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// Infosys // N flowers on a Recatangular pana int ans = 100000000; void solve(vector a, int n, int k, int index, int sum,            int maxsum) {     if (k == 1)     {         maxsum = max(maxsum, sum);         sum = 0;         for (int i = index; i < n; i++)         {             sum += a[i];         }         maxsum = max(maxsum, sum);         ans = min(ans, maxsum);         return;     }     sum = 0;     for (int i = index; i < n; i++)     {         sum += a[i];         maxsum = max(maxsum, sum);         solve(a, n, k - 1, i + 1, sum, maxsum);     } } int GetMaxBeauty(int N, int K, vector A) {     solve(A, N, K, 0, 0, 0);     return ans; } C++

def getLargestString(s, k):     frequency_array = [0] * 26     for i in range(len(s)):         frequency_array[ord(s[i]) -                         ord('a')] += 1     ans = ""     i = 25     while i >= 0:         if (frequency_array[i] > k):             temp = k             st = chr( i + ord('a'))                          while (temp > 0):                 ans += st                 temp -= 1                        frequency_array[i] -= k             j = i - 1                          while (frequency_array[j] <= 0 and                    j >= 0):                 j -= 1             if (frequency_array[j] > 0 and                 j >= 0):                 str1 = chr(j + ord( 'a'))                 ans += str1                 frequency_array[j] -= 1                          else:                 break         elif (frequency_array[i] > 0):             temp = frequency_array[i]             frequency_array[i] -= temp             st = chr(i + ord('a'))             while (temp > 0):                 ans += st                 temp -= 1         else:             i -= 1                  return ans           if name == "main":        S = input()     k = 3     print (getLargestString(S, k)) Python Bob code INFOSYS EXAM ANS 10AM ALL Slots are available Telegram:- @allcoding1_official @allcoding1_official discussion group:- @Infosys_examAns Coding Ans :- https://instagram.com/allcoding1_official?igshid=OGQ2MjdiOTE= Share with your friends

#include<stdio.h> Int main(){ Int n,x; Scanf(”%d",&n); int n=x; For (int i=0;i<=n-1;i++){ scanf(''%d'',&a[i]); x=2*x-a[i]; } Printf("%d",x); } C language

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Java

def next_stepping_number(N): N = str(N) for i in range(len(N) - 1): if abs(int(N[i]) - int(N[i+1])) != 1: return int(N[:i+1] + str(int(N[i]) + 1 if int(N[i]) < int(N[i+1]) else int(N[i]) - 1) + '9'*(len(N)-i-1)) return int(N) + 1 print(next_stepping_number(4)) # should return 5

def shortest_subarray(colors, C):     n = len(colors)     color_count = [0] * (C+1)     left, right = 0, 0     min_length = float('inf')     count = 0     while right < n:         color_count[colors[right]] += 1         if color_count[colors[right]] == 1:             count += 1         while count == C:             min_length = min(min_length, right - left + 1)             color_count[colors[left]] -= 1             if color_count[colors[left]] == 0:                 count -= 1             left += 1         right += 1     if min_length == float('inf'):         return -1     else:         return min_length Python3

def shortest_subarray(colors, C):     n = len(colors)     color_count = [0] * (C+1)     left, right = 0, 0     min_length = float('inf')     count = 0     while right < n:         color_count[colors[right]] += 1         if color_count[colors[right]] == 1:             count += 1         while count == C:             min_length = min(min_length, right - left + 1)             color_count[colors[left]] -= 1             if color_count[colors[left]] == 0:                 count -= 1             left += 1         right += 1     if min_length == float('inf'):         return -1     else:         return min_length Python3