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Coding Interview Resources

Coding Interview Resources

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This channel contains the free resources and solution of coding problems which are usually asked in the interviews. Managed by: @love_data

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📈 Telegram 频道 Coding Interview Resources 的分析概览

频道 Coding Interview Resources (@crackingthecodinginterview) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 52 248 名订阅者,在 技术与应用 类别中位列第 2 474,并在 印度 地区排名第 6 815

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 52 248 名订阅者。

根据 26 八月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 31,过去 24 小时变化为 -3,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 1.85%。内容发布后 24 小时内通常能获得 0.76% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 966 次浏览,首日通常累积 398 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 2
  • 主题关注点: 内容集中在 array, stack, algorithm, programming, sort 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
This channel contains the free resources and solution of coding problems which are usually asked in the interviews. Managed by: @love_data

凭借高频更新(最新数据采集于 27 八月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。

52 248
订阅者
-324 小时
-657
+3130
帖子存档
🔹 DATA ANALYST – INTERVIEW REVISION SHEET 1️⃣ Role Clarity > “A data analyst collects, cleans, analyzes data, and converts it into insights that help businesses make decisions.” 2️⃣ SQL (Most Important) Must-know clauses: • SELECT, WHERE, ORDER BY, LIMIT • GROUP BY, HAVING • JOINS (INNER, LEFT) • Subqueries, CTEs • Window functions (ROW_NUMBER, RANK) Golden rules: • WHERE → before aggregation • HAVING → after aggregation • LEFT JOIN → keeps all left table rows • NULLs break calculations → use COALESCE Classic questions: • Top N per group • Find duplicates • Running totals 3️⃣ Excel Essentials Formulas: • IF, XLOOKUP • COUNTIFS, SUMIFS • TRIM, LEFT, RIGHT Core features: • Pivot tables • Conditional formatting • Data validation (dropdowns) Avoid: • Merged cells • Hard-coded values 4️⃣ Power BI / Tableau Concepts: • Data model (star schema) • Relationships (one-to-many) • Measures > calculated columns Must-know DAX: • Total Sales = SUM(Sales[Amount]) • YTD Sales = TOTALYTD(SUM(Sales[Amount]), Sales[Date]) Design rules: • KPIs on top • One story per dashboard • Minimal visuals 5️⃣ Statistics (Only What Matters) • Mean vs Median • Standard deviation • Correlation ≠ causation • Outliers distort averages • Use median for Salaries, House prices 6️⃣ Data Cleaning (Interview Gold) Steps you should say: 1. Remove duplicates 2. Handle missing values 3. Fix data types 4. Standardize text 7️⃣ Business Metrics • Revenue • Growth rate • Conversion rate • Churn • Retention • Average order value Always connect metrics to business impact. 8️⃣ Case Question Framework (Very Important) Always answer like this: 1. What happened 2. Why it happened 3. What should be done Example: > “Sales dropped due to lower traffic in one region, so I’d recommend increasing marketing spend there.” 9️⃣ Project Explanation Template > “The goal was . I used to clean data, to analyze, and to visualize. The key insight was . The business impact was .” Memorize this. 🔟 HR Power Answers Why data analyst? > “I enjoy finding patterns in data and turning them into actionable insights.” Strength: “I combine technical skills with business understanding.” Weakness: “I used to over-analyze, but now I focus on impact.” 🧠 Last-Day Interview Tips • Think out loud • Ask clarifying questions • Don’t jump to tools immediately • Focus on impact, not syntax 💬 Tap ❤️ for more!

