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X from Y Code C++ Language ✅ Done TCS Codevita #include <bits/stdc++.h> using namespace std; typedef long long ll; #define codeingarea vector<int> #define all(a) (a).begin() , (a).end() #define sz(a) ((int)((a).size())) const ll INF = 4e18; vector<codeingarea> dp(1e4+1 , codeingaarea(1e4+1 , -1)); int f(int i , int j , int s , int r , string &x , string &y , string &y1) {     if(i>j)return 0;     if(dp[i][j] != -1)return dp[i][j];     int mini = 1e9;     for(int k=i; k<=j; k++)     {                 if(y1.find(x.substr(i , k-i+1)) != string::npos)mini = min(mini , r+f(k+1 , j , s , r , x , y , y1));         if(y.find(x.substr(i , k-i+1)) != string::npos)mini = min(mini , s+f(k+1 , j , s , r , x , y , y1));     }     return mini; } int solve(int s , int r , string x, string y) {     string y1 = y;     reverse(all(y1));     return f(0 , sz(x)-1 , s, r , x , y , y1); } int32_t main(){     ios_base::sync_with_stdio(false);      cin.tie(NULL);     string x , y;     cin >> x >> y;     int s, r;     cin >> s >> r;     int ans = solve(s , r, x , y);     cout << ans;     return 0; } X from Y C++ Language 100% Working ✅ TCS Codevita

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def min_string_factor(X, Y, S, R): len_X, len_Y = len(X), len(Y) dp = [[float('inf')] * (len_Y + 1) for _ in range(len_X + 1)] dp[0][0] = 0 for i in range(1, len_X + 1): for j in range(1, len_Y + 1): # Select substring from Y if X[i - 1] == Y[j - 1]: dp[i][j] = min(dp[i][j], dp[i - 1][j - 1] + S) # Select substring from reversed Y dp[i][j] = min(dp[i][j], dp[i][j - 1] + R) result = min(dp[len_X]) return result if result != float('inf') else "Impossible" # Reading input X = input().strip() Y = input().strip() S, R = map(int, input().strip().split()) # Output result print(min_string_factor(X, Y, S, R)) @codeing_area

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