allcoding1_official
前往频道在 Telegram
📈 Telegram 频道 allcoding1_official 的分析概览
频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 78 410 名订阅者，在 技术与应用 类别中位列第 1 627，并在 印度 地区排名第 3 771 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 78 410 名订阅者。
根据 06 十一月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -1 536，过去 24 小时变化为 -28，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 2.02%。内容发布后 24 小时内通常能获得 0.63% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 1 587 次浏览，首日通常累积 495 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 3。
- 主题关注点： 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新（最新数据采集于 07 十一月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 技术与应用 类别中的关键影响点。
78 410
订阅者
-2824 小时
-3417 天
-1 53630 天
帖子存档
78 410
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1
@allcoding1
discussion group:- @Infosys_exam_Ans
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
78 410
+1INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1
@allcoding1
discussion group:- @Infosys_exam_Ans
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
78 410
// Infosys
// N flowers on a Recatangular pana
int ans = 100000000;
void solve(vector a, int n, int k, int index, int sum,
int maxsum)
{
if (k == 1)
{
maxsum = max(maxsum, sum);
sum = 0;
for (int i = index; i < n; i++)
{
sum += a[i];
}
maxsum = max(maxsum, sum);
ans = min(ans, maxsum);
return;
}
sum = 0;
for (int i = index; i < n; i++)
{
sum += a[i];
maxsum = max(maxsum, sum);
solve(a, n, k - 1, i + 1, sum, maxsum);
}
}
int GetMaxBeauty(int N, int K, vector A)
{
solve(A, N, K, 0, 0, 0);
return ans;
}
C++
78 410
def getLargestString(s, k):
frequency_array = [0] * 26
for i in range(len(s)):
frequency_array[ord(s[i]) -
ord('a')] += 1
ans = ""
i = 25
while i >= 0:
if (frequency_array[i] > k):
temp = k
st = chr( i + ord('a'))
while (temp > 0):
ans += st
temp -= 1
frequency_array[i] -= k
j = i - 1
while (frequency_array[j] <= 0 and
j >= 0):
j -= 1
if (frequency_array[j] > 0 and
j >= 0):
str1 = chr(j + ord( 'a'))
ans += str1
frequency_array[j] -= 1
else:
break
elif (frequency_array[i] > 0):
temp = frequency_array[i]
frequency_array[i] -= temp
st = chr(i + ord('a'))
while (temp > 0):
ans += st
temp -= 1
else:
i -= 1
return ans
if name == "main":
S = input()
k = 3
print (getLargestString(S, k))
Python
Bob code
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1_official
@allcoding1_official
discussion group:- @Infosys_examAns
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
78 410
#include<stdio.h>
Int main(){
Int n,x;
Scanf(”%d",&n);
int n=x;
For (int i=0;i<=n-1;i++){
scanf(''%d'',&a[i]);
x=2*x-a[i];
}
Printf("%d",x);
}
C language
78 410
Python
Once check it out put
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1_official
@allcoding1_official
discussion group:- @Infosys_examAns
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
78 410
+1Python
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1_official
@allcoding1_official
discussion group:- @Infosys_examAns
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
78 410
+1Java
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1_official
@allcoding1_official
discussion group:- @Infosys_examAns
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
78 410
Java
INFOSYS EXAM ANS 10AM
ALL Slots are available
Telegram:- @allcoding1_official
@allcoding1_official
discussion group:- @Infosys_examAns
Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE=
Share with your friends
78 410
def next_stepping_number(N):
N = str(N)
for i in range(len(N) - 1):
if abs(int(N[i]) - int(N[i+1])) != 1:
return int(N[:i+1] + str(int(N[i]) + 1 if int(N[i]) < int(N[i+1]) else int(N[i]) - 1) + '9'*(len(N)-i-1))
return int(N) + 1
print(next_stepping_number(4)) # should return 5
78 410
def shortest_subarray(colors, C):
n = len(colors)
color_count = [0] * (C+1)
left, right = 0, 0
min_length = float('inf')
count = 0
while right < n:
color_count[colors[right]] += 1
if color_count[colors[right]] == 1:
count += 1
while count == C:
min_length = min(min_length, right - left + 1)
color_count[colors[left]] -= 1
if color_count[colors[left]] == 0:
count -= 1
left += 1
right += 1
if min_length == float('inf'):
return -1
else:
return min_length
Python3
78 410
def shortest_subarray(colors, C):
n = len(colors)
color_count = [0] * (C+1)
left, right = 0, 0
min_length = float('inf')
count = 0
while right < n:
color_count[colors[right]] += 1
if color_count[colors[right]] == 1:
count += 1
while count == C:
min_length = min(min_length, right - left + 1)
color_count[colors[left]] -= 1
if color_count[colors[left]] == 0:
count -= 1
left += 1
right += 1
if min_length == float('inf'):
return -1
else:
return min_length
Python3
