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allcoding1_official

allcoding1_official

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📈 Telegram 频道 allcoding1_official 的分析概览

频道 allcoding1_official (@allcoding1_official) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 85 628 名订阅者,在 技术与应用 类别中位列第 1 508,并在 印度 地区排名第 3 501

📊 受众指标与增长动态

невідомо 创建以来,项目保持高速增长,吸引了 85 628 名订阅者。

根据 21 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -1 434,过去 24 小时变化为 -33,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 3.09%。内容发布后 24 小时内通常能获得 0.73% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 2 645 次浏览,首日通常累积 625 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 1
  • 主题关注点: 内容集中在 dsa, stack, namaste, javascript, dev 等核心主题上。

📝 描述与内容策略

尚未提供频道描述。

凭借高频更新(最新数据采集于 22 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 技术与应用 类别中的关键影响点。

85 628
订阅者
-3324 小时
-3007
-1 43430
帖子存档
[Posted by Dushyant] [🖼 heights = [int(i) for i in input().split()] freq_dict = {} for h in heights: if h in freq_dict: freq
[Posted by Dushyant] [🖼 heights = [int(i) for i in input().split()] freq_dict = {} for h in heights: if h in freq_dict:   freq_dict[h] += 1 else:   freq_dict[h] = 1 for h in sorted(freq_dict): print(h, freq_dict[h])] heights = [int(i) for i in input().split()] freq_dict = {} for h in heights: if h in freq_dict:   freq_dict[h] += 1 else:   freq_dict[h] = 1 for h in sorted(freq_dict): print(h, freq_dict[h])

#include <iostream> #include <string> #include <vector> using namespace std; int numDecodings(string msg) {     int MOD = 1000000007;     int n = msg.size();         vector<long long> dp(n + 1, 0);     dp[0] = 1;         if (msg[0] == '0')         dp[1] = 0;     else if (msg[0] == '*')         dp[1] = 9;     else         dp[1] = 1;         for (int i = 2; i <= n; ++i) {         if (msg[i - 1] == '0') {                         if (msg[i - 2] == '1' || msg[i - 2] == '2')                 dp[i] += dp[i - 2];             else if (msg[i - 2] == '*')                 dp[i] += 2 * dp[i - 2];         } else if (msg[i - 1] >= '1' && msg[i - 1] <= '9') {                   dp[i] += dp[i - 1];                         if (msg[i - 2] == '1' || (msg[i - 2] == '2' && msg[i - 1] <= '6'))                 dp[i] += dp[i - 2];             else if (msg[i - 2] == '*') {                                 if (msg[i - 1] <= '6')                     dp[i] += 2 * dp[i - 2];                 else                     dp[i] += dp[i - 2];             }         } else if (msg[i - 1] == '*') {             dp[i] += 9 * dp[i - 1];                         if (msg[i - 2] == '1')                 dp[i] += 9 * dp[i - 2];             else if (msg[i - 2] == '2')                 dp[i] += 6 * dp[i - 2];             else if (msg[i - 2] == '*')                 dp[i] += 15 * dp[i - 2];         }                 dp[i] %= MOD;     }         return dp[n]; } Number of ways decode

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#include <iostream> #include <vector> #include <algorithm> using namespace std; int findLIS(vector<int>& s) {     vector<int> tails;     for (int x : s) {         auto it = lower_bound(tails.begin(), tails.end(), x);         if (it == tails.end()) {             tails.push_back(x);         } else {             *it = x;         }     }     return tails.size(); }   Swiggy LIS

#include <bits/stdc++.h> using namespace std; int jumps(int flagHeight, int bigJump) {     return flagHeight / bigJump+flagheight% bigJump; }.  Swiggy Jump to The Flag

long getMaxPrisonHole(int n, int m, vector x, vector y) {     vector xb(n+1, true);     vector yb(m+1, true);         for(int i : x) {         xb[i] = false;     }         for(int i : y) {         yb[i] = false;     }         long cx = 0, xm = LONG_MIN, cy = 0, ym = LONG_MIN;         for(int i = 0; i < xb.size(); i++) {         if(xb[i]) {             cx = 0;         } else {             cx++;             xm = max(cx, xm);         }     }         for(int i = 0; i < yb.size(); i++) {         if(yb[i]) {             cy = 0;         } else {             cy++;             ym = max(cy, ym);         }     }         return (xm+1) * (ym+1); }  Swiggy Prison Break

public static int selectStock(int saving, int[] currentValue, int[] futureValue) {         int n = currentValue.length;         int[][] dp = new int[n + 1][saving + 1];         for (int i = 1; i <= n; i++) {             for (int j = 0; j <= saving; j++) {                 dp[i][j] = dp[i - 1][j];                 if (j >= currentValue[i - 1]) {                     dp[i][j] = Math.max(dp[i][j], dp[i - 1][j - currentValue[i - 1]] + futureValue[i - 1] - currentValue[i - 1]);                 }             }         }         return dp[n][saving];     }.  Swiggy Selecting  Stocks

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Advanced SubArray Problem
Advanced SubArray Problem

Elections code
Elections code

int winning_party(int voters, int votes[]) { &nbsp;&nbsp;&nbsp; unordered_map vote_counts; &nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nb
int winning_party(int voters, int votes[]) {     unordered_map vote_counts;         for (int i = 0; i < voters; ++i) {         vote_counts[votes[i]]++;     }         for (auto it = vote_counts.begin(); it != vote_counts.end(); ++it) {         if (it->second > voters / 2) {             return it->first;         }     }         return -1; } Elections

def is_prime(n): if n <= 1: return False if n <= 3: return True if n % 2 == 0 or n % 3 == 0: return False i = 5 while i * i <= n: if n % i == 0 or n % (i + 2) == 0: return False i += 6 return True def next_prime(N): if N <= 1: return 2 prime = N + 1 while True: if is_prime(prime): return prime prime += 1 # Test the function N = 4 print(next_prime(N)) # Output: 5

encoded_value = "" for digit in str(input1): encoded_value += str(int(digit) ** 2) return int(encoded_value) Minimum array sum

encoded_value = "" for digit in str(input1): encoded_value += str(int(digit) ** 2) return int(encoded_value) Fallen Angel, [04/05/24, 4:12 pm] Minimum array sum

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