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لا تقع ضحية للمخادعين! تيليمتريو يكتشف ويُميّز هذه القنوات 👉 إذا كنت تريد رؤية العلامة، اشترك

allcoding1_official

allcoding1_official

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تُعد قناة allcoding1_official (@allcoding1_official) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 79 039 مشتركاً، محتلاً المرتبة 1 607 في فئة التكنولوجيات والتطبيقات والمرتبة 3 824 في منطقة الهند.

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منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 79 039 مشتركاً.

بحسب آخر البيانات بتاريخ 24 أكتوبر, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -1 636، وفي آخر 24 ساعة بمقدار -24، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 1.75‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 0.67‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 1 383 مشاهدة. وخلال اليوم الأول يجمع عادةً 527 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 0.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل dsa, stack, namaste, javascript, dev.

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بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 25 أكتوبر, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التكنولوجيات والتطبيقات.

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0
0

finding commas
finding commas

62.31
62.31

photo content

4A
4A

def count_commas(n): total_commas = 0 for number in range(1, n + 1): number_with_commas = "{:,}".format(number) total_commas
def count_commas(n):     total_commas = 0         for number in range(1, n + 1):         number_with_commas = "{:,}".format(number)         total_commas += number_with_commas.count(',')         return total_commas # Example usage: N = 1010 print(count_commas(N))  # Output: 11

A
A

9
9

7.08
7.08