Coding Interview Resources
This channel contains the free resources and solution of coding problems which are usually asked in the interviews. Managed by: @love_data
Ko'proq ko'rsatish📈 Telegram kanali Coding Interview Resources analitikasi
Coding Interview Resources (@crackingthecodinginterview) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 52 248 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 2 474-o'rinni va Hindiston mintaqasida 6 815-o'rinni egallagan.
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- Tematik yo‘nalishlar: Kontent array, stack, algorithm, programming, sort kabi asosiy mavzularga jamlangan.
📝 Tavsif va kontent siyosati
Muallif resursni shaxsiy fikrni ifoda etish maydoni sifatida ta’riflaydi:
“This channel contains the free resources and solution of coding problems which are usually asked in the interviews.
Managed by: @love_data”
Yuqori yangilanish chastotasi (oxirgi ma’lumot 27 Avgust, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.
NULLs, constraints
🧠 Interview Tip: Be able to explain Primary vs Foreign Key.
2️⃣ Basic Queries
🔹 SELECT, FROM, WHERE, ORDER BY, LIMIT
🧠 Practice: Filter and sort data by multiple columns.
3️⃣ Joins – Very Frequently Asked!
🔹 INNER, LEFT, RIGHT, FULL OUTER JOIN
🧠 Interview Tip: Explain the difference with examples.
🧪 Practice: Write queries using joins across 2–3 tables.
4️⃣ Aggregations & GROUP BY
🔹 COUNT, SUM, AVG, MIN, MAX, HAVING
🧠 Common Question: Total sales per category where total > X.
5️⃣ Window Functions
🔹 ROW_NUMBER(), RANK(), DENSE_RANK(), LAG(), LEAD()
🧠 Interview Favorite: Top N per group, previous row comparison.
6️⃣ Subqueries & CTEs
🔹 Write queries inside WHERE, FROM, and using WITH
🧠 Use Case: Filtering on aggregated data, simplifying logic.
7️⃣ CASE Statements
🔹 Add logic directly in SELECT
🧠 Example: Categorize users based on spend or activity.
8️⃣ Data Cleaning & Transformation
🔹 Handle NULLs, format dates, string manipulation (TRIM, SUBSTRING)
🧠 Real-world Task: Clean user input data.
9️⃣ Query Optimization Basics
🔹 Understand indexing, query plan, performance tips
🧠 Interview Tip: Difference between WHERE and HAVING.
🔟 Real-World Scenarios
🧠 Must Practice:
• Sales funnel
• Retention cohort
• Churn rate
• Revenue by channel
• Daily active users
🧪 Practice Platforms
• LeetCode (Easy–Hard SQL)
• StrataScratch (Real business cases)
• Mode Analytics (SQL + Visualization)
• HackerRank SQL (MCQs + Coding)
💼 Final Tip:
Explain why your query works, not just what it does. Speak your logic clearly.
💬 Tap ❤️ for more!heapq.heappush(heap, (node.val, node))
Repeatedly:
• Pop smallest node
• Add next node from same list
🔹 Complexity
Complexity - Value
Time - O(n log k)
Space - O(k)
Where:
n = total nodes
k = number of lists
🔹 Interview Tip
Very common hard interview problem.
🚀 38. How do you implement LRU / LFU cache?
🔹 LRU Cache
LRU: Least Recently Used
Remove least recently accessed item.
🔹 Efficient Design
Use:
1. HashMap
2. Doubly Linked List
🔹 Python LRU Example
from collections import OrderedDict
class LRUCache:
def __init__(self, capacity):
self.cache = OrderedDict()
self.capacity = capacity
def get(self, key):
if key not in self.cache:
return -1
self.cache.move_to_end(key)
return self.cache[key]
def put(self, key, value):
if key in self.cache:
self.cache.move_to_end(key)
self.cache[key] = value
if len(self.cache) > self.capacity:
self.cache.popitem(last=False)
🔹 Complexity
Operation - Complexity
Get - O(1)
Put - O(1)
🔹 Interview Tip
LRU cache is a FAANG-favorite system design question.
🚀 39. How do you check for balanced parentheses?
Use a stack.
🔹 Idea
• Push opening brackets.
• When closing bracket appears: Check top of stack
🔹 Python Solution
def is_valid(s):
stack = []
mapping = {
')': '(',
'}': '{',
']': '['
}
for char in s:
if char in mapping.values():
stack.append(char)
elif char in mapping:
if not stack or stack.pop() != mapping[char]:
return False
return not stack
print(is_valid("({[]})"))
🔹 Output
True
🔹 Complexity
Complexity - Value
Time - O(n)
Space - O(n)
🔹 Uses
✅ Compilers
✅ Expression parsing
✅ Syntax validation
🚀 40. How do you implement a circular queue?
Circular queue reuses empty spaces efficiently.
