AI Coding & CSE Fundamentals
🚀 Explore AI, Coding & Computer Science Fundamentals. 💻 Programming • DSA • DBMS • OS • Networks 🤖 AI & Emerging Technologies 🛠️ Projects • Tutorials • Learning Resources 📚 Your freedom to gain knowledge for free.
显示更多📈 Telegram 频道 AI Coding & CSE Fundamentals 的分析概览
频道 AI Coding & CSE Fundamentals (@aicoding_csefundamentals) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 12 318 名订阅者,在 技术与应用 类别中位列第 10 235,并在 印度 地区排名第 31 257 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 12 318 名订阅者。
根据 13 十一月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -236,过去 24 小时变化为 -9,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 10.85%。内容发布后 24 小时内通常能获得 N/A% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 337 次浏览,首日通常累积 0 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 11。
- 主题关注点: 内容集中在 input, string, scanf("%d, array, element 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台:
“🚀 Explore AI, Coding & Computer Science Fundamentals.
💻 Programming • DSA • DBMS • OS • Networks
🤖 AI & Emerging Technologies
🛠️ Projects • Tutorials • Learning Resources
📚 Your freedom to gain knowledge for free.”
凭借高频更新(最新数据采集于 14 十一月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
#include <stdio.h>
int add(int a, int b) {
return a + b;
}
int main() {
int num1, num2, sum;
printf("Enter two numbers: ");
scanf("%d %d", &num1, &num2);
sum = add(num1, num2);
printf("Sum = %d\n", sum);
return 0;
}#include <stdio.h>
int main() {
char ch;
printf("Enter a character: ");
scanf(" %c", &ch);
printf("ASCII value of %c = %d\n", ch, ch);
return 0;
}#include <stdio.h>
int main() {
int num;
scanf("%d", &num);
if (num > 0) {
printf("Positive\n");
} else if (num < 0) {
printf("Negative\n");
} else {
printf("Zero\n");
}
return 0;
}#include <stdio.h>
int main() {
int num;
printf("Enter an integer: ");
scanf("%d", &num);
if (num % 2 == 0) {
printf("%d is even.\n", num);
} else {
printf("%d is odd.\n", num);
}
return 0;
}#include <stdio.h>
int main() {
int integer_variable = 10;
float float_variable = 3.14;
char char_variable = 'A';
double double_variable = 3.14159;
short short_variable = 5;
long long_variable = 1234567890;
unsigned int unsigned_variable = 4294967295;
printf("Integer: %d\n", integer_variable);
printf("Float: %f\n", float_variable);
printf("Character: %c\n", char_variable);
printf("Double: %lf\n", double_variable);
printf("Short: %hd\n", short_variable);
printf("Long: %ld\n", long_variable);
printf("Unsigned Integer: %u\n", unsigned_variable);
return 0;
}#include <stdio.h>
int main() {
char op;
double num1, num2;
printf("Enter an operator (+, -, *, /): ");
scanf(" %c", &op);
printf("Enter two operands: ");
scanf("%lf %lf", &num1, &num2);
switch (op) {
case '+':
printf("%.1lf + %.1lf = %.1lf", num1, num2, num1 + num2);
break;
case '-':
printf("%.1lf - %.1lf = %.1lf", num1, num2, num1 - num2);
break;
case '*':
printf("%.1lf * %.1lf = %.1lf", num1, num2, num1 * num2);
break;
case '/':
if (num2 != 0) {
printf("%.1lf / %.1lf = %.1lf", num1, num2, num1 / num2);
} else {
printf("Error: Division by zero");
}
break;
default:
printf("Error: Invalid operator");
}
return 0;
}#include <stdio.h>
int main() {
printf("Size of int: %lu bytes\n", sizeof(int));
printf("Size of float: %lu bytes\n", sizeof(float));
printf("Size of char: %lu byte\n", sizeof(char));
printf("Size of double: %lu bytes\n", sizeof(double));
return 0;
}#include <stdio.h>
int main() {
int a = 10;
int b = 20;
a = a + b;
b = a - b;
a = a - b;
printf("a = %d, b = %d\n", a, b);
return 0;
}#include <stdio.h>
int main() {
int a = 10;
int b = 20;
int temp;
printf("Before swap: a = %d, b = %d\n", a, b);
temp = a;
a = b;
b = temp;
printf("After swap: a = %d, b = %d\n", a, b);
return 0;
}#include <stdio.h>
int main() {
int num1, num2, sum;
printf("Enter two integers: ");
scanf("%d %d", &num1, &num2);
sum = num1 + num2;
printf("Sum = %d\n", sum);
return 0;
}