be achieved by traversing the tree in the in-order manner that is, left the child -> root ->right node. Traverse left sub-tree and convert it into the doubly linked list by adding nodes to the end of the list. In this way, leftmost node will become head of the list. Then, convert the right sub-tree into the doubly linked list. Algorithm Define a Node class which represents a node in the binary tree. It will have three properties: data left, and right where the left and right represent two children of a node. Root will represent the root of the binary tree. Head and tail node represent the head and tail of the doubly linked list. BinaryTreeToDLL() will convert the given binary tree to corresponding doubly linked list. Perform inorder traversal of the binary tree by converting the left subtree first. If the list is empty, both head and tail will point to a node. If the list is not empty, the node will be inserted at the end of the list. Here, pointer left, and right will represent the previous and next pointer of the doubly linked list. Now, recursively call BinaryTreeToDLL() to convert the right subtree. a. display() will show all the nodes present in the list. Define a new node 'current' that will point to the head. Print current.data till current points to null. Current will point to the next node in the list in each iteration.

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