🔹 Visualization
Front → [1,2,3,_,_]
After dequeue + enqueue:
[,2,3,4,]
🔹 Python Implementation
class CircularQueue:
def __init__(self, size):
self.queue = [None] * size
self.front = 0
self.rear = 0
self.size = size
self.count = 0
def enqueue(self, value):
if self.count == self.size:
return "Full"
self.queue[self.rear] = value
self.rear = (self.rear + 1) % self.size
self.count += 1
def dequeue(self):
if self.count == 0:
return "Empty"
value = self.queue[self.front]
self.front = (self.front + 1) % self.size
self.count -= 1
return value
🔹 Complexity
Operation - Complexity
Enqueue - O(1)
Dequeue - O(1)
🔹 Real-World Uses
✅ CPU scheduling
✅ Streaming systems
✅ Buffers
✅ Embedded systems
🔥 Double Tap ❤️ For Part-5class MaxStack:
def __init__(self):
self.stack = []
self.max_stack = []
def push(self, value):
self.stack.append(value)
if not self.max_stack or value >= self.max_stack[-1]:
self.max_stack.append(value)
def pop(self):
if self.stack[-1] == self.max_stack[-1]:
self.max_stack.pop()
return self.stack.pop()
def get_max(self):
return self.max_stack[-1]
🔹 Complexity
Operation - Complexity
Push - O(1)
Pop - O(1)
Get Max - O(1)
🔹 Interview Tip
Very common design-based stack question.
🚀 32. How do you implement a queue using two stacks?
Queues are FIFO. Stacks are LIFO.
We can combine two stacks.
🔹 Idea
Stack1 → enqueue
Stack2 → dequeue
🔹 Python Solution
class Queue:
def __init__(self):
self.s1 = []
self.s2 = []
def enqueue(self, value):
self.s1.append(value)
def dequeue(self):
if not self.s2:
while self.s1:
self.s2.append(self.s1.pop())
return self.s2.pop()
🔹 Complexity
Operation - Complexity
Enqueue - O(1)
Dequeue - Amortized O(1)
🔹 Interview Tip
Interviewers love this because it tests understanding of stack behavior.
🚀 33. How do you design a stack that supports getMin() in O(1)?
Very similar to Max Stack.
🔹 Idea
Maintain:
• Main stack
• Min stack
🔹 Python Solution
class MinStack:
def __init__(self):
self.stack = []
self.min_stack = []
def push(self, value):
self.stack.append(value)
if not self.min_stack or value <= self.min_stack[-1]:
self.min_stack.append(value)
def pop(self):
if self.stack[-1] == self.min_stack[-1]:
self.min_stack.pop()
return self.stack.pop()
def get_min(self):
return self.min_stack[-1]
🔹 Complexity
Operation - Complexity
Push - O(1)
Pop - O(1)
Get Min - O(1)
🔹 Interview Tip
This is one of the highest-frequency interview problems.
🚀 34. What is a monotonic stack and when is it useful?
A monotonic stack maintains elements in:
• Increasing order OR
• Decreasing order
🔹 Uses
✅ Next Greater Element
✅ Largest Rectangle in Histogram
✅ Stock Span Problem
✅ Daily Temperatures
🔹 Example
arr = [2, 1, 3]
stack = []
for num in arr:
while stack and stack[-1] > num:
stack.pop()
stack.append(num)
🔹 Complexity
Most monotonic stack problems:
O(n)
because every element is pushed and popped once.
🔹 Interview Tip
Extremely important pattern for medium/hard problems.
🚀 35. How do you implement a priority queue / heap?
A heap is a complete binary tree.
Types:
• Min Heap
• Max Heap
🔹 Python Min Heap
import heapq
heap = []
heapq.heappush(heap, 10)
heapq.heappush(heap, 5)
heapq.heappush(heap, 20)
print(heapq.heappop(heap))
🔹 Output
5
🔹 Complexity
Operation - Complexity
Insert - O(log n)
Delete - O(log n)
Peek - O(1)
🔹 Uses
✅ Task scheduling
✅ Dijkstra’s algorithm
✅ Top K problems
✅ Priority processing
🚀 36. How do you find the top K frequent elements?
🔹 Approach
1. Count frequency using hashmap
2. Use heap
🔹 Python Solution
from collections import Counter
import heapq
def top_k(nums, k):
freq = Counter(nums)
return heapq.nlargest(k, freq.keys(), key=freq.get)
print(top_k([1, 1, 1, 2, 2, 3], 2))
🔹 Output
[1, 2]
🔹 Complexity
Complexity - Value
Time - O(n log k)
Space - O(n)
🔹 Interview Tip
Heap + hashmap combination is frequently tested.
🚀 37. How do you merge K sorted lists?
🔹 Efficient Approach
Use a Min Heap.
Heap stores:
smallest current node
🔹 Python Idea
import heapq