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allcoding1_official

allcoding1_official

前往频道在 Telegram

📈 Telegram 频道 allcoding1_official 的分析概览

频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 85 000 名订阅者,在 技术与应用 类别中位列第 1 493,并在 印度 地区排名第 3 481

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 85 000 名订阅者。

根据 04 七月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 507,过去 24 小时变化为 -65,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 3.16%。内容发布后 24 小时内通常能获得 0.93% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 2 684 次浏览,首日通常累积 792 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 1
  • 主题关注点: 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。

📝 描述与内容策略

尚未提供频道描述。

凭借高频更新(最新数据采集于 05 七月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。

85 000
订阅者
-6524 小时
-3587
-1 50730
帖子存档
Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 7) 3214 8-protection of life and personal liberty for 9-punish appropriately 10-marine, agilit 11)whet her appetite, up the creek 12)4312 13) R and Q 14) than it is , enormous range of 15) Pragmatist 16.Reflected upon telegram:- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 7) 3214 8-protection of life and personal liberty for 9-punish appropriately 10-marine, agilit 11)whet her appetite, up the creek 12)4312 13) R and Q 14) than it is , enormous range of 15)quixotic telegram:- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 7) 3214 8-protection of life and personal liberty for 9-punish appropriately 10-marine, agilit 11)whet her appetite, up the creek 12)4312 13) R and Q 14) than it is , enormous range of telegram:- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 7) 3214 8-protection of life and personal liberty for 9-punish appropriately 10-marine, agilit 11)whet her appetite, up the creek 12)4312 13) R and Q telegram:- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 7) 3214 8-protection of life and personal liberty for 9-punish appropriately 10-marine, agilit 11)whet her appetite, up the creek 12)4312 telegram:- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 7) 3214 8-protection of life and personal liberty for 9-punish appropriately 10-marine, agilit 11)whet her appetite, up the creek telegram:- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 7) 3214 8-protection of life and personal liberty for 9-punish appropriately 10-marine, agilit telegram:- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1243 7) 2134 Telegram :- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 telegram:- @allcoding1_official

N=int(input()) K=int(input()) price=list(map(int,input().split())) vol=list(map(int,input().split())) maxvol=0 volu=0 maxvol=max(vol) for i in range(0,N):     if (maxvol==vol[i] and price[i]<=K):         K=K-price[i]         volu=maxvol for i in range(0,N):     for j in range(i+1,N+1):         if (price[i]<=K and price[i]==price[j]):             if (vol[i]>vol[j]):                 volu=volu+vol[i]                 K=K-price[i]             else:                 volu=volu+vol[j]                 K=K-price[j]         elif (price[i]<=K and price[i]!=price[j]):             K=K-price[i]             volu=volu+vol[i] print(volu) Vijay code try this Python Telegram:- @allcoding1_official

#include<stdio.h> int main() {     int n;     scanf("%d",&n);     int arr[n];     for(int i=0;i<n;i++)     {         scanf("%d",&arr[i]);     }     int count=0;     int num=arr[0];     for(int i=1;i<n;i++)     {        if(num!=arr[i])             count++;     }     printf("%d",count); } C Language TCS 1st Qsn Telegram:- @allcoding1_official

Java coding Industrial Passed
+1
Java coding Industrial Passed

Reasoning 1. No 2. Puma 3. 18010 4. 2 5. Data in both 1 and 2 are necessary 6. Candidates is not to be selected 7. Harsh 8. UBPJDJQU 9 Both A and R is true BUT R is not correct explain of A 10. Both A and R are true and R is correct explanation of A

1) no 2) puma 3)171820911 4)14 5. Data in both 1 and 2 are necessary 6. Candidates is not to be selected 7. Harsh 8. UBPJDJQU Telegram:- @allcoding1_official

5. Data in both 1 and 2 are necessary 6. Candidates is not to be selected 7. Harsh 8. UBPJDJQU

D Telegram:-
D Telegram:-

1) no 2) puma 3)171820911 4)14 5)22 Telegram:- @allcoding1_official

1) no 2) puma 3)171820911 5)22 Telegram:- @allcoding1_official