allcoding1_official
前往频道在 Telegram
📈 Telegram 频道 allcoding1_official 的分析概览
频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 79 009 名订阅者,在 技术与应用 类别中位列第 1 613,并在 印度 地区排名第 3 828 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 79 009 名订阅者。
根据 25 十月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 654,过去 24 小时变化为 -52,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 1.79%。内容发布后 24 小时内通常能获得 0.62% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 414 次浏览,首日通常累积 489 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 0。
- 主题关注点: 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。
📝 描述与内容策略
尚未提供频道描述。
凭借高频更新(最新数据采集于 26 十月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。
79 009
订阅者
-5224 小时
-3677 天
-1 65430 天
帖子存档
79 029
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⚡️ Basics
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
⚡️ Sql Injection
⚡️ System Hacking
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⚡️ Wireless Network
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⚡️ Sniffing
⚡️ BufferOverflow
⚡️ Cryptography
⚡️ Denial Of Service
All courses (100 rupees)
Contact:- @meterials_available
79 029
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⚡️ Basics
⚡️ Reconnaissance and Footprinting
⚡️ Network Scanning
⚡️ Enumeration
⚡️ Firewalls HIDs Honeypot
⚡️ Malware and Threats
⚡️ Mobile Platform
⚡️ Pentesting
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⚡️ System Hacking
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All courses (100 rupees)
Contact:- @meterials_available
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⚡️ Basics
⚡️ Reconnaissance and Footprinting
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def count_commas(n):
total_commas = 0
for number in range(1, n + 1):
number_with_commas = "{:,}".format(number)
total_commas += number_with_commas.count(',')
return total_commas
# Example usage:
N = 1010
print(count_commas(N)) # Output: 11