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💻 Don’t Overwhelm to Prepare for Coding Interviews — It’s Only This Much 🚀 🔹 FOUNDATIONS (Must First) 1️⃣ Programming Language Mastery - Choose one: Python ⭐ (most popular) Java C++ JavaScript - Focus on: Syntax Loops & conditions Functions Built-in libraries Writing clean code 2️⃣ Time & Space Complexity - Big-O notation - Time vs space tradeoff - Best / average / worst case - Complexity analysis 🔥 Very important for interviews 3️⃣ Problem Solving Basics - Pattern recognition - Breaking problems into steps - Writing pseudocode - Edge case handling 🔥 CORE DATA STRUCTURES (HIGH PRIORITY) 4️⃣ Arrays - Traversal - Two pointer technique - Sliding window - Prefix sum (🔥 Most asked topic) 5️⃣ Strings - Manipulation - Palindrome problems - Pattern matching 6️⃣ Hashing - HashMap / Dictionary - Frequency counting - Fast lookup problems 7️⃣ Linked List - Insert/delete operations - Reverse list - Fast & slow pointer 8️⃣ Stack & Queue - LIFO / FIFO - Valid parentheses - Monotonic stack 9️⃣ Trees - Binary tree traversal - Binary Search Tree - Recursion - Tree depth / height (🔥 Very important) 🔟 Heap / Priority Queue - Min / max heap - Top K problems 1️⃣1️⃣ Graphs - BFS / DFS - Shortest path - Cycle detection 🚀 ALGORITHMS (CORE INTERVIEW TOPICS) 1️⃣2️⃣ Searching Algorithms - Linear search - Binary search 1️⃣3️⃣ Sorting Algorithms - Quick sort - Merge sort - Heap sort 1️⃣4️⃣ Recursion & Backtracking - Subsets - Permutations - N-Queens 1️⃣5️⃣ Greedy Algorithms - Activity selection - Interval problems 1️⃣6️⃣ Dynamic Programming (DP) - Memoization - Tabulation - Knapsack problems (🔥 Hard but high-value topic) ⚙️ INTERVIEW SKILLS 1️⃣7️⃣ Coding Patterns (Must Know ⭐) - Two pointers - Sliding window - Fast & slow pointers - Divide & conquer - Backtracking - BFS / DFS patterns 1️⃣8️⃣ Writing Clean Code - Readable variable names - Modular functions - Handling edge cases 1️⃣9️⃣ Debugging Skills - Test cases - Dry run - Error fixing 2️⃣0️⃣ Communication During Interview - Explain approach first - Think aloud - Discuss complexity (🔥 Often ignored but important) 🌟 ADVANCED / TOP COMPANY PREP 2️⃣1️⃣ System Design Basics - Scalability - Load balancing - Architecture concepts 2️⃣2️⃣ Object-Oriented Design - Classes & objects - Design principles - Low-level design 2️⃣3️⃣ Competitive Programming (Optional) - Codeforces - LeetCode contests ⭐ Best Practice Platforms - LeetCode ⭐ - HackerRank - Codeforces - GeeksforGeeks ⭐ Double Tap ♥️ For More

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def is_safe(row, col):     for r in range(row):         c = board[r]         if c == col or abs(c-col) == abs(r-row):             return False     return True def backtrack(row):     if row == n:         result.append(board[:])         return     for col in range(n):         if is_safe(row, col):             board[row] = col             backtrack(row + 1) backtrack(0) return result

