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allcoding1_official

allcoding1_official

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📈 Telegram kanali allcoding1_official analitikasi

allcoding1_official (@allcoding1_official) Ingliz til segmentidagi kanali faol ishtirokchi. Hozirda hamjamiyat 85 000 obunachidan iborat bo'lib, Texnologiyalar & Aralashmalar toifasida 1 493-o'rinni va Hindiston mintaqasida 3 481-o'rinni egallagan.

📊 Auditoriya ko‘rsatkichlari va dinamika

невідомо sanasidan buyon loyiha tez o‘sib, 85 000 obunachiga ega bo‘ldi.

04 Iyul, 2026 dagi oxirgi ma’lumotlarga ko‘ra kanal barqaror faollikka ega. Oxirgi 30 kunda obunachilar soni -1 507 ga, so‘nggi 24 soatda esa -65 ga o‘zgardi va umumiy qamrov yuqori darajada qolmoqda.

  • Tasdiqlash holati: Tasdiqlanmagan
  • Jalb etish (ER): Auditoriya o‘rtacha 3.16% darajada jalb etiladi. Nashrdan keyingi dastlabki 24 soatda kontent odatda umumiy obunachilar sonining 0.93% ini tashkil etuvchi reaksiyalarni to‘playdi.
  • Post qamrovi: Har bir post o‘rtacha 2 684 marta ko‘riladi; birinchi sutkada odatda 792 ta ko‘rish yig‘iladi.
  • Reaksiyalar va o‘zaro ta’sir: Auditoriya faol: har bir postga o‘rtacha 1 ta reaksiya keladi.
  • Tematik yo‘nalishlar: Kontent dsa, stack, namaste, javascript, dev kabi asosiy mavzularga jamlangan.

📝 Tavsif va kontent siyosati

Kanal uchun tavsif kiritilmagan.

Yuqori yangilanish chastotasi (oxirgi ma’lumot 05 Iyul, 2026 da olingan) sababli kanal doimo dolzarb va katta qamrovli bo‘lib qoladi. Analitika auditoriya kontent bilan faol hamkorlik qilishini, uni Texnologiyalar & Aralashmalar toifasidagi muhim ta’sir nuqtasiga aylantirishini ko‘rsatadi.

85 000
Obunachilar
-6524 soatlar
-3587 kunlar
-1 50730 kunlar
Postlar arxiv
Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 7) 3214 8-protection of life and personal liberty for 9-punish appropriately 10-marine, agilit 11)whet her appetite, up the creek 12)4312 13) R and Q 14) than it is , enormous range of 15) Pragmatist 16.Reflected upon telegram:- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 7) 3214 8-protection of life and personal liberty for 9-punish appropriately 10-marine, agilit 11)whet her appetite, up the creek 12)4312 13) R and Q 14) than it is , enormous range of 15)quixotic telegram:- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 7) 3214 8-protection of life and personal liberty for 9-punish appropriately 10-marine, agilit 11)whet her appetite, up the creek 12)4312 13) R and Q 14) than it is , enormous range of telegram:- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 7) 3214 8-protection of life and personal liberty for 9-punish appropriately 10-marine, agilit 11)whet her appetite, up the creek 12)4312 13) R and Q telegram:- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 7) 3214 8-protection of life and personal liberty for 9-punish appropriately 10-marine, agilit 11)whet her appetite, up the creek 12)4312 telegram:- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 7) 3214 8-protection of life and personal liberty for 9-punish appropriately 10-marine, agilit 11)whet her appetite, up the creek telegram:- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 7) 3214 8-protection of life and personal liberty for 9-punish appropriately 10-marine, agilit telegram:- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1243 7) 2134 Telegram :- @allcoding1_official

Verbals 1) dear richa 2) had fled 3) to take upon 4-cdab 5-a rough sail 6-1343 telegram:- @allcoding1_official

N=int(input()) K=int(input()) price=list(map(int,input().split())) vol=list(map(int,input().split())) maxvol=0 volu=0 maxvol=max(vol) for i in range(0,N):     if (maxvol==vol[i] and price[i]<=K):         K=K-price[i]         volu=maxvol for i in range(0,N):     for j in range(i+1,N+1):         if (price[i]<=K and price[i]==price[j]):             if (vol[i]>vol[j]):                 volu=volu+vol[i]                 K=K-price[i]             else:                 volu=volu+vol[j]                 K=K-price[j]         elif (price[i]<=K and price[i]!=price[j]):             K=K-price[i]             volu=volu+vol[i] print(volu) Vijay code try this Python Telegram:- @allcoding1_official

#include<stdio.h> int main() {     int n;     scanf("%d",&n);     int arr[n];     for(int i=0;i<n;i++)     {         scanf("%d",&arr[i]);     }     int count=0;     int num=arr[0];     for(int i=1;i<n;i++)     {        if(num!=arr[i])             count++;     }     printf("%d",count); } C Language TCS 1st Qsn Telegram:- @allcoding1_official

Java coding Industrial Passed
+1
Java coding Industrial Passed

Reasoning 1. No 2. Puma 3. 18010 4. 2 5. Data in both 1 and 2 are necessary 6. Candidates is not to be selected 7. Harsh 8. UBPJDJQU 9 Both A and R is true BUT R is not correct explain of A 10. Both A and R are true and R is correct explanation of A

1) no 2) puma 3)171820911 4)14 5. Data in both 1 and 2 are necessary 6. Candidates is not to be selected 7. Harsh 8. UBPJDJQU Telegram:- @allcoding1_official

5. Data in both 1 and 2 are necessary 6. Candidates is not to be selected 7. Harsh 8. UBPJDJQU

D Telegram:-
D Telegram:-

1) no 2) puma 3)171820911 4)14 5)22 Telegram:- @allcoding1_official

1) no 2) puma 3)171820911 5)22 Telegram:- @allcoding1_official