🚀 Coding Interview Questions with Answers — Part 6 📊 Sorting, Searching & Dynamic Programming 🚀 51. How do you implement quicksort and mergesort?  Both are divide-and-conquer sorting algorithms. 🔹 Quicksort  🔹 Idea  1. Pick pivot 2. Partition array 3. Recursively sort halves 🔹 Python Quicksort  def quicksort(arr):     if len(arr) <= 1:         return arr     pivot = arr[len(arr)//2]     left = [x for x in arr if x < pivot]     middle = [x for x in arr if x == pivot]     right = [x for x in arr if x > pivot]     return quicksort(left) + middle + quicksort(right) print(quicksort([5,2,8,1,3])) 🔹 Complexity  Case: Best/Average → Complexity: O(n log n)  Case: Worst → Complexity: O(n²)  🔹 Mergesort  🔹 Idea  1. Split array 2. Sort recursively 3. Merge sorted halves 🔹 Python Mergesort  def mergesort(arr):     if len(arr) <= 1:         return arr     mid = len(arr)//2     left = mergesort(arr[:mid])     right = mergesort(arr[mid:])     return merge(left, right) def merge(left, right):     result = []     i = j = 0     while i < len(left) and j < len(right):         if left[i] < right[j]:             result.append(left[i])             i += 1         else:             result.append(right[j])             j += 1     result.extend(left[i:])     result.extend(right[j:])     return result 🔹 Complexity  Case: All Cases → Complexity: O(n log n)  🔹 Interview Tip  Mergesort is stable. Quicksort is usually faster in practice. 🚀 52. How do you implement binary search in a rotated sorted array?  Example:  Target: 0[4][5][6][7][0][1][2]  🔹 Key Idea  One half is always sorted.  🔹 Python Solution  def search(nums, target):     left, right = 0, len(nums)-1     while left <= right:         mid = (left + right)//2         if nums[mid] == target:             return mid         if nums[left] <= nums[mid]:             if nums[left] <= target < nums[mid]:                 right = mid - 1             else:                 left = mid + 1         else:             if nums[mid] < target <= nums[right]:                 left = mid + 1             else:                 right = mid - 1     return -1 🔹 Complexity  Time: O(log n)  Space: O(1)  🔹 Interview Tip  Very common medium-level interview problem. 🚀 53. How do you implement insertion sort and when is it useful?  Insertion sort inserts elements into correct position. 🔹 Python Solution  def insertion_sort(arr):     for i in range(1, len(arr)):         key = arr[i]         j = i - 1         while j >= 0 and arr[j] > key:             arr[j+1] = arr[j]             j -= 1         arr[j+1] = key     return arr 🔹 Complexity  Case: Best → Complexity: O(n)  Case: Average/Worst → Complexity: O(n²)  🔹 When Useful?  ✅ Small datasets  ✅ Nearly sorted arrays  ✅ Online sorting  🔹 Interview Tip  Simple but important for fundamentals. 🚀 54. How do you find the k-th largest element? 🔹 Efficient Approach  Use: Min Heap OR Quickselect  🔹 Heap Solution  import heapq def kth_largest(nums, k):     return heapq.nlargest(k, nums)[-1] print(kth_largest([3,2,1,5,6,4], 2)) 🔹 Output  5  🔹 Complexity  Time: O(n log k)  Space: O(k)  🔹 Interview Tip  Quickselect is often asked as optimization. 🚀 55. What is the difference between DFS and backtracking?  Both use recursion, but purpose differs. 🔹 DFS  Goal: Traverse/search graph or tree  🔹 Backtracking  Goal: Try all possibilities and undo choices  🔹 Example Problems  DFS: Tree traversal, Graph traversal  Backtracking: N-Queens, Sudoku, Permutations  🔹 Key Difference  DFS: Traversal, No undo step  Backtracking: Decision making, Includes undo step  🔹 Interview Tip  Backtracking = DFS + constraint checking + undoing choices. 🚀 56. How do you solve the “N-Queens” problem?  Place N queens so none attack each other. 🔹 Backtracking Solution def solve_n_queens(n):     board = [-1] * n     result = []

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SQL Interview Roadmap – Step-by-Step Guide to Crack Any SQL Round 💼📊 Whether you're applying for Data Analyst, BI, or Data Engineer roles — SQL rounds are must-clear. Here's your focused roadmap: 1️⃣ Core SQL Concepts 🔹 Understand RDBMS, tables, keys, schemas 🔹 Data types, NULLs, constraints 🧠 Interview Tip: Be able to explain Primary vs Foreign Key. 2️⃣ Basic Queries 🔹 SELECT, FROM, WHERE, ORDER BY, LIMIT 🧠 Practice: Filter and sort data by multiple columns. 3️⃣ Joins – Very Frequently Asked! 🔹 INNER, LEFT, RIGHT, FULL OUTER JOIN 🧠 Interview Tip: Explain the difference with examples. 🧪 Practice: Write queries using joins across 2–3 tables. 4️⃣ Aggregations & GROUP BY 🔹 COUNT, SUM, AVG, MIN, MAX, HAVING 🧠 Common Question: Total sales per category where total > X. 5️⃣ Window Functions 🔹 ROW_NUMBER(), RANK(), DENSE_RANK(), LAG(), LEAD() 🧠 Interview Favorite: Top N per group, previous row comparison. 6️⃣ Subqueries & CTEs 🔹 Write queries inside WHERE, FROM, and using WITH 🧠 Use Case: Filtering on aggregated data, simplifying logic. 7️⃣ CASE Statements 🔹 Add logic directly in SELECT 🧠 Example: Categorize users based on spend or activity. 8️⃣ Data Cleaning & Transformation 🔹 Handle NULLs, format dates, string manipulation (TRIM, SUBSTRING) 🧠 Real-world Task: Clean user input data. 9️⃣ Query Optimization Basics 🔹 Understand indexing, query plan, performance tips 🧠 Interview Tip: Difference between WHERE and HAVING. 🔟 Real-World Scenarios 🧠 Must Practice: • Sales funnel • Retention cohort • Churn rate • Revenue by channel • Daily active users 🧪 Practice PlatformsLeetCode (Easy–Hard SQL) • StrataScratch (Real business cases) • Mode Analytics (SQL + Visualization) • HackerRank SQL (MCQs + Coding) 💼 Final Tip: Explain why your query works, not just what it does. Speak your logic clearly. 💬 Tap ❤️ for more!

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heapq.heappush(heap, (node.val, node))
Repeatedly: • Pop smallest node • Add next node from same list 🔹 Complexity  Complexity - Value  Time - O(n log k)  Space - O(k)  Where:  n = total nodes  k = number of lists  🔹 Interview Tip  Very common hard interview problem. 🚀 38. How do you implement LRU / LFU cache? 🔹 LRU Cache  LRU: Least Recently Used  Remove least recently accessed item. 🔹 Efficient Design  Use:  1. HashMap 2. Doubly Linked List 🔹 Python LRU Example
from collections import OrderedDict

class LRUCache:
    def __init__(self, capacity):
        self.cache = OrderedDict()
        self.capacity = capacity

    def get(self, key):
        if key not in self.cache:
            return -1

        self.cache.move_to_end(key)

        return self.cache[key]

    def put(self, key, value):
        if key in self.cache:
            self.cache.move_to_end(key)

        self.cache[key] = value

        if len(self.cache) > self.capacity:
            self.cache.popitem(last=False)
🔹 Complexity  Operation - Complexity  Get - O(1)  Put - O(1)  🔹 Interview Tip  LRU cache is a FAANG-favorite system design question. 🚀 39. How do you check for balanced parentheses? Use a stack. 🔹 Idea  • Push opening brackets. • When closing bracket appears: Check top of stack 🔹 Python Solution
def is_valid(s):
    stack = []

    mapping = {
        ')': '(',
        '}': '{',
        ']': '['
    }

    for char in s:
        if char in mapping.values():
            stack.append(char)

        elif char in mapping:
            if not stack or stack.pop() != mapping[char]:
                return False

    return not stack

print(is_valid("({[]})"))
🔹 Output  True  🔹 Complexity  Complexity - Value  Time - O(n)  Space - O(n)  🔹 Uses  ✅ Compilers  ✅ Expression parsing  ✅ Syntax validation  🚀 40. How do you implement a circular queue? Circular queue reuses empty spaces efficiently. 🔹 Visualization  Front → [1,2,3,_,_]  After dequeue + enqueue:  [,2,3,4,🔹 Python Implementation
class CircularQueue:
    def __init__(self, size):
        self.queue = [None] * size
        self.front = 0
        self.rear = 0
        self.size = size
        self.count = 0

    def enqueue(self, value):
        if self.count == self.size:
            return "Full"

        self.queue[self.rear] = value
        self.rear = (self.rear + 1) % self.size
        self.count += 1

    def dequeue(self):
        if self.count == 0:
            return "Empty"

        value = self.queue[self.front]
        self.front = (self.front + 1) % self.size
        self.count -= 1

        return value
🔹 Complexity  Operation - Complexity  Enqueue - O(1)  Dequeue - O(1)  🔹 Real-World Uses  ✅ CPU scheduling  ✅ Streaming systems  ✅ Buffers  ✅ Embedded systems  🔥 Double Tap ❤️ For Part-5

Sure! Here's the text with the asterisks replaced by double asterisks: --- 🚀 Coding Interview Questions with Answers — Part 4 🗂️ Stacks, Queues & Heaps 🚀 31. How do you implement a stack with a max-stack (O(1) max query)? A Max Stack supports: • Push • Pop • Get Maximum Element in O(1) 🔹 Idea Maintain: 1. Main stack 2. Max stack Max stack stores current maximums. 🔹 Python Solution
class MaxStack:
    def __init__(self):
        self.stack = []
        self.max_stack = []

    def push(self, value):
        self.stack.append(value)

        if not self.max_stack or value >= self.max_stack[-1]:
            self.max_stack.append(value)

    def pop(self):
        if self.stack[-1] == self.max_stack[-1]:
            self.max_stack.pop()

        return self.stack.pop()

    def get_max(self):
        return self.max_stack[-1]
🔹 Complexity Operation - Complexity Push - O(1)  Pop - O(1)  Get Max - O(1)  🔹 Interview Tip Very common design-based stack question. 🚀 32. How do you implement a queue using two stacks? Queues are FIFO. Stacks are LIFO.  We can combine two stacks. 🔹 Idea Stack1 → enqueue  Stack2 → dequeue 🔹 Python Solution
class Queue:
    def __init__(self):
        self.s1 = []
        self.s2 = []

    def enqueue(self, value):
        self.s1.append(value)

    def dequeue(self):
        if not self.s2:
            while self.s1:
                self.s2.append(self.s1.pop())

        return self.s2.pop()
🔹 Complexity Operation - Complexity Enqueue - O(1)  Dequeue - Amortized O(1)  🔹 Interview Tip Interviewers love this because it tests understanding of stack behavior. 🚀 33. How do you design a stack that supports getMin() in O(1)? Very similar to Max Stack. 🔹 Idea Maintain: • Main stack • Min stack 🔹 Python Solution
class MinStack:
    def __init__(self):
        self.stack = []
        self.min_stack = []

    def push(self, value):
        self.stack.append(value)

        if not self.min_stack or value <= self.min_stack[-1]:
            self.min_stack.append(value)

    def pop(self):
        if self.stack[-1] == self.min_stack[-1]:
            self.min_stack.pop()

        return self.stack.pop()

    def get_min(self):
        return self.min_stack[-1]
🔹 Complexity Operation - Complexity Push - O(1)  Pop - O(1)  Get Min - O(1)  🔹 Interview Tip This is one of the highest-frequency interview problems. 🚀 34. What is a monotonic stack and when is it useful? A monotonic stack maintains elements in: • Increasing order OR • Decreasing order 🔹 Uses ✅ Next Greater Element  ✅ Largest Rectangle in Histogram  ✅ Stock Span Problem  ✅ Daily Temperatures  🔹 Example
arr = [2, 1, 3]

stack = []

for num in arr:
    while stack and stack[-1] > num:
        stack.pop()

    stack.append(num)
🔹 Complexity Most monotonic stack problems:  O(n)  because every element is pushed and popped once. 🔹 Interview Tip Extremely important pattern for medium/hard problems. 🚀 35. How do you implement a priority queue / heap? A heap is a complete binary tree. Types: • Min Heap • Max Heap 🔹 Python Min Heap
import heapq

heap = []

heapq.heappush(heap, 10)
heapq.heappush(heap, 5)
heapq.heappush(heap, 20)

print(heapq.heappop(heap))
🔹 Output 5 🔹 Complexity Operation - Complexity Insert - O(log n)  Delete - O(log n)  Peek - O(1)  🔹 Uses ✅ Task scheduling  ✅ Dijkstra’s algorithm  ✅ Top K problems  ✅ Priority processing  🚀 36. How do you find the top K frequent elements? 🔹 Approach 1. Count frequency using hashmap 2. Use heap 🔹 Python Solution
from collections import Counter
import heapq

def top_k(nums, k):
    freq = Counter(nums)

    return heapq.nlargest(k, freq.keys(), key=freq.get)

print(top_k([1, 1, 1, 2, 2, 3], 2))
🔹 Output [1, 2] 🔹 Complexity Complexity - Value Time - O(n log k)  Space - O(n)  🔹 Interview Tip Heap + hashmap combination is frequently tested. 🚀 37. How do you merge K sorted lists? 🔹 Efficient Approach Use a Min Heap. Heap stores:  smallest current node 🔹 Python Idea
import heapq

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head = Node(1) second = Node(2) third = Node(3) head.next = second second.next = third third.next = head 🔹 Uses ✅ Round-robin scheduling ✅ Multiplayer games ✅ Music playlists ✅ CPU scheduling 🚀 29. How do you split a list into equal parts? 🔹 Approach 1. Count total nodes 2. Divide length 3. Break links carefully 🔹 Example 1 → 2 → 3 → 4 → 5 → 6 Split into 2 parts: 1 → 2 → 3 4 → 5 → 6 🔹 Python Idea length = count_nodes(head) part_size = length // k extra = length % k Distribute remaining nodes one by one. 🔹 Complexity Time → O(n) Space → O(1) 🔹 Interview Tip Frequently appears in partitioning problems. 🚀 30. How do you implement a doubly linked list? A doubly linked list stores: prev pointer + next pointer 🔹 Visualization NULL ← 1 ⇄ 2 ⇄ 3 → NULL 🔹 Python Implementation class Node:   def init(self, data):     self.data = data     self.prev = None     self.next = None 🔹 Advantages ✅ Bidirectional traversal ✅ Easier deletion ✅ Efficient backtracking 🔹 Disadvantages ❌ More memory ❌ Extra pointer management 🔹 Real-World Uses ✅ Browser history ✅ Undo/redo ✅ Navigation systems ✅ Music players 🔹 Complexity Insert/Delete → O(1) Search → O(n) 🔥 Double Tap ❤️ For Part-4